Plus One Botany Model Question Papers Paper 2 is part of Plus One Botany Previous Year Question Papers and Answers. Here we have given Plus One Botany Model Question Papers Paper 2
Plus One Botany Model Question Papers Paper 2
|Category||Plus One Previous Year Question Papers|
Time: 1 Hours
Cool off time : 10 Minutes
General Instructions to candidates :
- There is a ‘cool off time’ of 10 minutes each for Botany and Zoology in addition to the writing time ‘ of 1 hour each. Further there is a ‘ 5 minutes’ ‘preparatory time’ at the end of the Botany Examination and before the commencement of the Zoology Examination.
- Use the ‘cool off time’ to get familiar with the questions and to plan your answers.
- Read the instructions carefully.
- Read questions carefully before you answering.
- Calculations, figures and graphs should be shown in the answer sheet itself.
- Malayalam version of the questions is also provided.
- Give equations wherever necessary.
- Electronic devices except non programmable calculators are not allowed in the Examination Hall.
Answer all questions from question numbers 1 to 4. Each carry one score.
Fill in the blank
Cork cambium is otherwise called …..
Glycolysis is present in all organisms and it is the only process of respiration in anaerobic organisms.
Where does glycolysis occur?
By observing the relationship of the first pair, fill in the blanks of the second pair
F. W. Went : Auxins
E. Kurosawa : …….
Out of the four statements given below related to respiration, the correct statements are:
i. Though respiration has traditionally been considered a catabolic process, it would be better to consider it as an amphibolic pathway.
ii. In muscles when oxygen is inadequate, lactic acid is reduced to pyruvic acid.
iii. When facts are used in respiration, the RQ is greater than one.
iv. In respiration, the energy of oxidation- reduction is utilized for phosphorylation,
a. i) and ii)
b. ii) and iii)
c. iii) and iv)
d. i) and iv)
Answer any seven from question numbers 5 to 13. Each carries two scores.
Match the following columns A,B.
Observe the incomplete schematic representation given below and answer the questions.
Identify this pathway common for both
a. aerobic and anaerobic respiration.
b. Complete the scheme by filling the boxes A, B, C and D.
c. Mention the three major ways in which different cells handle pyruvic acid produced by this pathway.
‘Diatoms, the chief producers in the oceans, are useful to us even after their death.’ Evaluate the statement.
In dicot stem, cambium occurs between xylem and phloem and the vascular bundles are arranged in a broken ring fashion. However, dicot stem grows in diameter in a circular manner. Explain briefly how this could happen.
Identify the cycle and name the scientist who traced the pathway.
Two crucial events of aerobic respiration takes place in two parts of mitochondria. Locate the two parts and mention the two events in one or two sentences each.
Observe the given floral diagram.
a. Identify the family.
b. Write any four floral characters of the identified family.
How can you differentiate active transport from facilitated diffusion?
Fermentation is the incomplete oxidation of pyruvic acid. Find the difference between two types of fermentations in micro-organisms.
Answer any four from question numbers 14 to 18. Each carries 3 scores.
Breakdown of glucose into two molecules of pyruvic acid is called glycolysis. Draw the scheme of glycolysis using the following, starting from glucose ending in pyruvic and 1,3-biphosphoglyceric acid, glyceraldehyde 3 phosphate—> dihydroxy acetone phosphate, fructose, 1, 6- biphosphate, 3-phosphoglycerate, fructose-6-phosphate phosphoenol pyruvate, glucose-6 phosphate, 3 phos-phoglyceric acid.
A diagram prophase I stage of a Meiosis is given below. Draw similar diagrams to il-lustrate the following stages.
Comment on the following statements.
a. Abscisic acid is also known as stress hormone.
b. There are hormones promoting apical dominance and those acting against apical dominance.
An anatomist observed peculiar type of large spherical bundle sheath cells in sugarcane leaf and a physiologist identified the presence of PEP carboxylase in that leaf mesophyll.
a. Name the peculiar leaf anatomy.
b. Explain the physiological advantage of such type of plants.
The use of radioactive C14 by Melvin Calvin in algal photosynthesis studies led to the discovery of Co2 fixation in green plants.
a. Identify the first stable product in this Co2 fixation cycle.
b. Which are the three main stages of this cycle?
c. Name the enzyme which catalyzes the first stage of this cycle.
d. Work out how many ATP and NADPH molecules will be required to make one molecule of glucose?
d – i and iv
a. Glycolysis/EM P Pathway
b. A – Glucose 6- phosphate
B – Triose phosphate/glyceraldehyde- 3 phosphate
C – 2 -phosphoglyceric acid
D – 2 -phosphoenolpyruvic acid
c. Lactic acid fermentation in muscle cells. Alcoholic fermentation in Yeast. Aerobic respiration.
In diatoms the cell wall form 2 thin over laping shells which fit together as in soap box. These walls are embeded with silica. So it is very tough and Indistricta Diatoms deposits their cell wall in their habitat. This accumulation of cell wall over a billion year is known diatomaceous earth used in pol-ishing, filtration of oils and syrups.
The inter-fascicular cambium joins with in- tra-fascicular cambium and forms ring of cambium.
Kreb’s cycle. Adolf Hanns Krebs
For aerobic respiration to take place within the mitochondria, the final product of gly-colysis, pyruvate is transported from the cytoplasm into the mitochondria.
The crucial events in aerobic respiration are:
i. The complete oxidation of pyruvate by the stepwise removal of all the hydrogen atoms, leaving three molecules of C02.
ii. The passing on of the electrons removed as part of the hydrogen atoms to molecular O2 with simultaneous synthesis of ATP.
The first process takes place in the matrix of the mitochondria while the second process is located on the inner membrane of the mitochondria.
a. Liliaceae / Lily family
b. a. Inflorescence: solitary/cymose; often umbellate clusters
Flower: bisexual; actinomorphic
Perianth tepal six (3+3), often united into tube; valvate aestivation
Androecium: stamen six, 3+3, epitepalous
Gynoecium: tricarpellary.syncarpous, ovary superior, trilocular with many ovules; axile placentation
Fruit : capsule, rarely berry
Active transport : Transport of substances from low concentration to a higher concentration (uphill transport). It requires ATP to carry substances across the cell mem-brane.
Facilitated diffusion: Transport of substances from higher concentration to lower concentration. Substances move across the cell membrane without the expenditure of energy.
Alcoholic fermentation :- Pyruvic acid is converted to carbon dioxide and ethanol.
Lactic acid fermentation :- Pyruvic acid is converted to lactic acid.
Glucose → glucose 6 – phosphate → Fructose 6 phosphate →fructose 1, 6- biphosphate (6c) → Dihydroxy acetone phosphate (3c)
Glyceraldehydel, 3 phosphate (3c)
1, 3 biphospho glyceric acid
3 phospho glyceric acid
2 phosphoglyceric acid
2 phosphoenol pyruvate
Pyruvic acid (3c)
a. ABA stimulates closure of stomata/ increases tolerance of plants to various kinds of stress
b. Apical dominance – Auxin/Ethylene. Cytokinin act against apical dominance.
a. Kranz anatomy
b. 1. High temperature.
2. Photorespiration does not occur.
3. Several layers of bundle sheath cells.
4. Having large number of chloroplast.
5. No intercellular spaces.
a. 3-Phosphoglyceric acid (3-PGA).
b. Carboxylation, Reduction and Regeneration.
c. RuBPcarboxylase-oxygenase (RuBisCO)
d. 18 ATP molecules and 12 NADPH molecules.
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