## Selina Concise Mathematics Class 9 ICSE Solutions Area and Perimeter of Plane Figures

ICSE SolutionsSelina ICSE Solutions

APlusTopper.com provides step by step solutions for Selina Concise Mathematics Class 9 ICSE Solutions Chapter 20 Area and Perimeter of Plane Figures. You can download the Selina Concise Mathematics ICSE Solutions for Class 9 with Free PDF download option. Selina Publishers Concise Mathematics for Class 9 ICSE Solutions all questions are solved and explained by expert mathematic teachers as per ICSE board guidelines.

Download Formulae Handbook For ICSE Class 9 and 10

**Selina ICSE Solutions for Class 9 Maths Chapter 20 Area and Perimeter of Plane Figures**

**Exercise 20(A)**

**Solution 1:**

**Solution 2:**

**Solution 3:**

**Solution 4:**

**Solution 5:**

Since the perimeter of the isosceles triangle is 36cm and base is 16cm.

**Solution 6:**

**Solution 7:**

**Solution 8:**

**Solution 9:**

**Solution 10:**

**Solution 11:**

**Solution 12:**

**Solution 13:**

**Solution 14:**

**Solution 15:**

**Exercise 20(B)**

**Solution 1:**

**Solution 2:**

**Solution 3:**

**Solution 4:**

**Solution 5:**

**Solution 6:**

**Solution 7:**

**Solution 8:**

**Solution 9:**

**Solution 10:**

**Solution 11:**

**Solution 12:**

**Solution 13:**

We need to find the cost of carpeting of 80 cm = 0.8 m wide carpet, if the rate of carpeting is Rs. 25. Per metre.

Then

**Solution 14:**

**Solution 15:**

**Solution 16:**

**Solution 17:**

**Solution 18:**

**Solution 19:**

**Solution 20:**

**Solution 21:**

**Solution 22:**

**Solution 23:**

**Solution 24:**

**Solution 25:**

**Solution 26:**

**Solution 27:**

In the given figure, we can observe that the non-parallel sides are equal and hence it is an isosceles trapezium.

**Solution 28:**

**Solution 29:**

**Solution 30:**

**Solution 31:**

**Solution 32:**

**Solution 33:**

**Solution 34:**

**Solution 35:**

**Solution 36:**

**Exercise 20(C)**

**Solution 1:**

**Solution 2:**

**Solution 3:**

**Solution 4:**

**Solution 5:**

**Solution 6:**

**Solution 7:**

**Solution 8:**

**Solution 9:**

**Solution 10:**

**Solution 11:**

**Solution 12:**

**Solution 13:**

**Solution 14:**

**Solution 15:**

**Solution 16:**

**Solution 17:**

**Solution 18:**

**Solution 19:**

**Solution 20:**

From the given data, we can calculate the area of the outer circle and then the area of inner circle and hence the width of the shaded portion.

**Solution 21:**

**Solution 22:**

**Solution 23:**

**Solution 24:**

**Solution 25:**

**Solution 26:**

**Solution 27:**

**Solution 28:**

**More Resources for Selina Concise Class 9 ICSE Solutions**

- Selina Publishers Mathematics for Class 9
- Selina Class 9 ICSE Physics Solutions
- Selina ICSE Class 9 ChemistryÂ Solutions
- Selina Concise Biology Class 9 Solutions