{"id":2946,"date":"2023-03-25T10:00:07","date_gmt":"2023-03-25T04:30:07","guid":{"rendered":"https:\/\/www.aplustopper.com\/?p=2946"},"modified":"2023-03-25T11:05:29","modified_gmt":"2023-03-25T05:35:29","slug":"properties-of-cyclic-quadrilaterals","status":"publish","type":"post","link":"https:\/\/www.aplustopper.com\/properties-of-cyclic-quadrilaterals\/","title":{"rendered":"What are the Properties of Cyclic Quadrilaterals?"},"content":{"rendered":"

What are the Properties of Cyclic Quadrilaterals?<\/h2>\n

Cyclic quadrilateral<\/h3>\n

If all four points of a quadrilateral<\/a> are on circle then it is called cyclic Quadrilateral.
\n\"WhatA quadrilateral PQRS is said to be cyclic quadrilateral<\/strong> if there exists a circle passing through all its four vertices P, Q, R and S.
\nLet a cyclic quadrilateral be such that
\nPQ = a, QR = b, RS = c and SP = d.
\n\"WhatThen \u2220Q + \u2220S = 180\u00b0, \u2220A + \u2220C = 180\u00b0
\nLet\u00a0 2s = a + b + c + d
\n\"What
\n(1) Circumradius of cyclic quadrilateral:<\/strong> Circum circle of quadrilateral PQRS is also the circumcircle of \u2206PQR.
\n\"What
\n(2) Ptolemy’s theorem:<\/strong> In a cyclic quadrilateral PQRS, the product of diagonals is equal to the sum of the products of the length of the opposite sides i.e., According to Ptolemy’s theorem, for a cyclic quadrilateral PQRS.
\nPR.QS = PQ.RS + RQ.PS.
\n\"What<\/p>\n

Properties of Cyclic Quadrilaterals<\/h3>\n

\"What<\/p>\n

Theorem: Sum of opposite angles is 180\u00ba (or opposite angles of cyclic quadrilateral is supplementary)<\/strong>
\n\"What
\nGiven : O is the centre of circle. ABCD is the cyclic quadrilateral.
\nTo prove : \u2220BAD + \u2220BCD = 180\u00b0, \u2220ABC + \u2220ADC = 180\u00b0
\nConstruction : Join OB and OD
\nProof:
\n(i) \u2220BAD = (\\(\\frac { 1 }{ 2 } \\))\u2220BOD.
\n(The angle substended by an arc at the centre is double the angle on the circle.)
\n(ii) \u2220BCD = (\\(\\frac { 1 }{ 2 } \\)) reflex \u2220BOD.
\n(iii) \u2220BAD + \u2220BCD = (\\(\\frac { 1 }{ 2 } \\))\u2220BOD + (\\(\\frac { 1 }{ 2 } \\)) reflex \u2220BOD.
\nAdd (i) and (ii).
\n\u2220BAD + \u2220BCD = (\\(\\frac { 1 }{ 2 } \\))(\u2220BOD + reflex \u2220BOD)
\n\u2220BAD + \u2220BCD = (\\(\\frac { 1 }{ 2 } \\)) \u00d7 (360\u00b0)
\n(Complete angle at the centre is 360\u00b0)
\n\u2220BAD + \u2220BCD = 180\u00b0
\n(iv) Similarly \u2220ABC + \u2220ADC = 180\u00b0.<\/p>\n