Plus Two Zoology Previous Year Question Papers and Answers 2017 is part of Plus Two Zoology Previous Year Question Papers and Answers. Here we have given Plus Two Zoology Previous Year Question Papers and Answers 2017.
Plus Two Zoology Previous Year Question Papers and Answers 2017
|Sample Paper Set||2017|
|Category||Plus Two Previous Year Question Papers|
Time: 1 Hour
Cool off time: 10 Minutes
Maximum: 30 Score
General Instructions to Candidates :
- There is a ‘cool off time’ of 10 minutes each for Botany and Zoology in addition to the writing time of 1 hour each. Further, there is ‘5 minutes’ ‘Preparatory Time’ at the end of the Botany Examination and before the commencement of Zoology Examination.
- You are not allowed to write your answers nor to discuss anything with others during the ‘cool off time’ and ‘Preparatory time’.
- Use the ‘cool off time’ to get familiar with the questions and to plan your answers.
- Read questions carefully before answering.
- All questions are compulsory and the only internal choice is allowed.
- When you select a question, all the sub-questions must be answered from the same question itself.
- Calculations, figures, and graphs should be shown in the answer sheet itself.
- Malayalam version of the questions is also provided.
- Give equations wherever necessary.
- Electronic devices except non-programmable calculators are not allowed in the Examination Hall.
Answer all questions from 1-3. Each question carries 1 score.
The following table shows the F2 generation of a dihybrid cross. Identify the ‘Phenotype’ with homozygous recessive genotype. Find out AB: C:D.
|No||Phenotype||No.of offspring (F2 gen.)|
values of a frugivorous bat species are given below. Which value is not applicable to continents?
Distinguish in-situ conservation from ex- situ conservation with one example each.
Which of the following pairs of STDs is completely curable?
1. HIV, Hepatitis-B
2. Hepatitis-6, Gonorrhoea
3. Syphilis, Gonorrhoea
4. Chlamydomonasgenital herpes
Which of the following do not have similar sex chromosomes? (Homogametic)
1. Human female
2. Drosophila female
3. Bird female
4. Bird male
Feeding…………. in the first few days is essential for preventing infections in a newly born baby.
L.H. and FSH are gonadotrophins. Distinguish their roles in males and females.
Examine the following fragment of the beta-globin chain in human hemoglobin and identify the hereditary disease with reason.
A population of 208 people of MN blood group was sampled and it was found that 119 were MM group, 76 MN group, and 13 NN groups. Answer the following questions:
a. Determine the gene frequencies of M and N alleles in the population.
b. How do the above frequencies affect evolution?
Examine the pictures of Darwin’s finches given below and answer the following
a. What phenomenon in evolution is represented in the picture?
b. Explain the phenomenon with the help of an additional example.
What is the advantage of biofertilizers over chemical fertilizers / Give an example for biofertilizer?
What is ART? Categorize the following ARTs based on their applications in male sterility and female
sterility: GIFT, Al.
Which of the following sets of gases were used in Miller’s experiment?
1. CH4, no2, H20, C02
2. NH3, CH3, H20, H2
3. H2, CH4, NH3 ,H20
4. H20, N, CH4, H2
Which of the following combinations do not apply to DNA?
a. Deoxyribose, Guanine
b. Ribose, Adenine
c. Deoxyribose, Uracil
d. Guanine, Thymine
1. (a) and (b)
2. (b) and (c)
3. (c) and (d)
4. (a) and (d)
Examine the diagram of mRNA given below. Mark the 5’ and 3’ end of the mRNA by giving reasons.
A small fragment of the skin of a different person was extracted from the nails of a murdered person. This fragment of skin led the crime investigators to the murderer. Based on this incident answer the following questions:
a. What technique was used by the investigators?
b. What is the procedure involved in this technique?
In an E. coli culture, lactose is used as food instead of glucose. If so, answer the following questions:
a. How do the bacteria respond to the above situation at the genetic level?
b. If lactose is removed from the medium what will happen?
Morphine is said to be an abused drug. Discriminate the terms ‘use’ and ‘abuse’ of drugs based on this example.
Differentiate Active immunity from Passive immunity. Give an example for Passive immunity.
B is the homozygous recessive genotype
A:B:C: D = 3: 1:9:3
|In-situ conservation||Ex-situ conservation|
|1. It is the process of protecting endangered species of plants or animals in natural habitats, either by protecting or cleaning up the habitat itself or by defending the species from predators.||1. It is the process of protecting endangered species of plants or animals by removing them from unsafe or threatened habitats and placing them under the care of humans.|
2. It helps in recovering populations in the surroundings where they have developed their distinctive features;
Eg., National parks, wildlife sanctuaries, Biosphere reserves.
2. It helps in recovering populations or preventing their extinction under stimulated conditions that closely resemble their natural habitats.
Eg., Botanical gardens, zoos, seed/pollen bank, gene bank.
3. Syphilis, Gonorrhoea.
3. Bird female.
Colostrum (First milk).
In the male, LH stimulates the Leydig cells in testes to secrete testosterone and FSH stimulates Sertoli cells in testes for spermatogenesis. In females, LH stimulates the ovary to develop corpus luteum and FSH stimulates the ovary to develop follicles.
Sickle cell anemia.
Substitution of glutamic acid by valine at the sixth position of the beta-globin chain of hemoglobin molecule (Point mutation).
Frequency of M = (119 x 2)+76
Frequency of M = 238+76 ’
Frequency of N = (13×2)+76
= 26 +76
Gene frequency of M allele =M/(M+N)
M = 314/(314+102)
Gene frequency of M allele = 0.75
Gene frequency of N allele = N/(M+N)
N = 102/(314+102) N= 0.245
Gene frequency of N allele = 0.25
M = 0.75
N = 0.25
M+N = 1 or (p+q = 1)
75+0.25 = 1 ,
So it agrees with the Hardy weinberg law of equilibrium.
b. The frequency of occurrence of alleles of gene ramain fixed and same through generations. A change in the frequency of alleles brings about evolu- tion.The above frequencies agrees the Hardy weinberg law of equilibrium, so allele frequencies in a population constant and stable generation after generation. It doesn’t affect evolution.
a. The bird is Darwin’s Finches. The ‘ name of Island is Galapagos island.
b. Darwin finches differed primarily in body size and beak shape as adaptation to types of food available on islands. All these species evolved in different directions from the common ancestral form and adapted to new invaded habits and to modes of life necessary there. This phenomenon is called adaptive radiation.
Biofertilisers are either organism or organic compounds that enrich the nutrient quality of the soil. .The main sources of bio fertilisers are bacteria, fungi, and cyanobacteria. The root nodule of leguminous plants formed by the symbiotic association of Rhizobium, fix atmospheric nitrogen into organic forms which are used by the plant as a nutrient, while free-living bacteria in the soil like Azospirillum and Azo- tobacter fix atmospheric nitrogen, thus enriching the nitrogen content of the soil.
Mycorrhizae are a symbiotic association of fungi with plants. Many members of the genus Glomus form mycorrhizae. The fungal symbiont absorbs phosphorus from the soil and passes it to the plant. Plants having such associations show other benefits also, such as– resistance to root borne pathogens, tolerance to salinity and drought and an overall increase in plant growth and development. Cyanobacteria like Anabaena, Nostoc, Oscillatoria etc; fix atmospheric nitrogen and serve as biofertilizers. These algae also add organic matter to the soil and increase its fertility. Thus if farmers use bio-fertilizers regularly in the fields it increase soil nutrients and fertility and reduces the dependence on chemical fertilisers.
Infertile couples could be assisted to have children through certain special techniques called ART (Assisted Reproductive Technologies).
Al (Artificial Insemination)- This technique is used in cases where the male is unable (male sterility) to inseminate sperms in the female reproductive tract.
GIFT (Gamete Intra Fallopian Transfer) – In this technique is used in the cases where females who unable (Female sterility) to conceive.lt is the method of transfer of ovum from a donor into the fallopian tube of a female who unable to produce ovum.
It can provide the right conditions for fertilisation and development of the embryo.
(b) and (c)
Polyadenylation. It is the addition of a poly (A) tail to a messenger RNA (Adding adenosine to 3′ end). The poly(A) tail consists of multiple adenosine monophosphates, it is a stretch of RNA that has only adenine bases. Polyadenylation is part of the process that produces mature messenger RNA (mRNA) for translation.
a. DNA Fingerprinting,
b. 1. Isolation of DNA.
- Digestion of DNA by restriction endonuclease.
- Separation of DNA fragments by electrophoresis.
- Transferring of separated DNA fragments to nitrocellulose paper.
- Hybridisation using labelled VNTR probe.
- Detection of hybridised DNA fragments by autoradiography.
a. E coli bacteria can break down lactose. If glucose is around, they would much rather use that. Glucose requires fewer steps and less energy to break down than lactose. However, if lactose is the only sugar available, the E. coli will go right ahead and use it as an energy source.
To use lactose, the bacteria must express the lac operon genes, which encode key enzymes for lactose up taking and metabolism. To be as efficient as possible, E-coli should express the lac operon only when two conditions are met: Lactose is available, and Glucose, is not available
b. The level of inducer is completely metabolised by enzymes, it causes synthesis of repressor from repressor gene.
The repressor binds to the operator gene and blocks RNA polymerase from transcribing the operon. The result, transcription’ is stopped. This type of regulation is called negative regulation.
When drugs are taken for purposes other than medicinal or taken in amounts or frequencies that impairs physical, physiological or psychological functions, it is called drug abuse. Morphine is a very effective sedative and painkiller. It is very useful in patients who have undergone surgery.
Active and passive immunity.
- When a host is exposed to an antigen (which may be living or dead microbes), antibodies are produced in the host body against that antigen. This type of immunity is called active immunity.
eg..Vaccine against hepatitis B-virus
- When ready-made antibodies are directly given to protect the body against foreign agents, it is called passive immunity.
eg., During Tetanus injection to a pregnant woman, the foetus receives antibodies from the mother through the placenta.
You can also Download Plus Two Zoology Previous Year Question Papers and Answers to help you to revise complete Syllabus and score more marks in your examinations.
We hope the Plus Two Zoology Previous Year Question Papers and Answers 2017 help you. If you have any query regarding Plus Two Zoology Previous Year Question Papers and Answers 2017, drop a comment below and we will get back to you at the earliest.