\n<\/td>\n | Maximum available time 10 hrs\/day<\/td>\n | Maximum available time 15 hrs\/day<\/td>\n | <\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n i) Write the objective function. \nii) Whether it is a maximization case or a minimization case. Justify. \niii) Write the constraints. \nAnswer: \nLet x units = Machine G and y units = Machine H \ni) Objective function: Z = 20x + 30y \nii) It is a maximization problem. \niii) Constraints are: \n3x + 4y \u2264 10; 5x + 6y \u2264 15; x, y \u2265 0<\/p>\n Questions 8 to 17 carry 4 scores each. Answer any 8 questions. (8 \u00d7 4 = 32)<\/span><\/p>\nQuestion 8. \ni) A function f : A \u2192 B, where A = {1, 2, 3} and B = {4, 5, 6} defined by f(1) = 5, f(2) = 6, f(3) = 4, Check whether f is a bijection. If it is a bijection, write f-1<\/sup> as set of ordered pair. \nii) The operation table for an operation * is given below. Given that 1 is the identity element. Then which among the following is true regarding the element in the first column?<\/p>\n\n\n\n*<\/td>\n | 1<\/td>\n | 2<\/td>\n | 3<\/td>\n<\/tr>\n | \n1<\/td>\n | <\/td>\n | 2<\/td>\n | 3<\/td>\n<\/tr>\n | \n2<\/td>\n | <\/td>\n | 2<\/td>\n | 3<\/td>\n<\/tr>\n | \n3<\/td>\n | <\/td>\n | 3<\/td>\n | 3<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n a) 3, 2, 2 \nb) 1, 2, 3 \nc) 1, 1, 2 \nd) 2, 2, 2 \nCheck whether * is commutative. \nAnswer: \ni) A = {1, 2, 3}; B = {4, 5, 6} \nf(1) = 5, f(2) = 6, f(3) = 4 \nHence f= {(1, 5),(2, 6),(3, 4)} \nf-1<\/sup> = {(5, 1), (6, 2), (4, 3)} \nii) b) 1, 2, 3 \nSince; 1*2 = 2 and 2*1 =2 \n3 * 2 = 3 and 2*3 = 3 \nTherefore * is commutative<\/p>\nQuestion 9. \ni) If Sin-1<\/sup> x = y, then \n(a) 0 \u2264 y \u2264 \u03c0 \nb) \\(-\\frac{\\pi}{2}\\) \u2264 y \u2264 \\(\\frac{\\pi}{2}\\) \nc) 0 < y < \u03c0 \nd) \\(-\\frac{\\pi}{2}\\) \u2264 y \u2264 \\(\\frac{\\pi}{2}\\) \nii) Find the principal value of sin-1<\/sup>\u00a0(\\(\\frac{1}{2}\\)) \niii) sin-1<\/sup>x = \\(\\frac{3}{4}\\) find the value of cos-1<\/sup> x \nAnswer: \ni) \\(-\\frac{\\pi}{2}\\) \u2264 y \u2264 \\(\\frac{\\pi}{2}\\) \nii) sin-1<\/sup> \\(\\frac{1}{2}\\) = \\(\\frac{\\pi}{6}\\) \niii) sin-1<\/sup>x + cos-1<\/sup>x = \\(\\frac{\\pi}{2}\\) \n\\(\\frac{3}{4}\\) + cos-1<\/sup>x = \\(\\frac{\\pi}{2}\\) \u21d2 cos-1<\/sup>x = \\(\\frac{\\pi}{2}\\) – \\(\\frac{3}{4}\\)<\/p>\nQuestion 10. \ni) Find the relation between \u2018a\u2019 and \u2018b\u2019 so that the function defined by \nf(x) = \\(\\left\\{\\begin{array}{ll} \na x+1, & x \\leq 3 \\\\ \nb x+3, & x>3 \n\\end{array}\\right.\\) is continuous at x = 3 \nii) \u201cAll continuous function are not differentiable.\u201d Justify your answer with an example. \nAnswer: \ni) Since f(x) is continuous at x = 3 \n\\(\\lim _{x \\rightarrow 3^{-}}\\) f(x) = \\(\\lim _{x \\rightarrow 3^{+}}\\) f(x) = f(3) \n\\(\\lim _{x \\rightarrow 3}\\) (ax + 1) = \\(\\lim _{x \\rightarrow 3}\\) (bx + 3) = 3a +1 \n\u21d2 3a + 1 = 3b + 3 = 3a +1 \n\u21d2 3a + l = 3b + 3 \u21d2 3a – 3b – 2 = 0<\/p>\n ii) Consider the function f(x) = |x|. \nLet us check the continuity and differentiability at x = 0. \n \nLeft derivative * Right derivative \nTherefore not differentiable at x = 0.<\/p>\n Question 11. \ni) Find the equation to the tangent to the curve y = x2<\/sup> – 2x + 7 at (2, 7) \nii) Find the maximum value of the function? \nAnswer: \nf(x) = sin x + cos x, 0 < x < \\(\\frac{\\pi}{2}\\) \ni) y = x2<\/sup> – 2x + 7 \u21d2 \\(\\frac{d y}{d x}\\) = 2x – 2 \nSlope at x = 2 is 2 \u00d7 2 – 2 – 2 \nEquation of the tangent is \n(y – y1<\/sub>) = m(x – x1<\/sub>) \n\u21d2 (y – 7) = 2(x- 2) \n\u21d2 y – 7 = 2x – 4 \n\u21d2 2x – y + 3 = 0<\/p>\nii) c) f(x) = sin x + cos x \nf'(x) = cos x – sin x \nf”(x) = -sinx-cosx \nFor turning points; \nf'(x) = cos x – sin x = 0 \u21d2 tan x = 1 \n<\/p>\n Question 12. \nIntegrate \\(\\int \\frac{x+2}{2 x^{2}+6 x+5} d x\\) \nAnswer: \nPut x + 2 = A(4x + 6) + B \n4A = 1 \u21d2 A = \\(\\frac{1}{4}\\) \n \n<\/p>\n Question 13. \nConsider the differential equation \nx \\(\\frac{d y}{d x}\\) + y = \\(\\frac{1}{x^{2}}\\) \ni) Find the integrating factor. \nii) Solve the above differential equation. \nAnswer: \n<\/p>\n Question 14. \nlf the vectors \\(\\overline{P Q}\\) = -3i + 4j + 4k and \\(\\overline{P R}\\) = -5i + 2j + 4k are the sides of a \u0394PQR \ni) Find the angle between \\(\\overline{P Q}\\) and \\(\\overline{P R}\\) \nii) Find the length of the median through the vertex P. \nAnswer: \n \nii) \n \nWith respect to the initial P the position vector of Q and R will be \\(\\overline{P Q}\\) = -3i + 4j + 4k \nand \\(\\overline{P R}\\) = -5i + 2j + 4k respectively. \nSince M is the midpoint of QR. The position vector of M will be \n<\/p>\n Question 15. \ni) If \\(\\bar{a}\\) = 5i – j – 3k and \\(\\bar{b}\\) = i + 3j + 5k, then show that the vectors \\(\\bar{a}+\\bar{b}, \\bar{a}-\\bar{b}\\) are perpendicular. \nii) If \\(\\bar{a}\\) = i – 2j + 3k, \\(\\bar{b}\\) = 2i + 3j – 4k and \n\\(\\bar{c}\\) = i – 3j + 5k, then check whether \\(\\bar{a}\\), \\(\\bar{b}\\), \\(\\bar{c}\\) are coplanar. \nAnswer: \n<\/p>\n Question 16. \ni) Find the Cartesian equation of the line passing through origin and (5, -2, 3) ii) The point P(x, y, z) lies in the first octant and its distance from the origin is 12 units. If the position vector of P makes angles 45\u00b0, 60\u00b0with x and y axes respectively, find coordinates of P. \nAnswer: \n \nSince P lies in the first octant, we take n = \\(\\frac{1}{2}\\) \nTherefore the coordinate of P is \n<\/p>\n Question 17. \nSolve graphically Maximise Z = 5x + 3y Subject to the constraints 3x + 5y \u2264 15; 5x + 2y \u2264 10; x \u2265 0, y \u2265 0. \nAnswer: \nIn the figure the shaded region OABC is the fesible region. Here the region is bounded. \nThe corner points are \nO(0, 0), A(2, 0), B(\\(\\frac{20}{19}, \\frac{45}{19})\\), C(0, 3) \n \nGiven Z = 5x + 3y<\/p>\n \n\n\nCorner points<\/td>\n | Value of Z<\/td>\n<\/tr>\n | \nO<\/td>\n | Z = 0<\/td>\n<\/tr>\n | \nA<\/td>\n | Z = 5(2) + 3(0) = 10<\/td>\n<\/tr>\n | \nB<\/td>\n | Z = \\(5\\left(\\frac{20}{19}\\right)+3\\left(\\frac{45}{19}\\right)=\\frac{235}{19}\\)<\/td>\n<\/tr>\n | \nC<\/td>\n | Z = 5(0) + 3(3) = 9<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n Since maximum value of Z occurs at B, the soluion is z = \\(\\frac{235}{19}\\), (\\(\\frac{20}{19}\\), \\(\\frac{45}{19}\\))<\/p>\n Questions 18 to 24 carry 6 scores each. Answer any 5 questions. (5 \u00d7 6 = 30)<\/span><\/p>\nQuestion 18. \nA = \\(\\left[\\begin{array}{ccc} \n3 & 3 & -1 \\\\ \n-2 & -2 & 1 \\\\ \n-4 & -5 & 2 \n\\end{array}\\right]\\) \na) Find AT<\/sup> \nb) Express A as the sum of a symmetric and skew symmetric matrix. \nii) If AT<\/sup> = \\(\\left[\\begin{array}{cc} \n\\cos x & \\sin x \\\\ \n-\\sin x & \\cos x \n\\end{array}\\right]\\), verift that AT<\/sup> A = I \nAnswer: \n \n \n<\/p>\nQuestion 19. \ni) Without expanding prove that \n\\(\\left|\\begin{array}{ccc} \nx+y & y+z & z+x \\\\ \nz & x & y \\\\ \n1 & 1 & 1 \n\\end{array}\\right|\\) = 0 \nii) Consider the following system of equations \n2x – 3y + 5z = 11; 3x + 2y – 4z = -5; x + y – 2z = -3 \na) Express the system in Ax = B form. \nb) Solve the system by matrix method. \nAnswer: \n \n<\/p>\n Question 20. \nFind \\(\\frac{d y}{d x}\\) of the following \ni) x2<\/sup> + 2xy + 2y2<\/sup> = 1 \nii) yx<\/sup> = 2x<\/sup> \niii) x = cos \u03b8; y = sin \u03b8 at \u03b8 = \\(\\frac{\\pi}{4}\\) \nAnswer: \ni) x2<\/sup> + 2xy + 2y2<\/sup> = 1 \nDifferentiating w.r.to x; \n<\/p>\nii) yx<\/sup> = 2x<\/sup> \nTake log on both sides; \nx log y = x log 2 \nDifferentiating w.r.to x; \n<\/p>\nQuestion 21. \nEvaluate the following \n \nAnswer: \n \n \n<\/p>\n Question 22. \nConsider the parabolas y2<\/sup> = 4x, x2<\/sup> = 4y \ni) Draw a rough figure for the above parabolas. \nii) Find the point of intersection of the two parabolas. \niii) Find the area bounded by these two parabolas. \nAnswer: \n \nii) solving the two conics we get the point of intersection as (0, 0) and (4, 4). \niii) Area of the enclosed region \n<\/p>\nQuestion 23. \ni) Find the shortest distance between the lines whose vector equations are \n\\(\\bar{r}\\) = (i + 2j + 3k) + \u03bb(i – 3j + 2k) and \\(\\bar{r}\\) =(4i + 5j + 6k) + \u03bc(i – 3j + 2k) \nii) If a plane meets positive x axis at a distance of 2 units from the origin, positive y axis at a distance of 3 units from the origin and positive z axis at a distance of 4 units from the origin. Find the equation of the plane. \niii) Find the perpendicular distance of (0, 0, 0) from the plane obtained in part (ii) \nAnswer: \ni) \\(\\overline{a_{1}}\\) = i + 2j + 3k; \\(\\bar{b}\\) = i – 3j + 2k \n\\(\\overline{a_{2}}\\) = 4i + 5j + 6k Both lines are parallel. \n \n<\/p>\n Question 24. \ni) A die is thrown twice let the event A be ‘odd number on first throw’ and B be ‘odd number on the second throw’ check whether A and B are independent. \nii) Coloured balls are distributed in three boxes as shown in the following table:<\/p>\n \n\n\nBox<\/td>\n | Red<\/td>\n | Black<\/td>\n<\/tr>\n | \n1<\/td>\n | 2<\/td>\n | 0<\/td>\n<\/tr>\n | \nII<\/td>\n | 0<\/td>\n | 2<\/td>\n<\/tr>\n | \nIII<\/td>\n | 1<\/td>\n | 1<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n A box is selected at random and a ball is taken out. If the ball taken is of red colour, What is the probability that the other ball in the box is also of red colour? \nAnswer: \ni) n(S) = 36 \nA = {(1, 1), (1, 2), (1, 3), (1, 4), (1, 5), (1, 6), (3, 1), (3, 2), (3, 3), (3, 4), (3, 5), (3, 6), (5, 1), (5, 2), (5, 3), (5, 4), (5, 5), (5, 6)} \nB = {(1, 1), (2, 1), (3, 1), (4, 1), (5, 1), (6, 1), (1, 3), (2, 3), (3, 3), (4, 3), (5, 3), (6, 3), (1, 5), (2, 5), (3,5), (4, 5), (5, 5), (6, 5)} \n(A \u2229 B) = {(1, 1), (1, 3), (1, 5), (3, 1), (3, 3), (3, 5), (5, 1), (5, 3), (5, 5)} \n \nTherefore A and B are independent.<\/p>\n ii) Let B1<\/sub>, B2<\/sub>, B3<\/sub> are the event of getting the boxes. \nP(B1<\/sub>) = P(B2<\/sub>) = P(B3<\/sub>) = \\(\\frac{1}{3}\\) \nLet E be the event of getting a red ball. \n<\/p>\n | | | |