## Selina Concise Mathematics Class 10 ICSE Solutions Geometric Progression

**Selina Publishers Concise Mathematics Class 10 ICSE Solutions Chapter 11 Geometric Progression**

### Geometric Progression Exercise 11A – Selina Concise Mathematics Class 10 ICSE Solutions

Question 1.

Find, which of the following sequence form a G.P. :

(i) 8, 24, 72, 216, ……

(ii) , ……..

(iii) 9, 12, 16, 24, ……

Solution 1(i).

Solution 1(ii).

Solution 1(iii).

Question 2.

Find the 9th term of the series :

1, 4, 16, 64 ……..

Solution:

Question 3.

Find the seventh term of the G.P. :

1, , 3, …..

Solution:

Question 4.

Find the 8^{th} term of the sequence :

3, …….

Solution:

Question 5.

Find the 10^{th} term of the G.P. :

Solution:

Question 6.

Find the n^{th} term of the series :

Solution:

Question 7.

Find the next three terms of the sequence :

, 5, , ……

Solution:

Question 8.

Find the sixth term of the series :

2^{2}, 2^{3}, 2^{4}, ……….

Solution:

Question 9.

Find the seventh term of the G.P. :

[late]\sqrt{3}+1,1, \frac{\sqrt{3}-1}{2}[/latex], ……………..

Solution:

Question 10.

Find the G.P. whose first term is 64 and next term is 32.

Solution:

Question 11.

Find the next three terms of the series:

, ………….

Solution:

Question 12.

Find the next two terms of the series

2 – 6 + 18 – 54 …………

Solution:

### Geometric Progression Exercise 11B – Selina Concise Mathematics Class 10 ICSE Solutions

Question 1.

Which term of the G.P. :

Solution:

Question 2.

The fifth term of a G.P. is 81 and its second term is 24. Find the geometric progression.

Solution:

Question 3.

Fourth and seventh terms of a G.P. are respectively. Find the GP.

Solution:

Question 4.

If the first and the third terms of a G.P. are 2 and 8 respectively, find its second term.

Solution:

Question 5.

The product of 3rd and 8th terms of a G.P. is 243. If its 4^{th} term is 3, find its 7^{th} term.

Solution:

Question 6.

Find the geometric progression with 4^{th} term = 54 and 7^{th} term = 1458.

Solution:

Question 7.

Second term of a geometric progression is 6 and its fifth term is 9 times of its third term. Find the geometric progression. Consider that each term of the G.P. is positive.

Solution:

Question 8.

The fourth term, the seventh term and the last term of a geometric progression are 10, 80 and 2560 respectively. Find its first term, common ratio and number of terms.

Solution:

Question 9.

If the 4th and 9th terms of a G.P. are 54 and 13122 respectively, find the GP. Also, find its general term.

Solution:

Question 10.

The fifth, eight and eleventh terms of a geometric progression are p, q and r respectively. Show that : q^{2} = pr.

Solution:

### Geometric Progression Exercise 11C – Selina Concise Mathematics Class 10 ICSE Solutions

Question 1.

Find the seventh term from the end of the series : , 2, , ………. 32.

Solution:

Question 2.

Find the third term from the end of the GP.

, ………….. 162

Solution:

Question 3.

For the , ………… 81;

find the product of fourth term from the beginning and the fourth term from the end.

Solution:

Question 4.

If for a G.P., p^{th}, q^{th} and r^{th} terms are a, b and c respectively ; prove that :

(q – r) log a + (r – p) log b + (p – q) log c = 0

Solution:

Question 5.

If a, b and c in G.P., prove that : log a^{n}, log b^{n} and log c^{n} are in A.P.

Solution:

Question 6.

If each term of a G.P. is raised to the power x, show that the resulting sequence is also a G.P.

Solution:

Question 7.

If a, b and c are in A.P. a, x, b are in G.P. whereas b, y and c are also in G.P. Show that : x^{2}, b^{2}, y^{2} are in A.P.

Solution:

Question 8.

If a, b, c are in G.P. and a, x, b, y, c are in A.P., prove that :

Solution 8(i).

Solution 8(ii).

Question 9.

If a, b and c are in A.P. and also in G.P., show that: a = b = c.

Solution:

Question 10.

The first term of a G.P. is a and its n^{th} term is b, where n is an even number.If the product of first n numbers of this G.P. is P ; prove that : p^{2} – (ab)^{n}.

Solution:

Question 11.

If a, b, c and d are consecutive terms of a G.P. ; prove that :

(a^{2} + b^{2}), (b^{2} + c^{2}) and (c^{2} + d^{2}) are in GP.

Solution:

Question 12.

If a, b, c and d are consecutive terms of a G.P. To prove:

Solution:

### Geometric Progression Exercise 11D – Selina Concise Mathematics Class 10 ICSE Solutions

Question 1.

Find the sum of G.P. :

(i) 1 + 3 + 9 + 27 + ……….. to 12 terms.

(ii) 0.3 + 0.03 + 0.003 + 0.0003 + …… to 8 terms.

Solution 1(i).

Solution 1(ii).

Solution 1(iii).

Solution 1(iv).

Solution 1(v).

Solution 1(vi).

Question 2.

How many terms of the geometric progression 1+4 + 16 + 64 + ……… must be added to get sum equal to 5461?

Solution:

Question 3.

The first term of a G.P. is 27 and its 8^{th} term is . Find the sum of its first 10 terms.

Solution:

Question 4.

A boy spends ₹ 10 on first day, ₹ 20 on second day, ₹ 40 on third day and so on. Find how much, in all, will he spend in 12 days?

Solution:

Question 5.

The 4th and the 7th terms of a G.P. are respectively. Find the sum of n terms of this G.P.

Solution:

Question 6.

A geometric progression has common ratio = 3 and last term = 486. If the sum of its terms is 728 ; find its first term.

Solution:

Question 7.

Find the sum of G.P. : 3, 6, 12, ……………. 1536.

Solution:

Question 8.

How many terms of the series 2 + 6 + 18 + ………….. must be taken to make the sum equal to 728 ?

Solution:

Question 9.

In a G.P., the ratio between the sum of first three terms and that of the first six terms is 125 : 152.

Find its common ratio.

Solution:

Question 10.

Find how many terms of G.P. ………. must be added to get the sum equal to ?

Solution:

Question 11.

If the sum 1 + 2 + 2^{2} + ………. + 2^{n-1} is 255, find the value of n.

Solution:

Question 12.

Find the geometric mean between :

(i)

(ii) 14 and

(iii) 2a and 8a^{3}

Solution 12(i).

Solution 12(ii).

Solution 12(iii).

Question 13.

The sum of three numbers in G.P. is and their product is 1. Find the numbers.

Solution:

Question 14.

The first term of a G.P. is -3 and the square of the second term is equal to its 4^{th} term. Find its 7^{th} term.

Solution:

Question 15.

Find the 5^{th} term of the G.P. , 1, …..

Solution:

Question 16.

The first two terms of a G.P. are 125 and 25 respectively. Find the 5th and the 6th terms of the G.P.

Solution:

Question 17.

Find the sum of the sequence –, 1, – 3, 9, …………. upto 8 terms.

Solution:

Question 18.

The first term of a G.P. in 27. If the 8thterm be , what will be the sum of 10 terms ?

Solution:

Question 19.

Find a G.P. for which the sum of first two terms is -4 and the fifth term is 4 times the third term.

Solution:

**Additional Questions**

Question 1.

Find the sum of n terms of the series :

(i) 4 + 44 + 444 + ………

(ii) 0.8 + 0.88 + 0.888 + …………..

Solution 1(i).

Solution 1(ii).

Question 2.

Find the sum of infinite terms of each of the following geometric progression:

Solution 2(i).

Solution 2(ii).

Solution 2(iii).

Solution 2(iv).

Solution 2(v).

Question 3.

The second term of a G.P. is 9 and sum of its infinite terms is 48. Find its first three terms.

Solution:

Question 4.

Find three geometric means between and 432.

Solution:

Question 5.

Find :

(i) two geometric means between 2 and 16

(ii) four geometric means between 3 and 96.

(iii) five geometric means between and

Solution 5(i).

Solution 5(ii).

Solution 5(iii).

Question 6.

The sum of three numbers in G.P. is and their product is 1. Find the numbers.

Solution:

Sum of three numbers in G.P. = and their product = 1

Let number be , a, ar, then

Question 7.

Find the numbers in G.P. whose sum is 52 and the sum of whose product in pairs is 624.

Solution:

Question 8.

The sum of three numbers in G.P. is 21 and the sum of their squares is 189. Find the numbers.

Solution:

**More Resources for Selina Concise Class 10 ICSE Solutions**

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Dolly says

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Suhani says

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R says

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Ilisha srivastava says

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Santhra says

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Khushi Mehrotra says

Helpful but not arranged exercise wise. Pl. Improve it.

Jethalalgada says

Well said.

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These are really helpful for those students who do not get proper guidance from their teacher or tutor.

Dr. Mahipal Rohila says

Fantastic solution to gp

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It’s really helpful but not in arranged manner.

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