{"id":30835,"date":"2018-08-08T09:21:57","date_gmt":"2018-08-08T09:21:57","guid":{"rendered":"https:\/\/www.aplustopper.com\/?p=30835"},"modified":"2020-11-24T12:50:22","modified_gmt":"2020-11-24T07:20:22","slug":"ml-aggarwal-class-9-solutions-for-icse-maths-chapter-7-quadratic-equations","status":"publish","type":"post","link":"https:\/\/www.aplustopper.com\/ml-aggarwal-class-9-solutions-for-icse-maths-chapter-7-quadratic-equations\/","title":{"rendered":"ML Aggarwal Class 9 Solutions for ICSE Maths Chapter 7 Quadratic Equations"},"content":{"rendered":"
Question 1.<\/strong><\/span> Question 2.<\/strong><\/span> Question 3.<\/strong><\/span> Question 4.<\/strong><\/span> Question 5.<\/strong><\/span> Question 6.<\/strong><\/span> Question 7.<\/strong><\/span> Question 8.<\/strong><\/span> Question 9.<\/strong><\/span> Question 10.<\/strong><\/span> Question 11.<\/strong><\/span> Question 12.<\/strong><\/span> Multiple Choice Questions<\/strong><\/span><\/p>\n Choose the correct Solution from the given four options (1 to 5):<\/strong> Question 2.<\/strong><\/span> Question 3.<\/strong><\/span> Question 4.<\/strong><\/span> Question 5.<\/strong><\/span> Chapter Test<\/strong><\/span><\/p>\n Solve the following (1 to 3) equations :<\/strong> Question 2.<\/strong><\/span> Question 3.<\/strong><\/span> <\/p>\n","protected":false},"excerpt":{"rendered":" ML Aggarwal Class 9 Solutions for ICSE Maths Chapter 7 Quadratic Equations Question 1. Solve the following (1 to 12) equations: (i) x\u00b2 – 11x + 30 = 0 (ii) 4x\u00b2 -25 = 0 Solution: Question 2. (i) 2x\u00b2 – 5x = 0 (ii) x\u00b2 – 2x = 48 Solution: Question 3. (i) 6 + […]<\/p>\n","protected":false},"author":9,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_genesis_hide_title":false,"_genesis_hide_breadcrumbs":false,"_genesis_hide_singular_image":false,"_genesis_hide_footer_widgets":false,"_genesis_custom_body_class":"","_genesis_custom_post_class":"","_genesis_layout":"","footnotes":""},"categories":[3034],"tags":[],"yoast_head":"\n
\nSolve the following (1 to 12) equations:<\/strong>
\n(i) x\u00b2 – 11x + 30 = 0<\/strong>
\n(ii) 4x\u00b2 -25 = 0<\/strong>
\nSolution:<\/strong><\/span>
\n<\/p>\n
\n(i) 2x\u00b2 – 5x = 0<\/strong>
\n(ii) x\u00b2 – 2x = 48<\/strong>
\nSolution:<\/strong><\/span>
\n
\n<\/p>\n
\n(i) 6 + x = x\u00b2<\/strong>
\n(ii) 2x\u00b2 + 3x + 1= 0<\/strong>
\nSolution:<\/strong><\/span>
\n<\/p>\n
\n(i) 3x\u00b2 = 2x + 8<\/strong>
\n(ii) 4x\u00b2 + 15 = 16x<\/strong>
\nSolution:<\/strong><\/span>
\n
\n<\/p>\n
\n(i) x (2x + 5) = 25<\/strong>
\n(ii) (x +3) (x – 3) = 40<\/strong>
\nSolution:<\/strong><\/span>
\n
\n<\/p>\n
\n(i) (2x + 3) (x – 4) = 6<\/strong>
\n(ii) (3x + 1) (2x + 3) = 3<\/strong>
\nSolution:<\/strong><\/span>
\n
\n<\/p>\n
\n(i) 4x\u00b2 + 4x + 1 = 0<\/strong>
\n(ii) (x – 4)\u00b2 + 5\u00b2= 132<\/strong>
\nSolution:<\/strong><\/span>
\n<\/p>\n
\n(i) 21x\u00b2 = 4(2x + 1)<\/strong>
\n(ii) \\(\\frac { 2 }{ 3 }\\) x2 – \\(\\frac { 1 }{ 3 }\\) x – 1 = 0<\/strong>
\nSolution:<\/strong><\/span>
\n
\n<\/p>\n
\n(i) 6x + 29 = \\(\\frac { 5 }{ x }\\)<\/strong>
\n(ii) x + \\(\\frac { 1 }{ x }\\) = 2 \\(\\frac { 1 }{ 2 }\\)<\/strong>
\nSolution:<\/strong><\/span>
\n
\n<\/p>\n
\n
\nSolution:<\/strong><\/span>
\n
\n<\/p>\n
\n
\nSolution:<\/strong><\/span>
\n
\n<\/p>\n
\n
\nSolution:<\/strong><\/span>
\n
\n
\n<\/p>\n
\nQuestion 1.<\/strong><\/span>
\nWhich of the following is not a quadratic equation :<\/strong>
\n(a) 2x\u00b2 = 3x – 5<\/strong>
\n(b) (2x- 1) (x- 1) = 2x\u00b2 – 7x + 2<\/strong>
\n(c) (2x – 1) (x + 2) = (x – 1) (x + 1)<\/strong>
\n(d) (x+ 1), = x, + 2x+2<\/strong>
\nSolution:<\/strong><\/span>
\n(2x – 1) (x – 1) = 2x\u00b2 – 7x + 2 is not a quadratic equation. (b)<\/strong><\/p>\n
\nIf 2 is a root of the quadratic equation 2x\u00b2 – kx + 1 = 0, then the value of k is<\/strong>
\n
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nIf -3 is a root of the quadratic equation kx\u00b2 + 2x – 3 = 0, then the value of k is<\/strong>
\n(a) 1<\/strong>
\n(b) -1<\/strong>
\n(c) \\(\\frac { 1 }{ 9 }\\)<\/strong>
\n(d) \\(\\frac { 1 }{ -9 }\\)<\/strong>
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nWhich of the following quadratic equations has -1 as a root?<\/strong>
\n(a) x\u00b2 + 5x + 6 = 0<\/strong>
\n(b) 2x\u00b2 – 3x + 1 = 0<\/strong>
\n(c) 2x\u00b2 + x – 3 = 0<\/strong>
\n(d) 2x\u00b2 – x – 3 = 0<\/strong>
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nThe root of the quadratic equation x\u00b2 – 3x – 4 = 0 are<\/strong>
\n(a) -4, 1<\/strong>
\n(b) 4, -1<\/strong>
\n(c) 4, 1<\/strong>
\n(d) -4, -1<\/strong>
\nSolution:<\/strong><\/span>
\n<\/p>\n
\nQuestion 1.<\/strong><\/span>
\n(i) x(2x+ 5) = 3<\/strong>
\n(ii) 3x\u00b2 – 4x – 4 = 0<\/strong>
\nSolution:<\/strong><\/span>
\n
\n<\/p>\n
\n(i) 4x\u00b2 – 2x + \\(\\frac { 1 }{ 4 }\\) = 0<\/strong>
\n(ii) 2x\u00b2 + 7x + 6 = 0<\/strong>
\nSolution:<\/strong><\/span>
\n
\n<\/p>\n
\n
\nSolution:<\/strong><\/span>
\n
\n
\n<\/p>\n