\nCOMPUTER APPLICATIONS<\/span><\/p>\n
(Two Hours)<\/em><\/strong> Section \u2018A\u2019 (40 Marks)<\/span><\/p>\n (Attempt all<\/strong> questions)<\/em><\/p>\n Question 1:<\/strong> Answer:<\/strong> (b)<\/strong> A token<\/strong> is the smallest individual unit in a program. E.g. : keyword, identifiers, literals etc. whereas an identifier<\/strong> is the name given to different parts of a program. E.g. : variable, functions, classes etc.<\/p>\n (c)<\/strong> Instance variables are variables that are created for each instance of a class. These variables represent property\/state of object. (d)<\/strong> Inheritance<\/strong> is the process by which objects of one class can link and share some common properties of objects from another class. (e)<\/strong> Two types of access specifier : Question 2:<\/strong> Answer:<\/strong> (b)<\/strong> equals () is a string function where as = = is a relational operator equals ( ) checks for the equality of strings, whereas = = checks the equality of 2 primitive type values.<\/p>\n (c)<\/strong> The parameter listed in the function prototype are termed as the formal parameters whereas the parameter used in the function call statement are the actual parameters.<\/p>\n (d)<\/strong> Exception handling is a term associated with handling irregular situations that occur while a program is executing. When some error is occurred in a program then an exception is created by its throwable class. It helps Java not to terminate the program when the error occurs rather the program is able to continue execution.<\/p>\n (e)<\/strong> The base class is a class whose properties will be inherited and the derived class is a class which inherits the base class. E.g. of base class is Super and derived class is Subclass. Question 3:<\/strong> (b)<\/strong> Convert the following segment into equivalent for loop [2]<\/strong> (c)<\/strong> If a = 5, b = 9 calculate the value of a+ = a++ – ++b +a \u00a0[2]<\/strong><\/p>\n (d)<\/strong> Give the output of the following expressions : (e)<\/strong> If, String x = \u201cComputer\u201d; (f)<\/strong> If, array [] = {1, 9, 8, 5 2}; (g)<\/strong> What does the following mean ? (h)<\/strong> Write a Java statement to input tread the following from the user using the keyboard. Answer:<\/strong> (b)<\/strong> After converting the while loop into for : (c)<\/strong> a + = a ++ – ++ b + a (d)<\/strong> (i) 9.99 (e)<\/strong> (i) ompu (f)<\/strong> (i) array length = 5. (g)<\/strong> Employee staff=new Employee() means that staff is an object of class Employee and it is being created.<\/p>\n (h)<\/strong> (i) char ch=(char)object.read(); SECTION B (60 Marks)<\/span><\/p>\n Attempt any four<\/strong> questions from this Section.<\/em> Question 4:<\/strong> Answer:<\/strong> Question 5:<\/strong> Answer:<\/strong> Question 6:<\/strong> Answer:<\/strong> Question 7:<\/strong> Answer:<\/strong>
\nAnswers to this Paper must be written on the paper provided separately.<\/em>
\nYou will not be allowed to write during the first 15 minutes.<\/em>
\nThis time is to be spent in reading the question paper.<\/em>
\nThe time given at the head of this Paper is the time allowed for writing the answers.<\/em>
\nThis paper is divided into two Sections.<\/em>
\nAttempt all<\/strong> questions from Section A<\/strong> and any four<\/strong> questions from Section B<\/strong>. <\/em>
\nThe intended marks for questions or parts of questions are given in brackets [ ].<\/em><\/p>\n
\n(a)<\/strong> Mention any two attributes required for class declaration. [2]<\/strong>
\n(b)<\/strong> State the difference between token and identifier. [2]<\/strong>
\n(c)<\/strong> Explain instance variable. Give an example. [2]<\/strong>
\n(d)<\/strong> What is inheritance and how is it useful in Java ? [2]<\/strong>
\n(e)<\/strong> Explain any two types of access specifier. [2]<\/strong><\/p>\n
\n(a)<\/strong> Two attributes required for class declaration :
\n(1) Access specifier (2) Class name.<\/p>\n
\ne.g.
\nclass text
\n{
\nint data 1; \/\/ These are instance
\nint data 2; \/\/ variables
\n:
\n:
\n}<\/p>\n
\nIt helps in reusability in such a way that it adds some additional features to a class without modifying the contents of a class.<\/p>\n
\n(i) private:<\/strong> accessible only to the class in which it is defined.
\n(ii) public:<\/strong> can be accessible in any class.<\/p>\n
\n(a)<\/strong> What is meant by an infinite loop ? Give an example. [2]<\/strong>
\n(b)<\/strong> State the difference between = = operator and equals () method. [2]<\/strong>
\n(c)<\/strong> Differentiate between actual parameter and formal parameter. [2]<\/strong>
\n(d)<\/strong> What is the use of exception handling in Java ? [2]<\/strong>
\n(e)<\/strong> Differentiate between base and derived class. [2]<\/strong><\/p>\n
\n(a)<\/strong> An infinite loop is a loop whose test condition is always true. This type of loop never ends by itself.
\nFor example :
\nfor (i=l; i>0; i++)
\n{
\nSystem.out.println(\u201cPrashant Arora\u201d);
\nbase class
\n}<\/p>\n
\n![\"icse-previous-papers-with-solutions-for-class-10-computer-applications-2008-1\"](\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/09\/icse-previous-papers-with-solutions-for-class-10-computer-applications-2008-1.png\")
<\/p>\n
\n(a)<\/strong> Explain the function of each of the following with an example:
\n(i) break;
\n(ii) continue; [4]<\/strong><\/p>\n
\n{
\nint i, 1=0;
\nwhile (i<=20)
\nSystem.out.print (i+\u201c\u201d);
\n1++;
\n}<\/p>\n
\n(i) If x = -9.99, calculate Math.abs(x);
\n(ii) If x=9.0, calculate Math.sqrt (x); [2]<\/strong><\/p>\n
\nString y = \u201cApplications\u201d;
\nWhat do the following functions return for :
\n(i) System.out.print(x.substring(1,5));
\n(ii) System.out.print(x.indexOf(x.charAt(4)));
\n(iii) System.out.print(y+x.substring(5));
\n(iv) System.out.print(x.equals(y)); [4]<\/strong><\/p>\n
\n(i) What is array.length()?
\n(ii) What is array[2] ? [2]<\/strong><\/p>\n
\nEmployee staff = new Employee (); [2]<\/strong><\/p>\n
\n(i) Character.
\n(ii) String. [2]<\/strong><\/p>\n
\n(a)<\/strong> (i) A break statement terminates the current loop and proceeds to the first statement that follows the loop. For example:
\nboolean prime=true;
\nfor(int i=2; i<n; i++)
\n{
\nprime=(n%i==0);
\nif (prime) break;
\n}
\n(ii) A continue statement transfers the control to the next iteration leaving all the other statement unexecuted that follows after the continue statement.
\nFor example :
\nfor(int i=1; i<20; i++)
\n{
\nif(i%2==0)
\ncontinue;
\nSystem.out.println(i);
\n}
\nThe above loop will print all the odd numbers.<\/p>\n
\nfor(int i=0; i<=20; i++)
\n{
\nSystem.out.print(i+\u201c \u201d);
\n}<\/p>\n
\n= 5 – 10 + 6
\na + = 1
\nThe value of a after execution will be 6.<\/p>\n
\n(ii) 3.0<\/p>\n
\n(ii) 4
\n(iii) Applicationster
\n(iv) False<\/p>\n
\n(ii) array [2] = 8.<\/p>\n
\n(ii) String str=object.readLine();<\/p>\n
\nThe answers in this Section should consist of the Programs in either Blue J environment or any program environment with Java as the base. Each program should be written using Variable descriptions!Mnemonic Codes such that the logic of the program is clearly depicted. Flow-Charts and Algorithms are not required.<\/em><\/p>\n
\nDefine a class employee having the following description :
\nData members\/instance variables:<\/strong>
\nint pan \u2014 to store personal account number
\nString name \u2014 to store name
\ndouble tax income \u2014 to store annual taxable income
\ndouble tax \u2014 to store tax that is calculated
\nMember functions:<\/strong>
\ninput() \u2014 Store the pan number, name, taxable income
\ncalc() \u2014 Calculate tax for an employee
\ndisplay() \u2014 Output details of an employee
\nWrite a program to compute the tax according to the given conditions and display the output as per given format. \u00a0 \u00a0 \u00a0[15]<\/strong><\/p>\n\n\n
\n Total annual Taxable Income<\/strong><\/td>\n Tax Rate<\/strong><\/td>\n<\/tr>\n \n Upto Rs. 1,00;000<\/td>\n No tax<\/td>\n<\/tr>\n \n From 1,00,001 to 1,50,000<\/td>\n 10% of the income exceeding Rs. 1,00,000<\/td>\n<\/tr>\n \n From 1,50,001 to 2,50,000<\/td>\n Rs. 5,000 + 20% of the income exceeding Rs. 1,50,000<\/td>\n<\/tr>\n \n Above Rs. 2,50,000<\/td>\n Rs. 25,000 + 30% of the income exceeding Rs. 2,50,000.<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n ![\"icse-previous-papers-with-solutions-for-class-10-computer-applications-2008-2\"](\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/09\/icse-previous-papers-with-solutions-for-class-10-computer-applications-2008-2.png\")
<\/p>\n
\nclass employee
\n{
\nint pan;
\nString name;
\ndouble taxincome, tax;
\nvoid input(int p, String n, Double income)
\n{
\npan=p;
\nname=n;
\ntaxincome=income;
\n}
\nvoid calc()
\n{
\nif(taxincome<=100000)
\n{
\ntax=0.0;
\n}
\nelse if(taxincome<=150000)
\n{
\ntax=1*(taxincome-100000);
\n}
\nelse if(taxincome<=250000)
\n{
\ntax=5000 + 2*(taxincome-150000);
\n}
\nelse
\n{
\ntax=25000 + 3*(taxincome-250000);
\n}
\n}
\nvoid display()
\n{
\nSystem.out.println(\u201cPan Number\\tName\\tTax-income\\tTax\u201d);
\nSystem.out.println(pan+\u201c \\ t\u201d+name+\u201c \\ t\u201d+taxincome+\u201c \\ t\u201d+tax);
\n}
\n}<\/p>\n
\nWrite a program to input a string and print out the text with the uppercase and lowercase letters reversed, but all other characters should remain the same as before.
\nExample:<\/strong>
\nINPUT : WelComE TO School
\nOUTPUT : wELcOMe to SCHOOL [15]<\/strong><\/p>\n
\nclass letter
\n{
\npublic static void main( )throws IOException
\n{
\nBufferedReader br=new BufferedReader(new InputStreamReader(System.in));
\nSystem.out.println(\u201cEnter any string :\u201d);
\nString s = br.readLine ( );
\nint len=s.length();
\nString s1=\u201d\u201d;\/\/second string
\nfor(int i=0; i<len; i++)
\n{
\nchar ch=s.charAt(i);
\nif(Character.isUpperCase(ch))
\n{
\ns1=s1+Character.toLowerCase(ch);
\n}
\nelse if(Character.isLowerCase(s.charAt(i)))
\n{
\ns1=s1+Character.toUpperCase(ch);
\n}
\nelse
\n{
\ns1=s1+s.charAt(i);
\n}
\n}
\ns=s1,
\nSystem.out.println(s);
\n}
\n}<\/p>\n
\nDefine a class and store the given city names in a single dimensional array. Sort these names in alphabetical order using the Bubble Sort technique only.
\nINPUT : Delhi, Bangalore, Agra, Mumbai, Calcutta
\nOUTPUT : Agra, Bangalore, Calcutta, Delhi, Mumbai \u00a0[15]<\/strong><\/p>\n
\nimport java.io.*;
\nclass city
\n{
\npublic static void main( )
\n{
\nString [ ] name = {\u201cDelhi\u201d, \u201cBangalore\u201d, \u201cAgra\u201d, \u201cMumbai\u201d, \u201cCalcutta\u201d};
\nint i, j;
\nString temp;
\n\/\/bubble sort begins
\nfor(i=0; i<4; i++)
\n{
\nfor (j=0; j<4\u2014i; j++)
\n{
\nif((name[j].compareTo(name[j+1]))>0)
\n{
\ntemp=name[j];
\nname[j]=name[j+1];
\nname[j+1]=temp;
\n}
\n}
\n}
\n\/\/printing
\nfor(i=0; i<5; i++)
\n{
\nSystem.out.println(name [i]);
\n}
\n}
\n}<\/p>\n
\nWrite a menu driven class to accept a number from the user and check whether it is a Palindrome or a Perfect number.
\n(a) Palindrome number\u2014 (a number is a Palindrome which when read in reverse order is same as read in the right order)
\nExample : 11, 101, 151 etc.
\n(b) Perfect number\u2014 (a number is called Perfect if it is equal to the sum of its factors other than the number itself.) Example : 6 = 1 + 2 + 3 \u00a0[15]<\/strong><\/p>\n
\nimport java.io.*;
\nclass number
\n{
\npublic static void main()throws IOException
\n{
\nInputStreamReader IR=new InputStreamReader(System.in);
\nBufferedReader br=new BufferedReader(IR);
\nSystem.out.println(\u201cPress 1 for Palindrome Number\u201d);
\nSystem.out.println(\u201cPress 2 for Perfect Number\u201d);
\nSystem.out.println(\u201cEnter your choice\u201d);
\nint ch=Integer.parseInt(br.readLine());
\nint num1, num2;
\nswitch(ch)
\n{
\ncase 1:
\nSystem.out.println(\u201cEnter the Number :\u201d);
\nnum1=Integer.parseInt(br.readLine());
\nint rev=0;
\nint x=num1; \/\/duplicate copy
\nwhile (x!=0)
\n{
\nrev=rev*10+x%10;
\nx=x\/10;
\n}
\nif(rev==num1)
\n{
\nSystem.out.println(\u201cThe number is Palindrome\u201d);
\n}
\nelse
\n{
\nSystem.out.println(\u201cThe Number is Not Palindrome\u201d);
\n}
\nbreak;
\ncase 2:
\nSystem.out.print(\u201cEnter the Number :\u201d);
\nnum2=Integer.parseInt(br.readLine());
\nint sum=0;
\nfor(int i=1; i<num2; i++)
\n{
\nif(num2%i==0)
\n{
\nsum=sum+i;
\n}
\n}
\nif(sum==num2)
\n{
\nSystem.out.println(\u201cThe Number is Perfect Number\u201d);
\n}
\nelse
\n{
\nSystem.out.println(\u201cTbe Number is Not a Perfect Number\u201d);
\n}
\nbreak;
\ndefault:
\nSystem.out.println(\u201cWrong Choice! Run the program again\u201d);
\nbreak;
\n}
\n}
\n}<\/p>\n
![\"icse-previous-papers-with-solutions-for-class-10-computer-applications-2008-3\"](\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/09\/icse-previous-papers-with-solutions-for-class-10-computer-applications-2008-3.png\")