Plus Two Physics Chapter Wise Previous Questions Chapter 10 Wave Optic is part of Kerala Plus Two Physics Chapter Wise Previous Questions and Answers Kerala. Here we have given Plus Two Physics Chapter Wise Questions and Answers Chapter 10 Wave Optic.
Kerala Plus Two Physics Chapter Wise Previous Questions and Answers Chapter 10 Wave Optic
An unpolarised light incident on a medium as shown in figure
Show that the direction of reflected and refracted waves are mutually perpendicular. [March-2018]
Hence, angle between reflected ray and
refracted ray = 180 – (p+r)=180 – 90 = 90°
i.e., they are mutually perpendicular.
A plane wave-front AB incident on a surface XY and undergoes refraction as shown in figure:
a. Prove Snell’s law of refraction by using this figure.
b. What is the change in speed of propagation and frequency of the refracted wave? [March-2018]
a. Sound wave do not exhibit……
b. Describe Young’s double slit experiment to determine bandwidth of the interference pattern.
a.The Intensity of scattered light I ¡n Rayleigh scattering Is proportional to …….
b. Explain the diffraction pattern obtained due to a single slit and represent graphically the variation of intensity with angle of diffraction. [March-2017]
The reason sound can’t be polarised is that it is a longitudinal wave unlike light which is a transverse wave.
Condition for secondary minima: Divide the slit into 2n parts. Path difference λ/2 corres ponds to phase difference of π (i.e., waves meet out of phase). As there are even number of parts, the net intensity is zero (dark fringe) at P.
The condition for nth secondary minima is. d sinθ = n λ n = 1, 2, 3
Condition for secondary maxima: Divide the slit into 2n+1 parts. Contribution from >2n
parts will get cancelled. But the wavelet from
(2n+1)th part will contribute to some intensity to from a secondary maxima. The condition for nth secondary maxima is,
Angular width of central maxima:
The following questions has choice:
a. Unpolarized light is incident on a plane glass surface. What should be the angle of incidence so that the reflected and refracted rays are perpendicular to each other? (Given n = 1.5)
b. Using Huygen’s concept of wave front, derive Snell’s law of refraction.
a. Light waves from two coherent sources having intensities I and 2I cross each other at a point with a phase difference of 60°. What is the resultant intensity at the point?
b. With the help of a diagram obtain an expression for finding the distance between two consecutive bright or dark fringes in the interference pattern produced by double slits. [March-2016]
a. tan ip = n
ip = tan-1 (n) = tan1 (1.5) = 56.3°
b. Let v2 and v2 speed of light in medium 1 and 2 respectively. We assume a plane wave front AB propagating in the direction of A’A incident on the interface at an angle i.
i. Interferences of light from two sources can be observed if
a. the sources are independent
b. the sources are of different frequencies and random phases
c. the sources are of different frequency
d. the sources are coherent
ii. Draw Young’s arrangement to produce interference pattern.
iii. Derive an expression for the fringe width of interference pattern formed on the screen.
iv. Write the condition to produce good interference bands. [March-2015]
i.d. the sources are coherent
iv.The two sources must be coherent. The amplitudes or intensities of the interfering waves must be equal or very nearly equal.
We obtained alternate dark and bright regions if we look at the shadow by an obstacle closed to geometrical shadow.
a. Mention the phenomenon behind it.
b. Differentiate the interference pattern with a coherently illuminated single slit diffraction pattern. [March-2014]
|Interference pattern||Diffraction pattern|
|1. Band width is same not same||1. Band width is|
|2. Uniform brightness for bright band and darkness for dark band||2. Not uniform brightness and darkness for|
|3. So many fringes or band can be seen||3. Few fringes can be see|
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