{"id":40971,"date":"2024-02-19T07:35:33","date_gmt":"2024-02-19T02:05:33","guid":{"rendered":"https:\/\/www.aplustopper.com\/?p=40971"},"modified":"2024-02-19T12:36:19","modified_gmt":"2024-02-19T07:06:19","slug":"plus-one-maths-chapter-wise-previous-questions-chapter-11","status":"publish","type":"post","link":"https:\/\/www.aplustopper.com\/plus-one-maths-chapter-wise-previous-questions-chapter-11\/","title":{"rendered":"Plus One Maths Chapter Wise Previous Questions Chapter 11 Conic Sections"},"content":{"rendered":"
Question 1. Question 2. Question 3. Question 4. Question 5. Question 6. Question 7. Question 8. Question 1. Question 2. Question 3. Question 4. Question 5. Question 6. Question 7. Question 8. Question 9. Question 10. Kerala Plus One Maths Chapter Wise\u00a0Previous Questions Chapter 11 Conic Sections Plus One Maths Conic Sections 3 Marks Important Questions Question 1. 1. Find the equation of the Hyperbola where foci (0,\u00b18)are and the length of the latus rectum is 24.(IMP-2012) Answer: Since foci (0,\u00b18) => ae = 8 Latus rectum = 24= => 12a […]<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_genesis_hide_title":false,"_genesis_hide_breadcrumbs":false,"_genesis_hide_singular_image":false,"_genesis_hide_footer_widgets":false,"_genesis_custom_body_class":"","_genesis_custom_post_class":"","_genesis_layout":"","footnotes":""},"categories":[42728],"tags":[],"yoast_head":"\n
\n1. Find the equation of the Hyperbola where foci (0,\u00b18)are and the length of the latus rectum is 24.(IMP-2012)<\/span>
\nAnswer:
\nSince foci (0,\u00b18)
\n=> ae = 8
\nLatus rectum = 24= \\(\\frac {2b\u00b2 }{ a }\\)
\n=> 12a = b\u00b2
\nb\u00b2 =a\u00b2(e\u00b2 -1)
\n=> b\u00b2 – a\u00b2e\u00b2 -a\u00b2
\n=>12a = 64 – a\u00b2
\n=>a\u00b2+12a-64 = 0
\n=> a = – 16,4
\nacceptable value is => a = 4
\n=> 48 = b\u00b2
\nHence equation is
\n<\/p>\n
\nFind the equation of the circle with centre (- a,- b)and radius \\(\\sqrt{a^{2}+b^{2}}\\) .\u00a0(IMP-2012)<\/span>
\nAnswer:
\nWe have the equation of a circle as;
\n(x-h)\u00b2 + (y-k)\u00b2 – r\u00b2
\n=> (x + a)\u00b2 +(y + b)\u00b2 = a\u00b2 + b\u00b2
\n=> x\u00b2 +2 ax + a\u00b2 + y\u00b2 +2 by + b\u00b2 =a\u00b2 +b\u00b2
\n=> x\u00b2 +2ax + y\u00b2 +2by = 0<\/p>\n
\nFind the coordinate of the foci, the length of the major axis, minor axis, latus rectum and eccentricity of the ellipse \\(\\frac{x^{2}}{25}+\\frac{y^{2}}{9}=1\\) . (MARCH-2013)<\/span>
\nAnswer:
\n<\/p>\n
\nConsider the parabola y\u00b2 =12x.\u00a0(MARCH-2015)<\/span>
\ni) Find the coordinate of the focus.
\nii) Find the length of the latus rectum.
\nAnswer:
\ni) Given; y\u00b2 =12x comparing with y\u00b2 = 4ax We have 4a = 12 => a = 3 Then; Focus is (3,0)
\nii) Length of latus rectum = 4a = 12<\/p>\n
\nFind the foci, vertices, the eccentricity and the length of the latus rectum of the hyperbola 16x\u00b2 – 9y\u00b2 =144. (SAY-2017)\u00a0<\/span>
\nAnswer:
\nThe equation of the hyperbola is of the form
\n
\n=>a\u00b2 =9,b\u00b2 =16
\n=>c\u00b2 = a\u00b2 +b\u00b2 =9 + 16 = 25
\n=>c = 5
\nCoordinate of foci are (\u00b15,0)
\nCoordinate of vertices are (\u00b1a,0) => (\u00b13,0)
\n<\/p>\n
\nDirectrix of the parabola x\u00b2 = – 4ay is ………..\u00a0(MARCH-2014)<\/span>
\na) x + a = 0
\nb) x – a = 0
\nc) y – a = 0
\nd) y + a = 0
\nFind the equation of the ellipse whose length of the major axis is 20 and foci are (0 \u00b15)
\n(March-2015)
\nAnswer:
\ni) y-a = 0
\nii) The equation of the ellipse is of the form;
\n<\/p>\n
\nFind the coordinates of the focii, vertices, eccentricity and the length of the Latus Rectum of the ellipse 100x\u00b2 + 25y\u00b2 = 2500\u00a0(IMP-2015)<\/span>
\nAnswer:
\nGiven: 100x\u00b2 +25y\u00b2 = 2500
\n<\/p>\n
\nFind the foci, vertices, length of the major axis and eccentricity of the ellipse: \\(\\frac{x^{2}}{25}+\\frac{y^{2}}{9}=1\\)\u00a0(MARCH-2016)<\/span>
\nAnswer:
\nSince 25 > 9 the standard equation of the ellipse is \\(\\frac{x^{2}}{25}+\\frac{y^{2}}{9}=1\\) => a\u00b2 =25;b\u00b2 =9
\nc\u00b2 =a\u00b2 – b\u00b2 =25 – 9 = 16
\n=>c = 4
\nCoordinate of foci are (\u00b14,0)
\nCoordinate of vertex are (\u00b15,0)
\nLength of major axis = 2a = 2 x 5 = 10
\n<\/p>\nPlus One Maths Conic Sections 4 Marks Important Questions<\/h3>\n
\nAn ellipse whose major axis as x-axis and the centre (0,0) passes through (4,3) and (- 1,4).\u00a0(MARCH-2010)<\/span>
\ni) Find the equation of the ellipse.
\nii) Find is eccentricity.
\nAnswer:
\ni)
\n
\nii)
\n<\/p>\n
\nConsider the conic find 9y\u00b2 -4x\u00b2 = 36\u00a0(IMP-2010)<\/span>
\ni) The foci.
\nii) Eccentricity.
\niii) Length of latus rectum.
\nAnswer:
\n<\/p>\n
\nFind the equation of the circle with center (2,2) and passing through the point (4,5).\u00a0(MARCH-2011)<\/span>
\nFind the eccentricity and the length of latus rectum of the ellipse 4x\u00b2 + 9y\u00b2 =36
\nAnswer:
\n<\/p>\n
\nFor the hyperbola 9x\u00b2 – 16y\u00b2 =144\u00a0(IMP-2011)<\/span>
\ni) find eccentricity.
\nii) find the latus rectum.
\nAnswer:
\ni)
\n
\nii)
\n<\/p>\n
\nA hyperbola whose transverse axis is x-axis, centre (0,0) and foci (\u00b1\u221a10,0) passes through the point (3,2)\u00a0(MARCH-2012)<\/span>
\ni) Find the equation of the hyperbola.
\nii) Find the eccentricity.
\nAnswer:
\ni)
\n
\nii)
\n<\/p>\n
\nFind the centre and radius of the circle.\u00a0(IMP-2013)<\/span>
\nx\u00b2 +y\u00b2 – 8x + 10y – 12 = 0.
\nii) Determine the eccentricity and length of latus rectum of the hyperbola —–
\nAnswer:
\ni) Comparing with the general equation we have
\ng = – 4; f = 5; c = – 12
\nCentre – (- g,- f) => (4,- 5)
\n\\(\\sqrt{g^{2}+f^{2}-c} \\)= \\(\\sqrt{16+25+12}=\\sqrt{53}\\)
\nii)
\n<\/p>\n
\nConsider the ellipse \\(\\frac{x^{2}}{25}+\\frac{y^{2}}{9}=1\\). Find the coordinate of the foci, the length of the major axis, the length of the minor axis, latus rectum and eccentricity.\u00a0(MARCH-2014)<\/span>
\nAnswer:
\n<\/p>\n
\nWhich one of the following equations\u00a0(IMP-2014)<\/span>
\nrepresents a parabola which is symmetrical about the positive Y-axis?
\na) y\u00b2 = 4x
\nb) y\u00b2 = – 8x
\nc) x\u00b2 + 4y = 0
\nd) x\u00b2 – 4y = 0
\nii) Find the equation of the ellipse vertices are (\u00b113,0) and foci are (\u00b15,0)
\nAnswer:
\n<\/p>\n
\nMatch the following.\u00a0(IMP-2014)<\/span>
\n
\nAnswer:
\n<\/p>\n
\ni) Find the equation of the parabola with focus (6,0) and equation of the directrix is x = – 6.\u00a0(MARCH-2017)<\/span>
\nii) Find the coordinate of the foci, vertices, the length of transverse axis, conjugate axis and eccentricity of the hyperbola \\(\\frac{x^{2}}{16}-\\frac{y^{2}}{9}=1\\)
\n(MARCH -2017)
\nAnswer:
\n<\/p>\nPlus One Maths Chapter Wise Previous Questions and Answer<\/a><\/h4>\n","protected":false},"excerpt":{"rendered":"