Time Allowed: 2\u00a0hours<\/span> General Instructions to Candidates:<\/span><\/p>\n Part – A<\/span><\/p>\n Answer all questions from 1 to 5. Each carries 1 score. (5 \u00d7 1 = 5)<\/span><\/p>\n Question 1. Question 2. Question 3. Question 4. Question 5. Part – B<\/span><\/p>\n Answer 9 questions from 6 to 16. Each carries 2 scores each. (9 \u00d7 2 = 18)<\/span><\/p>\n Question 6. Question 7. Question 8. Question 9. Question 10. Question 11. Question 12. unsigned int(2 bytes), int(4 bytes),long (4 bytes), unsigned long (4 bytes), float(4 bytes), double(8 bytes), long double(10 bytes)<\/p>\n Question 13. Question 14. Question 15. Question 16. Part – C<\/span><\/p>\n Answer any 9 questions from 17 to 27. Each carries 3 scores each. (9 \u00d7 3 = 27)<\/span><\/p>\n Question 17. 2) To find the value Y, i.e. decimal equivalent, multiply each digit by its corresponding weightage and simply sum it up. 3) To find the value Z, i.e. octal equivalent, divide the binary number into groups of 3 bits and write down the corresponding octal equivalent. Question 18. e-waste disposal methods:<\/p>\n Question 19. Question 20. Question 21. Question 22. b) header files: A header file is a prestored file that helps to use some operators and functions. To write C++ programs the header files are must.<\/p>\n Following are the header files<\/p>\n c) The main function: The main function is the first function which is invoked at the time of execution and the program ends within main(). The other functions are invoke from main().<\/p>\n Question 23. Question 24. Question 25.
\nCool off time: 15 Minutes<\/span>
\nMaximum Marks: 60<\/span><\/p>\n\n
\nThe least Significant Digit (LSD) of (1234.56)10<\/sub> is
\nAnswer:
\n6<\/p>\n
\nThe process of detecting and correcting errors in a program is called …………
\nAnswer:
\nDebugging<\/p>\n
\nName any two keywords in C++.
\nAnswer:
\nint, float<\/p>\n
\nThe memory size required for void data type is ………..
\nAnswer:
\n0<\/p>\n
\nRewrite the expression a = a + 1 using an arithmetic assignment operator.
\nAnswer:
\na+=1 or a++ or ++a.<\/p>\n
\nFind the octal and hexadecimal equivalent of (111101)2<\/sub>.
\nAnswer:
\n(75)8<\/sub>
\n(3D)16<\/sub><\/p>\n
\nWrite short note on any two utility softwares.
\nAnswer:
\nUtilities: Utilities are programs which are designed to assist computer for its smooth functioning. The utilities are given below:<\/p>\n\n
\nRedraw the following flow chart by correcting mistakes.
\n![\"Plus](\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/Plus-One-Computer-Application-Model-Question-Paper-1-1.png\")
\nAnswer:
\n![\"Plus](\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/Plus-One-Computer-Application-Model-Question-Paper-1-2.png\")
<\/p>\n
\nClassify the following into valid and invalid literals and give reason for invalid literals.
\n33,000+410. 5.6E82
\nAnswer:
\n33,000 – Invalid since comma cannot be allowed.
\n+410 – Invalid since real part missing.
\n5.6E – Invalid since exponent part missing.
\n82 – Valid<\/p>\n
\nConsider a = 5 and b = 2 and find the result of the following expressions.
\na) a>b
\nb) a! = b&&b>a
\nAnswer:
\na) a> b = 5 > 2
\nIt returns true
\nb) a!=b && b>a
\n5!=2 && 2>5
\ntrue && false
\nso It returns false.<\/p>\n
\nWrite short note on any two statements in C++.
\nAnswer:
\nStatements: Statements are smallest executable unit of a programming language. Each and every statement must be end with semicolon(;).
\n1. Declaration statement: Each and every variable must be declared before using it.
\nEg: int age;
\n2. Assignment,statements: Assignment operator is used to assign the value of RHS to LHS.
\nEg: X=100;
\n3. Input statements: lnput(>>) operator is used to perform input operation.
\nEg. cin>>n;
\n4. Output statements: output(<<) operator is used to perform output operation.
\nEg: cout<<n;<\/p>\n
\nBriefly explain type promotion with suitable example.
\nAnswer:
\nImplicit type conversion-: This is performed by C++ compiler internally. C++ converts all the lower sized data type to the highest sized operand. It is known as type promotion. Data types are arranged lower size to higher size is as follows.<\/p>\n
\nWrite the equivalent switch statement for the following.
\nIf (ch= = \u2018P\u2019)
\ncout<<\u201cPass\u2019\u201d
\nelse If (ch= =\u2018F\u2019)
\ncout<<\u201cFailed\u201d;
\nAnswer:
\nswitch(ch)
\n{
\ncase \u2018P\u2019:cout<<\u201cPass\u201d;
\nbreak;
\ncase \u2018F\u2019: cout<<\u201cFailed\u201d;
\n}<\/p>\n
\nDefine the terms given below.
\na) Bandwidth
\nb) Noise
\nAnswer:
\na) Bandwidth: The maximum amount of data that can be transmitted by the medium measured in Hertz.
\nb) Noise: It is the unwanted electrical or electro-magnetic interferences that adversely affect the transmitted data signals.<\/p>\n
\nName any four basic elements for data communication:
\nAnswer:
\nCommunication is the exchange of information between two human beings. But data communication is the exchange of, information between two computers (devices).<\/p>\n\n
\nWrite two advantages of Electronic Payment System (EPS).
\nAnswer:
\nElectronic Payment System (EPS): It is also called plastic money that is electronically exchange money between two individuals or firms (buyers and sellers) in an online environment.<\/p>\n
\nIf (X)16<\/sub> = (Y)10<\/sub> = (Z)8<\/sub> = (11111111 )2<\/sub> find the values of X, Yand Z.
\nAnswer:
\n1) To find the value X, i.e. hexadecimal equivalent, divide the binary number into groups of 4 bits and write down the corresponding hexadecimal equivalent.
\n![\"Plus](\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/Plus-One-Computer-Application-Model-Question-Paper-1-3.png\")
<\/p>\n
\n1*27<\/sup>+1*26<\/sup>+1*25<\/sup>+1*24<\/sup>+1*23<\/sup>+1*22<\/sup>+1*21<\/sup>+1*20<\/sup>
\n=128 + 64 + 32 + 16 + 8 + 4 + 2 + 1
\n= 255
\nHere Y = 255<\/p>\n
\n![\"Plus](\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/Plus-One-Computer-Application-Model-Question-Paper-1-4.png\")
<\/p>\n
\nWhat is e-waste? Explain any two e-waste disposal methods.
\nAnswer:
\ne-waste(electronic waste): It refers to the mal functioning electronic products such as faulty computers, mobile phones, tv sets, toys, CFL etc.<\/p>\n\n
\nWrite an algorithm to find the numbers from 1 to 10.
\nAnswer:
\nStep 1 : Start
\nStep 2 : Set i=1.
\nStep 3 : if i>10 go to Step 6
\nStep 4 : Print i.
\nStep 5 : Set i=i+1 go to Step 3.
\nStep 6 : Stop.<\/p>\n
\nExplain any two types of programming errors.
\nAnswer:
\nIn general there are two types of errors syntax errors and logical errors. When the rules or syntax of the language are not followed then syntax errors occurred and it is displayed after compilation. When the logic of a program is wrong then logical errors occurred and it is not displayed after compilation but it is displayed in the execution and testing phase.<\/p>\n
\nConsider the following diagram answer the question.
\n![\"Plus](\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/Plus-One-Computer-Application-Model-Question-Paper-1-5.png\")
\nWrite the base address (L-value), content (R-value) and Name of variable.
\nAnswer:
\nBase address (L-value) – 3000
\nContent (R-value) – 105
\nName of variable – NUM<\/p>\n
\nWrite short notes on:
\na) Preprocessor directive
\nb) Header file
\nc) Main () function
\nAnswer:
\na) Preprocessor directives: A C++ program starts with the preprocessor directive i.e., # include, #define, #undef, etc, are such a preprocessor directives. By using #include we can link the header files that are needed to use the functions. By using #define we can define some constants. Eg. #define x 100.<\/p>\n\n
\nWhat is the use of type modifiers in C++? List any four type modifiers.
\nAnswer:
\nType modifiers: With the help of type modifiers we can change the sign and range of data with same size. The important modifiers are signed, unsigned, long and short.<\/p>\n
\nWrite a C++ program to input an integer and check whether it is positive, negative or zero.
\nAnswer:
\n#include<iostream>
\nusing namespace std;
\nint main()
\n{
\nint n;
\ncout<<\u201cEnter a number\u201d;
\ncin>>n;
\nif(n>0)
\ncout<<\u201cThe number is positive\u201d;
\nelse if(n<0)
\ncout<<n<<\u201cThe number is negative\u201d;
\nelse
\ncout<<n<<\u201cThe number is zero\u201d;
\n}<\/p>\n
\nCompare Dial-up connection and wired broadband connection.
\nAnswer:<\/p>\n