{"id":538,"date":"2023-05-04T10:00:00","date_gmt":"2023-05-04T04:30:00","guid":{"rendered":"https:\/\/www.aplustopper.com\/?p=538"},"modified":"2023-05-05T09:16:45","modified_gmt":"2023-05-05T03:46:45","slug":"solving-a-quadratic-equation-by-factoring","status":"publish","type":"post","link":"https:\/\/www.aplustopper.com\/solving-a-quadratic-equation-by-factoring\/","title":{"rendered":"Solving A Quadratic Equation By Factoring"},"content":{"rendered":"

Solving A Quadratic Equation By Factoring<\/a><\/strong><\/h2>\n

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Since, 3x2<\/sup> \u2013 5x + 2 is a quadratic polynomial;
\n3x2<\/sup> \u2013 5x + 2 = 0 is a quadratic equation.
\nAlso,
\n3x2<\/sup> \u2013 5x + 2 = 3x2<\/sup> \u2013 3x \u2013 2x + 2 [Factorising]
\n= 3x (x \u2013 1) \u2013 2(x \u2013 1)
\n= (x \u2013 1) (3x \u2013 2)
\nIn the same way :
\n3x2<\/sup> \u2013 5x + 2 = 0 \u00a0 \u21d2 \u00a0 3x2<\/sup> \u2013 3x \u2013 2x + 2 = 0 \u00a0\u00a0[Factorising L.H.S.]
\n\u21d2 \u00a0 (x \u2013 1) (3x \u2013 2) = 0
\ni.e., \u00a0x \u2013 1 = 0 \u00a0 or \u00a0 3x \u2013 2 = 0
\n\u21d2 \u00a0x = 1 \u00a0 or \u00a0 x = 2\/3
\nwhich is the solution of given quadratic equation.
\nIn order to solve the given Quadratic Equation:<\/strong>
\n1. Clear the fractions and brackets, if given.
\n2. By transfering each term to the left hand side; express the given equation as
\nax2\u00a0<\/sup>+ bx + c = 0 \u00a0 or \u00a0 a + bx + cx2<\/sup> = 0
\n3. Factorise left hand side of the equation obtained (the right hand side being zero).
\n4. By putting each factor equal to zero; solve it.<\/p>\n

Solving A Quadratic Equation By Factoring With\u00a0Examples<\/strong><\/h2>\n