{"id":28528,"date":"2022-12-13T10:00:29","date_gmt":"2022-12-13T04:30:29","guid":{"rendered":"https:\/\/www.aplustopper.com\/?p=28528"},"modified":"2022-12-14T09:38:50","modified_gmt":"2022-12-14T04:08:50","slug":"algebra-1-common-core-answers-chapter-12-data-analysis-and-probability-exercise-12-2","status":"publish","type":"post","link":"https:\/\/www.aplustopper.com\/algebra-1-common-core-answers-chapter-12-data-analysis-and-probability-exercise-12-2\/","title":{"rendered":"Algebra 1 Common Core Answers\u00a0Chapter 12 Data Analysis and Probability Exercise 12.2"},"content":{"rendered":"

Algebra 1 Common Core Answers\u00a0Student Edition Grade 8 – 9 Chapter 12 Data Analysis and Probability Exercise 12.2<\/span><\/h2>\n

Algebra 1 Common Core Solutions<\/a><\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 1LC<\/strong>
\nGiven, the data shown below is the battery life, in hours for different brand of batteries
\n12 9 10 14 10 11 10 18 21 10 14 22
\nWe have to make a frequency table for the above data.
\nTo make frequency table first we find the number of interval and the size of interval which is reasonable for the given data The minimum data value is Q and the maximum data value is 22. so we chose the total interval length is 16 (we chose any value for the length of interval which is near to the difference between maximum and minimum data value) We divide 16 values into 4 intervals of size 4 These intervals are:
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 2LC<\/strong>
\nGiven, the data shown below is the battery life, in hours for different brand of batteries.
\n12 9 10 14 10 11 10 18 21 10 14 22
\nWe have to make Histogram of the above data
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 3LC<\/strong>
\nGiven. the data shown below is the battery life. in hours for different brand of batteries
\n12910141011101821101422
\nWe have to make a cumulative frequency table for the above data
\n\"Algebra
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 4LC<\/strong>
\n\"Algebra
\nThe Table 1 shows that the busiest hour for the store owner is 9-11 hour Thus we can say that frequency table helps to the store owner to determine its busiest business hour<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 5LC<\/strong>
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 6LC<\/strong>
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 7E<\/strong>
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 8E<\/strong>
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 9E<\/strong>
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 10E<\/strong>
\n\"Algebra
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 11E <\/strong>
\n\"Algebra
\n\"Algebra
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 12E<\/strong>
\n\"Algebra
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 13E<\/strong>
\n\"Algebra
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 14E<\/strong>
\n\"Algebra
\nFrom the above histogram we see that it has one peak this is not in the centre By the definition of skewed histogram. \u201cif the histogram has one peak that is not in center then the histogram is skewed\u201d. Thus the above histogram is skewed<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 15E<\/strong>
\n\"Algebra
\nFrom the above histogram we see that it has one peak this is not in the Centre. By the definition of skewed histogram. \u201cif the histogram has one peak that is not in center then the histogram is skewed\u201d Thus the above histogram is skewed.<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 16E<\/strong>
\n\"Algebra
\nFrom the above histogram we see that it has one peak this is not in the centre By the definition of skewed histogram, \u201cif the histogram has one peak that is not in center then the histogram is skewed\u201d. Thus the above histogram is skewed<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 17E<\/strong>
\n\"Algebra
\nFrom the above histogram we see that it has one peak this is not in the centre By the definition of skewed histogram, \u201cif the histogram has one peak that is not in center then the histogram is skewed\u201d. Thus the above histogram is skewed<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 18E<\/strong>
\n\"Algebra
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 19E<\/strong>
\n\"Algebra
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 20E<\/strong>
\n\"Algebra
\n\"Algebra
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 21E<\/strong>
\n\"Algebra
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 22E<\/strong>
\n\"Algebra
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 23E<\/strong>
\n\"Algebra
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 24E<\/strong>
\nGiven, that the set of data which shows test score;
\n81 70 73 89 68 79 91 59 77 73 80 75 88 65 82 94 77 67 82
\nWe have to make Histogram of the above data uses of interval 10.
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 25E<\/strong>
\nGiven, that the set of data which shows test score;
\n81 70 73 89 68 79 91 59 77 73 80 75 88 65 82 94 77 67 82
\nWe have to make Histogram of the above data uses of interval 20.
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 26E<\/strong>
\n\"Algebra
\n\"Algebra
\n\"Algebra
\nThe frequency table of all the three interval size shows that the interval size 20 makes a little variation in test score Since in the interval test score 59-78 the frequency is lo and in the interval of test score 79-98 the frequency is 9. Thus the interval size of 20 makes little variation in test score.<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 27E<\/strong>
\n\"Algebra
\nFrom the above histogram we see that the last interval of the histogram is 80-99, and in this interval there are 4 Customers. The maximum value of the 80-99 is 99 Thus the upper limit on the amount of money that any customer spent is $999.<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 28E<\/strong>
\n\"Algebra
\nFrom the above histogram we see that the last interval of the histogram is 80-99, and in this interval there are 4 Customers. The maximum value of the 80-99 is 99 Thus the upper limit on the amount of money that any customer spent is $999.<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 29E<\/strong>
\n\"Algebra
\nFrom the above histogram we see that there are 9 customers which spent less than $20 This is corresponding to the first interval that O-19. Thus 9 customers spent less than $20.<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 30E<\/strong>
\n\"Algebra
\nFrom the above histogram we see that there are 9 customers which correspond to the first interval O-19 spent less than $20. There are 15 customers which corresponds to the second interval 20-39 spent less than $40. There are 13 customers which is correspond to the first interval 40-59 spent less than $60, 9 customers which is correspond to the first interval 60-79 spent less than $80 and there are 4 customers which is correspond to the first interval 80-99 spent less than $100<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 31E<\/strong>
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 32E<\/strong>
\nGiven, that a set of data which has 200 data values We have to make a histogram that must have 40\u00b0\/b of the values lies in the interval 20-29 The remaining values should be evenly divided among the intervals 0-9, 10-19, 30-39, and 40-49.
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 33E<\/strong>
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 34E<\/strong>
\n\"Algebra
\nSolution:
\nFrom the above histogram we see that it has one peak which is not in the centre. By the definition of skewed histogram. \u201cif the histogram has one peak that is not in center then the histogram is skewed\u201d. Thus the above histogram is skewed Therefore the correct option is (C).
\nThe option (A) is not correct Because by the definition of symmetric histogram. \u201cif a vertical line can divide the histogram into two parts that are close to mirror images, then the histogram is symmetric\u201d. In the above histogram there is no any vertical line that divided histogram into two parts and each part is mirror image to other.
\nThe option (B) is not correct. Because only three type of histogram, symmetric, skewed and uniform.
\nThe option (D) is also not correct By the definition of a histogram, \u201cif the bars are roughly the same then histogram is uniform\u201d. Hence option (D) is not correct.<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 35E<\/strong>
\nQuestion:
\nWhat isthe solution of (\u20144x\u20146) + (6x+1)=I3?………. (1)
\n(F) \u20144 (G) 6 (H) 5 (I) 9
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 36E<\/strong>
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 37E<\/strong>
\n\"Algebra
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 38E<\/strong>
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 39E<\/strong>
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 40E<\/strong>
\n\"Algebra
\n\"Algebra<\/p>\n

Chapter 12 Data Analysis and Probability Exercise 12.2 41E<\/strong>
\nGiven the numbers,
\n0.9,-0.2,1.2,5,-1,0,0.1,2……………….. (1)
\nWe have to order the numbers from least to greatest
\nThe least number in a numbers given numbers is … since it is the most negative value number The second least number \u201402. third least number O. fourth least number 0.1 . fifth least number 0.9 sixth least number 1.2. seventh least number 2 and 5 is the greatest number
\nThus we arrange the given numbers as above, we get
\n-1,-0.2,0,0.1,O.9,1.2,2,5<\/p>\n","protected":false},"excerpt":{"rendered":"

Algebra 1 Common Core Answers\u00a0Student Edition Grade 8 – 9 Chapter 12 Data Analysis and Probability Exercise 12.2 Algebra 1 Common Core Solutions Chapter 12 Data Analysis and Probability Exercise 12.2 1LC Given, the data shown below is the battery life, in hours for different brand of batteries 12 9 10 14 10 11 10 […]<\/p>\n","protected":false},"author":5,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_genesis_hide_title":false,"_genesis_hide_breadcrumbs":false,"_genesis_hide_singular_image":false,"_genesis_hide_footer_widgets":false,"_genesis_custom_body_class":"","_genesis_custom_post_class":"","_genesis_layout":"","footnotes":""},"categories":[20593],"tags":[31959,20595,32374,31958,20597,20602,20594,20599,20600,20601,31956,31957],"yoast_head":"\nAlgebra 1 Common Core Answers\u00a0Chapter 12 Data Analysis and Probability Exercise 12.2 - A Plus Topper<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.aplustopper.com\/algebra-1-common-core-answers-chapter-12-data-analysis-and-probability-exercise-12-2\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Algebra 1 Common Core Answers\u00a0Chapter 12 Data Analysis and Probability Exercise 12.2\" \/>\n<meta property=\"og:description\" content=\"Algebra 1 Common Core Answers\u00a0Student Edition Grade 8 – 9 Chapter 12 Data Analysis and Probability Exercise 12.2 Algebra 1 Common Core Solutions Chapter 12 Data Analysis and Probability Exercise 12.2 1LC Given, the data shown below is the battery life, in hours for different brand of batteries 12 9 10 14 10 11 10 […]\" \/>\n<meta property=\"og:url\" content=\"https:\/\/www.aplustopper.com\/algebra-1-common-core-answers-chapter-12-data-analysis-and-probability-exercise-12-2\/\" \/>\n<meta property=\"og:site_name\" content=\"A Plus Topper\" \/>\n<meta property=\"article:publisher\" content=\"https:\/\/www.facebook.com\/aplustopper\/\" \/>\n<meta property=\"article:published_time\" content=\"2022-12-13T04:30:29+00:00\" \/>\n<meta property=\"article:modified_time\" content=\"2022-12-14T04:08:50+00:00\" \/>\n<meta property=\"og:image\" content=\"https:\/\/farm1.staticflickr.com\/927\/42369156414_0c4554e4b9_o.png\" \/>\n<meta name=\"twitter:card\" content=\"summary\" \/>\n<meta name=\"twitter:label1\" content=\"Written by\" \/>\n\t<meta name=\"twitter:data1\" content=\"Prasanna\" \/>\n\t<meta name=\"twitter:label2\" content=\"Est. reading time\" \/>\n\t<meta name=\"twitter:data2\" content=\"6 minutes\" \/>\n<script type=\"application\/ld+json\" class=\"yoast-schema-graph\">{\"@context\":\"https:\/\/schema.org\",\"@graph\":[{\"@type\":\"Organization\",\"@id\":\"https:\/\/www.aplustopper.com\/#organization\",\"name\":\"Aplus Topper\",\"url\":\"https:\/\/www.aplustopper.com\/\",\"sameAs\":[\"https:\/\/www.facebook.com\/aplustopper\/\"],\"logo\":{\"@type\":\"ImageObject\",\"@id\":\"https:\/\/www.aplustopper.com\/#logo\",\"inLanguage\":\"en-US\",\"url\":\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/12\/Aplus_380x90-logo.jpg\",\"contentUrl\":\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/12\/Aplus_380x90-logo.jpg\",\"width\":1585,\"height\":375,\"caption\":\"Aplus Topper\"},\"image\":{\"@id\":\"https:\/\/www.aplustopper.com\/#logo\"}},{\"@type\":\"WebSite\",\"@id\":\"https:\/\/www.aplustopper.com\/#website\",\"url\":\"https:\/\/www.aplustopper.com\/\",\"name\":\"A Plus Topper\",\"description\":\"Improve your Grades\",\"publisher\":{\"@id\":\"https:\/\/www.aplustopper.com\/#organization\"},\"potentialAction\":[{\"@type\":\"SearchAction\",\"target\":{\"@type\":\"EntryPoint\",\"urlTemplate\":\"https:\/\/www.aplustopper.com\/?s={search_term_string}\"},\"query-input\":\"required name=search_term_string\"}],\"inLanguage\":\"en-US\"},{\"@type\":\"ImageObject\",\"@id\":\"https:\/\/www.aplustopper.com\/algebra-1-common-core-answers-chapter-12-data-analysis-and-probability-exercise-12-2\/#primaryimage\",\"inLanguage\":\"en-US\",\"url\":\"https:\/\/farm1.staticflickr.com\/927\/42369156414_0c4554e4b9_o.png\",\"contentUrl\":\"https:\/\/farm1.staticflickr.com\/927\/42369156414_0c4554e4b9_o.png\"},{\"@type\":\"WebPage\",\"@id\":\"https:\/\/www.aplustopper.com\/algebra-1-common-core-answers-chapter-12-data-analysis-and-probability-exercise-12-2\/#webpage\",\"url\":\"https:\/\/www.aplustopper.com\/algebra-1-common-core-answers-chapter-12-data-analysis-and-probability-exercise-12-2\/\",\"name\":\"Algebra 1 Common Core Answers\\u00a0Chapter 12 Data Analysis and Probability Exercise 12.2 - 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