{"id":30509,"date":"2019-01-16T11:19:05","date_gmt":"2019-01-16T11:19:05","guid":{"rendered":"https:\/\/www.aplustopper.com\/?p=30509"},"modified":"2020-11-27T15:57:50","modified_gmt":"2020-11-27T10:27:50","slug":"ncert-solutions-for-class-10-maths-chapter-8","status":"publish","type":"post","link":"https:\/\/www.aplustopper.com\/ncert-solutions-for-class-10-maths-chapter-8\/","title":{"rendered":"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1"},"content":{"rendered":"<p>NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1 are part of NCERT Solutions for Class 10 Maths. Here are we have given Chapter 8 <strong>Introduction to Trigonometry\u00a0Class 10 NCERT Solutions Ex 8.1.<\/strong><\/p>\n<p>Here you get the CBSE Class 10 Mathematics chapter 8, Introduction to Trigonometry and its Applications: We are provides free comprehensive chapter wise class 10 Mathematics notes with proper images &amp; diagram. Here you will find all the answers to the NCERT textbook questions of Chapter 8 Introduction to Trigonometry.<\/p>\n<ul>\n<li><a title=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.2\" href=\"https:\/\/www.aplustopper.com\/ncert-solutions-for-class-10-maths-chapter-8-ex-8-2\/\" target=\"_blank\" rel=\"noopener\">Introduction to Trigonometry Class 10 Ex 8.2<\/a><\/li>\n<li><a title=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.3\" href=\"https:\/\/www.aplustopper.com\/ncert-solutions-for-class-10-maths-chapter-8-ex-8-3\/\" target=\"_blank\" rel=\"noopener\">Introduction to Trigonometry Class 10 Ex 8.3<\/a><\/li>\n<li><a title=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.4\" href=\"https:\/\/www.aplustopper.com\/ncert-solutions-for-class-10-maths-chapter-8-ex-8-4\/\" target=\"_blank\" rel=\"noopener\">Introduction to Trigonometry Class 10 Ex 8.4<\/a><\/li>\n<\/ul>\n<table style=\"table-layout: fixed; width: 650px;\" border=\"1\">\n<tbody>\n<tr>\n<td><strong>Board<\/strong><\/td>\n<td>CBSE<\/td>\n<\/tr>\n<tr>\n<td><strong>Textbook<\/strong><\/td>\n<td>NCERT<\/td>\n<\/tr>\n<tr>\n<td><strong>Class<\/strong><\/td>\n<td>Class 10<\/td>\n<\/tr>\n<tr>\n<td><strong>Subject<\/strong><\/td>\n<td>Maths<\/td>\n<\/tr>\n<tr>\n<td><strong>Chapter<\/strong><\/td>\n<td>Chapter 8<\/td>\n<\/tr>\n<tr>\n<td><strong>Chapter Name<\/strong><\/td>\n<td>Introduction to Trigonometry<\/td>\n<\/tr>\n<tr>\n<td><strong>Exercise<\/strong><\/td>\n<td>Ex 8.1<\/td>\n<\/tr>\n<tr>\n<td><strong>Number of Questions Solved<\/strong><\/td>\n<td>11<\/td>\n<\/tr>\n<tr>\n<td><strong>Category<\/strong><\/td>\n<td>NCERT Solutions<\/td>\n<\/tr>\n<\/tbody>\n<\/table>\n<h2>NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1<\/h2>\n<p><a class=\"button-red\" href=\"https:\/\/www.aplustopper.com\/ncert-solutions-for-class-10-maths\/\">NCERT Solutions for Class 10 Maths<\/a><\/p>\n<p>Page No: 181<\/p>\n<p><strong>Question 1.<\/strong><br \/>\nIn \u0394 ABC, right-angled at B, AB = 24 cm, BC = 7 cm. Determine :<br \/>\n(i) sin A, cos A<br \/>\n(ii) sin C, cos C<\/p>\n<p><strong>Solution:<br \/>\n<\/strong>In \u2206ABC by applying Pythagoras theorem<br \/>\nAC<sup>2<\/sup>\u00a0= AB<sup>2<\/sup>\u00a0+ BC<sup>2<\/sup><br \/>\n= (24)<sup>2<\/sup>\u00a0+ (7)<sup>2<\/sup><br \/>\n= 576 + 49<br \/>\n= 625<br \/>\nAC = \u221a625\u00a0= 25 cm<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-101422\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 8\" width=\"316\" height=\"507\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8.png 316w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-187x300.png 187w\" sizes=\"(max-width: 316px) 100vw, 316px\" \/><\/p>\n<p><strong>Question 2.<\/strong> In Figure, find tan P \u2013 cot R.<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-101423\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-2.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry 2\" width=\"289\" height=\"149\" \/><br \/>\n<strong>Solution:<br \/>\n<\/strong>In\u00a0 \u2206PQR by applying Pythagoras theorem<br \/>\nPR<sup>2<\/sup> = PQ<sup>2<\/sup> + QR<sup>2<\/sup><br \/>\n(13)<sup>2<\/sup> = (12)<sup>2<\/sup> + QR<sup>2<\/sup><br \/>\n169 = 144 + QR<sup>2<\/sup><br \/>\n25 = QR<sup>2<\/sup><br \/>\nQR = 5<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-101424\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-3.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry 3\" width=\"257\" height=\"376\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-3.png 257w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-3-205x300.png 205w\" sizes=\"(max-width: 257px) 100vw, 257px\" \/><\/p>\n<p><strong>Question 3.<\/strong> If sin A =3\/4, calculate cos A and tan A.<\/p>\n<p><strong>Solution:<br \/>\n<\/strong>Let\u00a0 \u2206ABC be a right angled triangle, right angled at point B.<br \/>\nGiven that<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-101426\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-5.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry 5\" width=\"388\" height=\"158\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-5.png 388w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-5-300x122.png 300w\" sizes=\"(max-width: 388px) 100vw, 388px\" \/><br \/>\nsin A = 3\/4<br \/>\nBC\/AC = 3\/4<br \/>\nLet BC be 3 K so AC will be 4 K where K \u00a1s a positive integer.<br \/>\nNow applying Pythagoras theorem in \u2206ABC<br \/>\nAC<sup>2<\/sup> = AB<sup>2<\/sup>\u00a0+ BC<sup>2<\/sup><br \/>\n(4 K)<sup>2<\/sup> = AB<sup>2<\/sup>\u00a0+ (3 K)<sup>2<\/sup><br \/>\n16 K<sup>2<\/sup> &#8211; g K<sup>2<\/sup> = AB<sup>2<\/sup><br \/>\n7 K<sup>2<\/sup> = AB<sup>2<\/sup><br \/>\nAB =\u00a0\u221a7k<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-101434\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-4.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry 4\" width=\"242\" height=\"163\" \/><\/p>\n<p><strong>Question 4.<\/strong><br \/>\nGiven 15 cot A = 8, find sin A and sec A.<\/p>\n<p><strong>Solution:<br \/>\n<\/strong>Consider a right triangle, right angled at B<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-101435\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-6.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry 6\" width=\"333\" height=\"365\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-6.png 333w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-6-274x300.png 274w\" sizes=\"(max-width: 333px) 100vw, 333px\" \/><br \/>\nLet AB be 8 K so BC will be 15 K where K is a positive integer.<br \/>\nNow applying Pythagoras theorem in \u2206ABC<br \/>\nAC<sup>2<\/sup> = AB<sup>2<\/sup> + BC<sup>2<\/sup><br \/>\n= (8K)<sup>2<\/sup> + (15K)<sup>2<\/sup><br \/>\n= 64 K<sup>2<\/sup> + 225 K<sup>2<\/sup><br \/>\n= 289 K<sup>2<\/sup><br \/>\nAC = 17 K<br \/>\n<strong><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-101436\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-7.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry 7\" width=\"236\" height=\"160\" \/><\/strong><\/p>\n<p><strong>Question 5.<\/strong> Given sec \u03b8 = 13\/12, calculate all other trigonometric ratios.<\/p>\n<p><strong>Solution:<br \/>\n<\/strong>Consider a right angle triangle\u00a0\u2206ABC right angled at point B.<strong><br \/>\n<\/strong><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-101438\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-8.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry 8\" width=\"409\" height=\"329\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-8.png 409w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-8-300x241.png 300w\" sizes=\"(max-width: 409px) 100vw, 409px\" \/><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-101439\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-9.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry 9\" width=\"333\" height=\"283\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-9.png 333w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-9-300x255.png 300w\" sizes=\"(max-width: 333px) 100vw, 333px\" \/><\/p>\n<p><strong>Question 6.<\/strong><br \/>\nIf \u2220A and \u2220B are acute angles such that cos A = cos B, then show that \u2220A = \u2220B.<\/p>\n<p><strong>Solution:<br \/>\n<\/strong>Since cos A = cos B<br \/>\nSo AB\/AC = BC\/AC<br \/>\nAB = BC<br \/>\nSo \u2220A = \u2220B (Angles opposite to equal sides are equal in length)<\/p>\n<p><strong>Question 7.<\/strong> If cot \u03b8 =7\/8, evaluate :<br \/>\n(i) \\(\\frac { \\left( 1+sin\\theta \\right) \\left( 1-sin\\theta \\right) }{ \\left( 1+cos\\theta \\right) \\left( 1-cos\\theta \\right) } \\)<br \/>\n(ii) Cot<sup>2<\/sup>\u03b8<\/p>\n<p><strong>Solution:<br \/>\n<\/strong>Consider a right angle triangle\u00a0\u2206ABC right angled at point B.<strong><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-101441\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-10.gif\" alt=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry 10\" width=\"462\" height=\"890\" \/><br \/>\n<\/strong><\/p>\n<p><strong>Question 8.<\/strong> If 3cot A = 4\/3 , check whether \\(\\frac { 1-tan^{ 2 }A }{ 1+tan^{ 2 }A } ={ cos }^{ 2 }A-{ sin }^{ 2 }A\\)\u00a0or not.<\/p>\n<p><strong>Solution:<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-101443\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-11.gif\" alt=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry 11\" width=\"418\" height=\"1006\" \/><br \/>\n<\/strong><\/p>\n<p><strong>Question 9.<\/strong> In triangle ABC, right-angled at B, if tan A =1\/\u221a3 find the value of:<br \/>\n(i) sin A cos C + cos A sin C<br \/>\n(ii) cos A cos C \u2013 sin A sin C<\/p>\n<p><strong>Solution:<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-101445\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-12.gif\" alt=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry 12\" width=\"396\" height=\"739\" \/><br \/>\n<\/strong><\/p>\n<p><strong>Question 10.<\/strong> In \u0394 PQR, right-angled at Q, PR + QR = 25 cm and PQ = 5 cm. Determine the values of sin P, cos P and tan P.<\/p>\n<p><strong>Solution:<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-101448\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-13.gif\" alt=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry 13\" width=\"376\" height=\"529\" \/><br \/>\n<\/strong><\/p>\n<p><strong>Question 11.<\/strong> State whether the following are true or false. Justify your answer.<br \/>\n(i) The value of tan A is always less than 1.<br \/>\n(ii) sec A = 12\/5 for some value of angle A.<br \/>\n(iii) cos A is the abbreviation used for the cosecant of angle A.<br \/>\n(iv) cot A is the product of cot and A.<br \/>\n(v) sin \u03b8 = 4\/3 for some angle \u03b8.<\/p>\n<p><strong>Solution:<br \/>\n<\/strong><img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-101453\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-14.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry 14\" width=\"268\" height=\"436\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-14.png 268w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-14-184x300.png 184w\" sizes=\"(max-width: 268px) 100vw, 268px\" \/><br \/>\nLet AC be 12 K, AB will be 5 K, where K is a positive integer<br \/>\nNow applying Pythagoras theorem in \u2206ABC<br \/>\nAC<sup>2<\/sup> = AB<sup>2<\/sup> + BC<sup>2<\/sup><br \/>\n(12 K)<sup>2<\/sup> = (5 K)<sup>2<\/sup> + BC<sup>2<\/sup><br \/>\n144 K<sup>2<\/sup> = 25 K<sup>2<\/sup>\u00a0+ BC<sup>2<\/sup><br \/>\nBC<sup>2<\/sup> = 119 K<sup>2<\/sup><br \/>\nBC = 109 K<br \/>\nWe may observe that for given two sides AC = 12 K and AB = S K<br \/>\nBC should be such that &#8211;<br \/>\nAC &#8211; AB &lt; BC &lt; AC + AB<br \/>\n12 K &#8211; 5 K &lt; BC &lt;12 K + 5 K<br \/>\n7 K &lt; BC &lt; 17 K<br \/>\nBut BC = 10.9 K.<br \/>\nClearly such a triangle is possible and hence such value of sec A is possible. Hence, the given statement is true.<\/p>\n<p>(iii) Abbreviation used for cosecant of angle A is cosec A. And cos A is the abbreviation used for cosine of angle A. Hence, the given statement is false.<\/p>\n<p>(iv) cot A is not the product of cot and A but it is cotangent of \u2220A. Hence, the given statement is false.<\/p>\n<p>(v) sine \u03b8 = 4\/3<br \/>\nWe know that in a right angle triangle<br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-101454\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2019\/01\/NCERT-Solutions-for-Class-10-Maths-Chapter-8-Introduction-to-Trigonometry-15.png\" alt=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry 15\" width=\"202\" height=\"42\" \/><br \/>\nIn a right angle triangle hypotenuse is always greater then the remaining two sides.<br \/>\nHence such value of sin\u00a0\u03b8 is not possible. Hence, the given statement is false.<\/p>\n<p>We hope the NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1 help you. If you have any query regarding NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1, drop a comment below and we will get back to you at the earliest.<\/p>\n<blockquote class=\"twitter-tweet\" data-width=\"500\" data-dnt=\"true\">\n<p lang=\"en\" dir=\"ltr\">NCERT Solutions For Class 10 Maths &#8211; AplusTopper<a href=\"https:\/\/t.co\/q7hSKh3xmf\">https:\/\/t.co\/q7hSKh3xmf<\/a><a href=\"https:\/\/twitter.com\/hashtag\/NCERTSolutionsForClass10Maths?src=hash&amp;ref_src=twsrc%5Etfw\">#NCERTSolutionsForClass10Maths<\/a> <a href=\"https:\/\/twitter.com\/hashtag\/NCERTSolutions?src=hash&amp;ref_src=twsrc%5Etfw\">#NCERTSolutions<\/a> <a href=\"https:\/\/twitter.com\/hashtag\/AplusTopper?src=hash&amp;ref_src=twsrc%5Etfw\">#AplusTopper<\/a><\/p>\n<p>&mdash; ObulReddy cbse (@ObulReddyCBSE) <a href=\"https:\/\/twitter.com\/ObulReddyCBSE\/status\/1025279827379535872?ref_src=twsrc%5Etfw\">August 3, 2018<\/a><\/p><\/blockquote>\n<p><script async src=\"https:\/\/platform.twitter.com\/widgets.js\" charset=\"utf-8\"><\/script><\/p>\n<p>&nbsp;<\/p>\n","protected":false},"excerpt":{"rendered":"<p>NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1 are part of NCERT Solutions for Class 10 Maths. Here are we have given Chapter 8 Introduction to Trigonometry\u00a0Class 10 NCERT Solutions Ex 8.1. Here you get the CBSE Class 10 Mathematics chapter 8, Introduction to Trigonometry and its Applications: We are [&hellip;]<\/p>\n","protected":false},"author":7,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_genesis_hide_title":false,"_genesis_hide_breadcrumbs":false,"_genesis_hide_singular_image":false,"_genesis_hide_footer_widgets":false,"_genesis_custom_body_class":"","_genesis_custom_post_class":"","_genesis_layout":"","footnotes":""},"categories":[6805],"tags":[36685],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v17.8 (Yoast SEO v17.8) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1 - A Plus Topper.com<\/title>\n<meta name=\"description\" content=\"NCERT Solutions for Class 10 Maths Chapter 8 Introduction to Trigonometry Ex 8.1 helpful to finish your Home Work. 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