{"id":19331,"date":"2018-01-29T06:48:35","date_gmt":"2018-01-29T06:48:35","guid":{"rendered":"https:\/\/www.aplustopper.com\/?p=19331"},"modified":"2020-11-24T09:55:29","modified_gmt":"2020-11-24T04:25:29","slug":"frank-icse-solutions-class-9-physics-fluids","status":"publish","type":"post","link":"https:\/\/www.aplustopper.com\/frank-icse-solutions-class-9-physics-fluids\/","title":{"rendered":"Frank ICSE Solutions for Class 9 Physics &#8211; Fluids"},"content":{"rendered":"<h2><span style=\"color: #00ccff;\"><strong>Frank ICSE Solutions for Class 9 Physics &#8211; Fluids<\/strong><\/span><\/h2>\n<p><span style=\"color: #00ccff;\"><strong>PAGE NO: 157<\/strong><\/span><br \/>\n<span style=\"color: #eb4924;\"><strong>Solution 1:<\/strong><\/span><br \/>\nThe thrust on the unit surface is known as pressure. The SI unit of pressure is Nm<sup>-2<\/sup>.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 2:<\/strong><\/span><br \/>\nPressure is given by<br \/>\nP = h X<sub>p<\/sub> X<sub>g<\/sub>.<br \/>\nWhere h is height of liquid column, p is density of liquid, g is acceleration due to gravity.<br \/>\nDensity of mercury is = 1.36 x 10<sup>4<\/sup> kg\/m<sup>3<\/sup>.<br \/>\nh= height of mercury column which is given = 75 cm = 0.75 m.<br \/>\nSo pressure = 0.75 x 1.36 x 104 x 9.8 = 9.996 x 10<sup>4<\/sup>Nm<sup>-2<\/sup>.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 3:<\/strong><\/span><br \/>\nPressure is a scalar physical quantity.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 4:<\/strong><\/span><br \/>\nOne pascal is defined as the pressure exerted on a surface of area 1 m<sup>2<\/sup> by a force of 1 Newton acting normally on the surface.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 5:<\/strong><\/span><br \/>\nThe force acting normally on a surface is known as thrust.<br \/>\nSI unit of thrust is N.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 6:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83926\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-1.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 1\" width=\"561\" height=\"458\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-1.png 561w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-1-300x245.png 300w\" sizes=\"(max-width: 561px) 100vw, 561px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 7:<\/strong><\/span><br \/>\nWater can&#8217;t be used in place of mercury in a barometer because of its low density. It would require 10.34 m long tube to measure 1 atmospheric pressure which is not practically possible while mercury having high density (13.6 g\/cc) would require only 0.76 m long pipe which is practically possible.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 8:<\/strong><\/span><br \/>\nPressure is the physical quantity which is measured in bar.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 9:<\/strong><\/span><br \/>\nThrust is a vector quantity.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 10:<\/strong><\/span><br \/>\nThrust on a surface is the force acting normally on a surface while pressure on a surface is thrust acting on the unit area of a surface.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 11:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83927\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-2.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 2\" width=\"628\" height=\"434\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-2.png 628w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-2-300x207.png 300w\" sizes=\"(max-width: 628px) 100vw, 628px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 12:<\/strong><\/span><br \/>\nLake has greater pressure at the bottom than the surface as pressure increases with depth. So when gas bubble is released at the bottom of the lake it experiences more pressure and is small in size but as it rises upwards the pressure experienced by it decreases. So it grows in size as it moves towards the surface from bottom.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 13:<\/strong><\/span><br \/>\nA dam has broader walls at the bottom than at the top because the pressure exerted by a liquid increases with its depth, and at any point at a particular depth liquid pressure is same in all directions. Now as more pressure is exerted by water on the wall of the dam as depth increases. Hence a thick wall is constructed at the bottom of dam to withstand greater pressure.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 14:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83928\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-3.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 3\" width=\"551\" height=\"378\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-3.png 551w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-3-300x206.png 300w\" sizes=\"(max-width: 551px) 100vw, 551px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 15:<\/strong><\/span><br \/>\nThe pressure at a point in a liquid depends upon on the following three factors:<\/p>\n<ul>\n<li>It depends on the point below the free surface (h).<\/li>\n<li>It depends on density of liquid (p).<\/li>\n<li>It depends upon acceleration due to gravity (g) of the place.<\/li>\n<\/ul>\n<p><span style=\"color: #eb4924;\"><strong>Solution 16:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83930\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-4.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 4\" width=\"689\" height=\"179\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-4.png 689w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-4-300x78.png 300w\" sizes=\"(max-width: 689px) 100vw, 689px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 17:<\/strong><\/span><br \/>\nA substance having a tendency to flow is called fluid.<br \/>\nA fluid exerts pressure on the bottom due to its weight and on the walls of the container in which it is enclosed by virtue of its ability to flow. This is called fluid pressure.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 18:<\/strong><\/span><br \/>\nThe laws of liquid pressure are<\/p>\n<ul>\n<li>Pressure inside the liquid increases with the depth from the free surface of the liquid.<\/li>\n<li>Pressure is same at all points on a horizontal plane, in case of a stationary liquid.<\/li>\n<li>Pressure is same in all directions about a point inside the liquid.<\/li>\n<li>Pressure at same depth is different in different liquids. It increases with the increase in the density of the liquid.<\/li>\n<li>A liquid will always seek its own level.<\/li>\n<\/ul>\n<p><span style=\"color: #eb4924;\"><strong>Solution 19:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83933\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-5.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 5\" width=\"650\" height=\"135\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-5.png 650w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-5-300x62.png 300w\" sizes=\"(max-width: 650px) 100vw, 650px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 20:<\/strong><\/span><br \/>\nA diving suit is a garment or device designed to protect a diver from the underwater environment.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 21:<\/strong><\/span><br \/>\nThere are five main types of ambient pressure suits. These are wetsuits, drysuits, semidry suits, dive skins etc.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 22:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83935\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-6.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 6\" width=\"518\" height=\"267\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-6.png 518w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-6-300x155.png 300w\" sizes=\"(max-width: 518px) 100vw, 518px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 23:<\/strong><\/span><br \/>\nManometer is a simple pressure gauge that measures differences in pressure at the two ends of the apparatus.<br \/>\nManometer is a U shaped tube containing water whose one limb is dipped in vessel and vessel is tightly covered with plastic sheet. U shaped tube has two limbs one towards the vessel and other is opened to atmosphere.<br \/>\nNow if level of water toward atmospheric open limb is more than level of water in limb towards apparatus end then liquid is said to be at higher pressure than atmosphere. And if level of water toward atmospheric open limb is less than level of water in limb towards apparatus end then liquid is said to be at lower pressure than atmospheric pressure.<\/p>\n<p><span style=\"color: #00ccff;\"><strong>PAGE NO : 158<\/strong><\/span><br \/>\n<span style=\"color: #eb4924;\"><strong>Solution 24:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83936\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-7.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 7\" width=\"477\" height=\"277\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-7.png 477w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-7-300x174.png 300w\" sizes=\"(max-width: 477px) 100vw, 477px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 25:<\/strong><\/span><br \/>\nA hydraulic press works on the principle of pascal&#8217;s law. A hydraulic press can be used for extracting juice of sugarcane, sugar beet etc.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 28:<\/strong><\/span><br \/>\nPascal&#8217;s law states that pressure applied to an enclosed liquid, is transmitted equally to every part of the liquid or in other words when pressure is applied at a point in a confined fluid, it is transmitted undiminished and equally in all directions throughout the liquid.<br \/>\nHydraulic machines such as hydraulic press, hydraulic brakes and hydraulic jack are application of pascal&#8217;s law.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 29:<\/strong><\/span><br \/>\nAltimeter is a device which is used in an aircraft to measure its altitude.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 30:<\/strong><\/span><br \/>\nAtmospheric pressure decreases with increase in height. our atmosphere comprises of a large number of parallel layers. The pressure on a layer is equal to the thrust or weight of the gaseous column on the unit area of that layer. Hence, as we go up, the weight of the gaseous column decreases, which decrease the pressure of the gaseous column.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 31:<\/strong><\/span><br \/>\nAneroid means containing no liquid and aneroid barometer is evacuated so it tends to collapse under the pressure of air. The stout spring balances the thrust on the metal box due to normal air pressure and prevents the box from collapsing. As this type of barometer doesn&#8217;t contain any liquid so it got its name aneroid barometer.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 32:<\/strong><\/span><br \/>\nBarometer is a device which is used for measuring atmospheric pressure. Barometers are used in weather forecasting and in measuring altitudes.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 33:<\/strong><\/span><br \/>\nMercury is used in barometer because<\/p>\n<ul>\n<li>It can be obtained in pure form.<\/li>\n<li>It does not vaporizeat ordinary temperatures.<\/li>\n<li>Its density is high and hence the length of the mercury column supported by atmospheric pressure is 76 cm which is practically possible.<\/li>\n<\/ul>\n<p><span style=\"color: #00ccff;\"><strong>PAGE NO: 173<\/strong><\/span><br \/>\n<span style=\"color: #eb4924;\"><strong>Solution 1:<\/strong><\/span><br \/>\nAll liquid exerts an upward force on the body placed in it. This Phenomenon is called buoyancy.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 2:<\/strong><\/span><br \/>\nThe upward force which any liquid exerts upon a body placed in it is called the upthrust. The SI unit of upthrust is N.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 3:<\/strong><\/span><br \/>\nBuoyant force act on a body in upward direction.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 4:<\/strong><\/span><br \/>\nUpthrust is defined as the upward force on the object provided by the liquid because the object has displaced some of the fluid.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 5:<\/strong><\/span><br \/>\nWhen block of cork is immersed in water buoyant force acts on it in upward direction so to overcome this force we have to apply an equal force in downward direction to keep block of cork inside water.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 6:<\/strong><\/span><br \/>\nWood has density less than water so volume of water displaced by it is more than the volume of wooden block submerged so force of upthrust is greater than the weight of wood which pushes wooden block on the surface. Hence, a piece of wood when left under water again comes to the surface.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 7:<\/strong><\/span><br \/>\nA body will weigh more in air as weight of body acts in downward direction and there is no force in upward direction while body submerged in water weigh less because an upthrust act on the body in upward direction so the resultant weight of the body decreases.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 8:<\/strong><\/span><br \/>\nUpthrust or buoyant force depends on the following factors:<\/p>\n<ul>\n<li>Volume of body submerged in the liquid.<\/li>\n<li>Density of the liquid.<\/li>\n<li>Acceleration due to gravity.<\/li>\n<\/ul>\n<p><span style=\"color: #eb4924;\"><strong>Solution 9:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83937\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-8.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 8\" width=\"556\" height=\"427\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-8.png 556w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-8-300x230.png 300w\" sizes=\"(max-width: 556px) 100vw, 556px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 10:<\/strong><\/span><br \/>\nWeight of the body in air = 300 gf.<br \/>\nApparent Weight of the completely immersed body in water = 280 gf.<\/p>\n<ul>\n<li>Loss in weight of the body = Weight of body in air &#8211; apparent weight of immersed body.<br \/>\nLoss in weight = 300 gf &#8211; -280 gf = 20 gf.<\/li>\n<li>As upthrust on the body = loss in weight<\/li>\n<li>So uptrust = 20 gf.<\/li>\n<\/ul>\n<p><span style=\"color: #eb4924;\"><strong>Solution 11:<\/strong><\/span><br \/>\nEdge of metal cube = 5 cm.<br \/>\nDensity of the metal cube = 9 gcm<sup>-3<\/sup>\u00a0= 9 x 10<sup>3<\/sup> kgm<sup>-3<\/sup>.<br \/>\nVolume of the metal cube = 125 cm<sup>3<\/sup> = 125 x 10<sup>-6<\/sup>\u00a0m<sup>3<\/sup>.<br \/>\nMass of the metal cube =9 x 10<sup>3<\/sup> x 125 x 10<sup>-6<\/sup>\u00a0= 1125 x 10<sup>-3<\/sup>\u00a0=1.125 kg.<br \/>\nWeight of the liquid = mass x gravity = 1.125 x 10 = 11.25 N.<br \/>\nDensity of liquid = 1.2 gcm<sup>-3<\/sup>= 1.2 x 10<sup>3<\/sup> kgm<sup>-3<\/sup>.<br \/>\nUpthrust of the liquid = V X<sub>p<\/sub> X<sub>g<\/sub>.<br \/>\nUpthrust = 125 x 10<sup>-6<\/sup>\u00a0x 1.2 x 10<sup>3<\/sup> x 10 = 1.5 N.<br \/>\nApparent weight of the body = weight of liquid &#8211; upthrust<br \/>\nApparent weight = 11.25 N &#8211; 1.5 N = 9.75 N<br \/>\nTension in the string is equal to the apparent weight of the body<br \/>\nSo, tension in string would be 9.75 N.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 12:<\/strong><\/span><br \/>\nIt is easier to lift a heavy stone under water because in water an upthrust acts on the upward direction which reduces the apparent weight of the stone and makes it easy to lift.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 13:<\/strong><\/span><br \/>\nPrinciple of Archimedes&#8217; states that when a body is totally or partially immersed in a fluid, it experiences an upthrust equal to the weight of the fluid displaced by it.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 14:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83962\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-9.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 9\" width=\"577\" height=\"767\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-9.png 577w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-9-226x300.png 226w\" sizes=\"(max-width: 577px) 100vw, 577px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 15:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83974\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-11.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 11\" width=\"645\" height=\"315\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-11.png 645w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-11-300x147.png 300w\" sizes=\"(max-width: 645px) 100vw, 645px\" \/><\/p>\n<p><span style=\"color: #00ccff;\"><strong>PAGE NO : 174<\/strong><\/span><br \/>\n<span style=\"color: #eb4924;\"><strong>Solution 16:<\/strong><\/span><br \/>\nWood has density less than water so volume of water displaced by it is more than the volume of wooden block submerged so force of upthrust is greater than the weight of wood which makes it float on the water surface. And the apparent weight of the piece of the wood would be zero.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 17:<\/strong><\/span><br \/>\nDensity of iron is less than the density of mercury so it will float on the surface of the mercury. Apparent weight of the floating iron ball is zero.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 18:<\/strong><\/span><br \/>\nIron nail has density less than that of mercury so it will float on the surface of mercury but in the case of water it will sink because the density of iron nail is more than that of water.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 19:<\/strong><\/span><br \/>\nNo, the relative density of a substance is the ratio of the density of the substance to the density of water at 4<sup>0<\/sup>C.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 20:<\/strong><\/span><\/p>\n<ul>\n<li>SI unit of buoyant force is N.<\/li>\n<li>SI unit of density is Kgm<sup>-3<\/sup>.<\/li>\n<li>SI unit of weight of body is N.<\/li>\n<li>Relative density is a pure ratio it has no dimension.<\/li>\n<\/ul>\n<p><span style=\"color: #eb4924;\"><strong>Solution 21:<\/strong><\/span><br \/>\nDensity of iron is more than the density of water so it sinks down in the water but in case of ship, it is design in such a manner that it encloses large quantity of air in air tight bags and in rooms and corridors which makes the average density of ship less than that of water and ship floats on the surface of the water.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 22:<\/strong><\/span><br \/>\nThe fractional part submerged equals the ratio of the density of the material of the block to the density of the liquid.<br \/>\n(Density of floating body \/ Density of liquid) = fraction submerged.<br \/>\nThe Fraction of ice submerged in water remain same as density of ice and water remain same during melting. As ice melts some volume of ice decrease and convert into water and volume of water increase by same amount. So, level of water remains same during melting.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 23:<\/strong><\/span><br \/>\nThe fractional part submerged equals the ratio of the density of the material of the block to the density of the liquid.<br \/>\n(Density of floating body \/ Density of liquid) = fraction submerged.<br \/>\nHeight of wooden piece = 15 cm.<br \/>\nHeight of wooden piece sinks in water = 10 cm.<br \/>\nFraction of wooden piece submerged in water = 10\/15 = 0.67.<br \/>\nAs liquid is water so ratio of Density of wooden by density of water gives relative density of floating wooden piece. So, relative density of wooden block is 0.67.<br \/>\nHeight of wooden piece = 15 cm.<br \/>\nHeight of wooden piece sinks in spirit = 12 cm.<br \/>\nFraction of wooden piece submerged in water = 12\/15 = 0.8.<br \/>\nWe know density of wooden piece = 0.67<br \/>\n(Density of floating body \/ Density of liquid) = fraction submerged.<br \/>\nDensity of liquid\/spirit = (Density of floating body \/fraction submerged)<br \/>\nDensity of liquid\/spirit = 0.67\/0.8 = 0.83.<br \/>\nRelative density of spirit is 0.83.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 24:<\/strong><\/span><\/p>\n<ul>\n<li>When a body is completely immersed in water then it displaces equal volume of water to its own weight. Volume of body of man is same in both river and sea so weight of water of sea displaced by him is equal to the weight of water of river displaced by him. And ratio of weights would be 1:1.<\/li>\n<li>Sea water contains mineral salts and density of sea water increase due to presence of these. As density of sea water is more than the normal water so it apply more buoyant force than usual one and a person find it easy to swim in sea water.<\/li>\n<\/ul>\n<p><span style=\"color: #eb4924;\"><strong>Solution 25:<\/strong><\/span><br \/>\nThe fractional part submerged equals the ratio of the density of the material of the block to the density of the liquid.<br \/>\n(Density of floating body \/ Density of liquid) = fraction submerged.<br \/>\nFraction of wooden piece submerged in water = 2\/3 = 0.67.<br \/>\nAs liquid is water so ratio of Density of wooden by density of water gives relative density of floating wooden piece.<br \/>\nSo, relative density of wooden block is 0.67.<br \/>\nDensity of water in SI system = 1000 Kg m<sup>-3<\/sup>.<br \/>\nDensity of wood=relative density x density of water =0.67 x 1000 Kg m<sup>-3<\/sup>\u00a0=670 kgm.<br \/>\nFraction of wooden piece submerged in oil = 3\/4 = 0.75.<br \/>\nWe know density of wooden piece = 0.67<br \/>\n(Density of floating body \/ Density of liquid) = fraction submerged.<br \/>\nRelative Density of oil = (Relative Density of wooden block\/fraction submerged)<br \/>\nDensity of oil = 0.67\/0.75 = 0.893.<br \/>\nDensity of water in SI system = 1000 Kg m<sup>-3<\/sup>.<br \/>\nDensity of oil =relative density x density of water =0.893 x 1000 Kg m<sup>-3<\/sup>\u00a0=893 kgm<sup>-3<\/sup>.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 26:<\/strong><\/span><br \/>\nRelative density of Ice = 0.92<br \/>\nRelative density of sea water = 1.025<br \/>\nLet total volume of iceberg = X cm<sup>3<\/sup>.<br \/>\nVolume of iceberg above water = 800 cm<sup>3<\/sup>.<br \/>\nVolume of iceberg in submerged in the water = (X &#8211; 800) cm<sup>3<\/sup>.<br \/>\nFraction of iceberg submerged = (X- 800)\/X<br \/>\nNow we know that fractional part submerged equals the ratio of the density of the material of the block to the density of the liquid.<br \/>\n(Density of ice \/ Density of sea water) = fraction submerged<br \/>\n0.92\/1.025 = (X-800)\/X<br \/>\n0.8975 X = X &#8211; 800<br \/>\nX &#8211; 0.8975 X = 800<br \/>\n0.1025 X = 800<br \/>\nX = 800\/0.1025 = 7804.8 cm<sup>3<\/sup>.<br \/>\nTotal volume of iceberg = 7804.8 cm<sup>3<\/sup>.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 27:<\/strong><\/span><br \/>\nRelative density of wax = 0.95<br \/>\nRelative density of brine = 1.1<br \/>\n(Density of wax\/ Density of brine) = fraction submerged<br \/>\n0.95\/1.1 = fraction of volume submerged<br \/>\nFraction of volume submerged = 0.86<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 28:<\/strong><\/span><br \/>\nRelative density of Ice = 0.9 cm<br \/>\nRelative density of sea water = 1.1 cm<br \/>\n(Density of ice \/ Density of sea water) = fraction submerged of iceberg<br \/>\n0.9\/1.1 = fraction of iceberg submerged<br \/>\nFraction of iceberg submerged = 9\/11.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 30:<\/strong><\/span><br \/>\nLactometer is commonly used for testing the purity of milk.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 31:<\/strong><\/span><br \/>\nDensity of water at 4<sup>0<\/sup>c in SI system is = 1000 Kgm<sup>-3<\/sup>.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 32:<\/strong><\/span><br \/>\nSide of wooden cube = 10 cm.<br \/>\nVolume of wooden cube = 10 x 10 x 10 = 1000 cm<sup>3<\/sup>.<br \/>\nMass of wooden cube = 700 g.<br \/>\nDensity of wooden cube = mass\/volume = 700\/1000 = 0.7 gcm<sup>-3<\/sup>.<br \/>\nDensity of water = 1 gcm<sup>-3<\/sup>.<br \/>\n(Density of floating body \/ Density of liquid) = fraction submerged<br \/>\n0.7\/1 =fraction submerged<br \/>\nFraction of wooden cube submerged in water = 0.7<br \/>\nHeight of wooden cube = 10 cm<br \/>\nPart of wooden cube which is submerged = 10 x 0.7 = 7 cm<br \/>\nSo, wooden cube will float in water with 3 cm height above the water surface.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 33:<\/strong><\/span><br \/>\nVolume of wooden block = 0.032 m<sup>3<\/sup>.<br \/>\nMass of wooden block = 24 Kg.<br \/>\nDensity of wooden block = mass\/volume = 24\/0.032 = 750 Kgm<sup>-3<\/sup>.<br \/>\nDensity of water = 1000 Kgm<sup>-3<\/sup>.<br \/>\n(Density of floating body \/ Density of liquid) = fraction submerged<br \/>\n750\/1000 =fraction submerged<br \/>\nFraction of wooden block submerged in water = 0.75<br \/>\nTotal volume of wooden block = 0.032 m<sup>3<\/sup>.<br \/>\nPart of volume of wooden block which is submerged = 0.032 x 0.75 = 0.024 m<sup>3<\/sup>.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 34:<\/strong><\/span><br \/>\nRelative density = density of substance \/density of water at 4<sup>0<\/sup>C.<br \/>\nAs relative density of platinum is 21.50, this means platinum is 21.5 times denser than water at 4<sup>0<\/sup>C.<\/p>\n<p><span style=\"color: #00ccff;\"><strong>PAGE NO : 175<\/strong><\/span><br \/>\n<span style=\"color: #eb4924;\"><strong>Solution 35:<\/strong><\/span><br \/>\nDensity of mercury = 13600 Kgm<sup>-3<\/sup>.<br \/>\nDensity of water at 4<sup>0<\/sup>C = 1000 kg m<sup>-3<\/sup>.<br \/>\nRelative density = density of substance \/density of water at 4<sup>0<\/sup>C.<br \/>\nRelative density of mercury = 13600 Kgm<sup>-3<\/sup>\/1000 kg m<sup>-3<\/sup>\u00a0= 13.6.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 36:<\/strong><\/span><br \/>\nvolume of body = 100 cm<sup>3<\/sup>.<br \/>\nWeight of body = 1 kgf = 1000 gf<br \/>\nMass of body= 1000 gm.<br \/>\nDensity of liquid = 1000 gm\/100cm<sup>3<\/sup> = 10 gcm<sup>3<\/sup>.<br \/>\nDensity of water at 4o = 1gcm<sup>-3<\/sup>.<br \/>\nRelative density = density of substance \/density of water at 4<sup>0<\/sup> C<br \/>\nRelative density = 10 gcm<sup>3<\/sup> \/1 gcm<sup>3<\/sup> = 10<br \/>\nMass of body= 1000 gm.<br \/>\nDensity of water = 1 gcm<sup>-3<\/sup><br \/>\nAcceleration due to gravity = 10 ms<sup>-2<\/sup>.<br \/>\nUpthrust = V X<sub>p<\/sub> X<sub>g<\/sub>.<br \/>\nUpthrust = 100 x 1 gf = 100 gf.<br \/>\nResultant weight of the body = weight &#8211; upthrust = 1000 gf &#8211; 100 gf = 900 gf.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 37:<\/strong><\/span><br \/>\nWhen a body is completely immersed in water then it displaces equal volume of water to its own weight.<br \/>\nSo, volume of body = 20000 cm<sup>3<\/sup>.<br \/>\nMass of body = 70 kg = 70000 gm<br \/>\nDensity of body = mass \/volume = 70000\/20000= 3.5 gm cm<sup>-3<\/sup>.<br \/>\nDensity of water in C.G.S system = 1g cm<sup>-3<\/sup>.<br \/>\nRelative density of body = density of body \/density of water =3.5 gm cm<sup>-3<\/sup>\/1g cm<sup>-3<\/sup>.<br \/>\nRelative density = 3.5.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 38:<\/strong><\/span><br \/>\nRelative density = density of mercury \/density of water.<br \/>\nDensity of mercury = relative density x density of water.<br \/>\nRelative density = 13.6.<br \/>\nDensity of water in C.G.S system = 1g cm<sup>-3<\/sup>.<br \/>\nSo, density of mercury in C.G.S system = 13.6 x 1 = 13.6 gcm<sup>-3<\/sup>.<br \/>\nDensity of water in SI system = 1000 Kg m<sup>-3<\/sup>.<br \/>\nSo, density of mercury in SI system = 13.6 x 1000 = 13.6 x 10<sup>3<\/sup> Kgcm<sup>-3<\/sup>.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 39:<\/strong><\/span><br \/>\nDensity of iron is = 7.8 x 10<sup>3<\/sup> Kg m<sup>-3<\/sup>.<br \/>\nDensity of water at 4<sup>0<\/sup>C = 10<sup>3<\/sup> Kg m<sup>-3<\/sup>.<br \/>\nRelative density of a substance is the ratio of the density of the substance to the density of water at 4<sup>0<\/sup>C.<br \/>\nSo, relative density of iron is = 7.8 x 10<sup>3<\/sup> Kg m<sup>-3<\/sup>\/103 Kg m<sup>-3<\/sup>\u00a0= 7.8<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 40:<\/strong><\/span><\/p>\n<ul>\n<li>Mass of a metallic piece remains unchanged with increase in temperature.<\/li>\n<li>Volume of metallic piece increases with increase in temperature.<\/li>\n<li>Density of metallic piece decreases with increases in temperature.<\/li>\n<\/ul>\n<p><span style=\"color: #eb4924;\"><strong>Solution 41:<\/strong><\/span><br \/>\nDensity of water decreases with the increase in temperature and increases with decreases in temperature.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 42:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83975\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-12.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 12\" width=\"340\" height=\"91\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-12.png 340w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-12-300x80.png 300w\" sizes=\"(max-width: 340px) 100vw, 340px\" \/><\/p>\n<p><span style=\"color: #00ccff;\"><strong>PAGE NO: 177<\/strong><\/span><br \/>\n<span style=\"color: #eb4924;\"><strong>Solution 1:<\/strong><\/span><br \/>\nAll liquid exerts a upward force on the body placed in it. This Phenomenon is called buoyancy.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 2:<\/strong><\/span><br \/>\nThe upward force which any liquid exerts upon a body placed in it is called the upthrust.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 3:<\/strong><\/span><br \/>\nPressure is a scalar quantity.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 4:<\/strong><\/span><br \/>\nThrust is a vector quantity.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 5:<\/strong><\/span><br \/>\nSI unit of density is Kgm<sup>-3<\/sup>.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 6:<\/strong><\/span><br \/>\nThe relative density of a substance is the ratio of the density of the substance to the density of water at 4<sup>0<\/sup>C.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 7:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83977\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-13.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 13\" width=\"493\" height=\"112\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-13.png 493w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-13-300x68.png 300w\" sizes=\"(max-width: 493px) 100vw, 493px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 8:<\/strong><\/span><br \/>\nPrinciple of Archimedes&#8217; states that when a body is totally or partially immersed in a fluid, it experiences an upthrust equal to the weight of the fluid displaced. Yes, it applies to gases also.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 9:<\/strong><\/span><br \/>\nThrust on a surface is the force acting normally on a surface while pressure on a surface is thrust acting on the unit area of a surface.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 10:<\/strong><\/span><br \/>\nPascal&#8217;s law states that pressure applied to an enclosed liquid, is transmitted equally to every part of the liquid or in other words when pressure is applied at a point in a confined fluid, it is transmitted undiminished and equally in all directions throughout the liquid.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 11:<\/strong><\/span><br \/>\nYes, all liquid exert pressure.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 12:<\/strong><\/span><br \/>\nHydraulic machines such as hydraulic press, hydraulic brakes and hydraulic jack are application of pascal&#8217;s law.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 13:<\/strong><\/span><br \/>\nPascal&#8217;s law is principle of hydraulic machines.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 14:<\/strong><\/span><br \/>\nBrahma press depends upon Pascal&#8217;s law.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 15:<\/strong><\/span><\/p>\n<ul>\n<li>A hydraulic press can be used for extracting juice of sugarcane, sugar beet etc.<\/li>\n<li>A hydraulic press can be used for pressing cotton bales, quilts, books etc.<\/li>\n<\/ul>\n<p><span style=\"color: #eb4924;\"><strong>Solution 16:<\/strong><\/span><br \/>\nAtmospheric point at any point in air at rest is equal to the weight of a vertical column of air on a unit area surrounding the point, the column extending to the top of atmosphere.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 17:<\/strong><\/span><br \/>\nAtmospheric pressure at sea level is about 10<sup>5<\/sup> N\/m<sup>2<\/sup>.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 18:<\/strong><\/span><br \/>\nBarometer is used for measuring the atmospheric pressure.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 19:<\/strong><\/span><br \/>\nAltimeter is a device which is used in an aircraft to measure its altitude.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 20:<\/strong><\/span><br \/>\nA falling barometer indicates the approach of rain or storm or both.<\/p>\n<p><span style=\"color: #00ccff;\"><strong>PAGE NO : 178<\/strong><\/span><br \/>\n<span style=\"color: #eb4924;\"><strong>Solution 21:<\/strong><\/span><br \/>\nA atmospheric pressure diving suit is a garment or device designed to protect a diver from the underwater environment. Yes, diving suits create buoyancy.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 23:<\/strong><\/span><br \/>\nA fluid exerts pressure on the bottom due to its weight and on the walls of the container in which it is enclosed by virtue of its ability to flow. This is called fluid pressure.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 24:<\/strong><\/span><br \/>\nA dam has broader walls at the bottom than at the top because the pressure exerted by a liquid increases with its depth, and at any point at a particular depth liquid pressure is same in all directions. Now as more pressure is exerted by water on the wall of the dam as depth increases. Hence a thick wall is constructed at the bottom of dam to withstand greater pressure.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 25:<\/strong><\/span><br \/>\nPascal&#8217;s law states that pressure applied to an enclosed liquid, is transmitted equally to every part of the liquid.<br \/>\nMeans when pressure is applied at a point in a confined fluid, it is transmitted undiminished and equally in all directions throughout the liquid.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 27:<\/strong><\/span><br \/>\nFactors which affect the atmospheric pressure as we go up are<\/p>\n<ul>\n<li>Weight of gaseous column.<\/li>\n<li>Density of gaseous column.<\/li>\n<\/ul>\n<p><span style=\"color: #eb4924;\"><strong>Solution 28:<\/strong><\/span><br \/>\nAtmospheric pressure decreases with increase in height. Our atmosphere comprises of a large number of parallel layers. The pressure on a layer is equal to the thrust or weight of the gaseous column on the unit area of that layer. Hence, as we go up, the weight of the gaseous column decreases, which decrease the pressure of the gaseous column.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 29:<\/strong><\/span><br \/>\nBarometer is a device used for measuring atmospheric pressure.<br \/>\nSimple barometer has two main defects<\/p>\n<ul>\n<li>It is not suitable for making accurate measurement of atmospheric pressure as any change in the level of mercury in the tube changes the level of the free surface of mercury is trough and fixed scale cannot be used with it.<\/li>\n<li>Simple barometer is not portable. So, it cannot be used by airmen, navigators, mountaineers, who need a portable barometer.<\/li>\n<\/ul>\n<p><span style=\"color: #eb4924;\"><strong>Solution 31:<\/strong><\/span><br \/>\nWe don&#8217;t feel uneasy even under enormous pressure of the atmosphere above us because our blood also exerts a pressure called blood pressure, which is greater than atmospheric pressure. So, there is balance between our blood pressure and atmospheric pressure.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 32:<\/strong><\/span><br \/>\nReading of a barometer would rise if it is taken to the mine as pressure increases with depth.<br \/>\nReading of a barometer would fall if it is taken to a hill as pressure decreases with increase in height.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 33:<\/strong><\/span><br \/>\nWeight of solid in air = 2.10 N<br \/>\nRelative density of solid = 8.4<br \/>\nNow, Relative density = weight of solid in air\/ loss of weight of solid in water.<br \/>\nLoss of weight of solid in water = weight of solid in air\/ Relative density.<br \/>\nLoss of weight of solid in water = 2.10\/8.4 = 0.25 N.<br \/>\nWeight of solid in water = weight in air &#8211; loss of weight in water<br \/>\nWeight of solid in water = 2.10 &#8211; 0.25 =1.85 N.<br \/>\nRelative density of liquid =1.2<br \/>\nWe know<br \/>\nRelative density of liquid = Loss of weight of solid in liquid\/loss of weight of solid in water.<br \/>\nLoss of weight of solid in liquid = Relative density x loss of weight of solid in water.<br \/>\nLoss of weight of solid in liquid = 1.2 x 0.25 = 0.3 N.<br \/>\nWeight of solid in liquid = weight of solid in air &#8211; loss of weight of solid in liquid.<br \/>\nWeight of solid in liquid = 2.10 &#8211; 0.3 = 1.8 N.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 34:<\/strong><\/span><br \/>\nDensity of iron is 7800Kgm<sup>-3<\/sup>.<br \/>\nThis means a cube of iron having side 1m would weigh 7800 Kg.<br \/>\nDensity of water at 4<sup>0<\/sup>C is 1000 Kgm<sup>-3<\/sup>.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 35:<\/strong><\/span><br \/>\nRelative density of body = 0.52<br \/>\nDensity of water at 4<sup>0<\/sup>C = 1000 Kgm<sup>-3<\/sup>.<br \/>\nDensity of body = 0.52 x 1000 Kgm<sup>-3<\/sup>= 520 Kgm<sup>-3<\/sup><br \/>\nWe know density = mass x volume.<br \/>\nMass = density x volume<br \/>\nMass = 520 x 2 =1040 Kg.<br \/>\nMass of given body is 1040 Kg.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 36:<\/strong><\/span><br \/>\nPiece of metal weighs in air = 44.5 f<br \/>\nPiece of metal weighs in liquid = 39.5 f.<br \/>\nLoss of weight of metal in liquid = 44.5 &#8211; 39.5 = 5f.<br \/>\nRelative density = weight of solid in air\/ loss of weight of solid in water.<br \/>\nRelative density of liquid =44.5f\/5f =8.9<br \/>\nRelative density of liquid = 8.9<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 37:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83981\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-14.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 14\" width=\"607\" height=\"435\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-14.png 607w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-14-300x215.png 300w\" sizes=\"(max-width: 607px) 100vw, 607px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 38:<\/strong><\/span><br \/>\nPrinciple of floatation states that a floatating body displaces an amount of fluid equal to its own weight.<br \/>\nShip is designed in such a manner that it encloses large quantity of air in air tight bags and in rooms and corridors which makes the average density of ship less than that of water.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 40:<\/strong><\/span><br \/>\nAcid battery hydrometer is used to check the concentration of sulphuric acid in an acid battery.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 41:<\/strong><\/span><br \/>\nIron nail has density less than that of mercury so it will float on the surface of mercury but in the case of water it will sink because the density of iron nail is more than that of water.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 43:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83982\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-15.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 15\" width=\"638\" height=\"648\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-15.png 638w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-15-295x300.png 295w\" sizes=\"(max-width: 638px) 100vw, 638px\" \/><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83983\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-16.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 16\" width=\"637\" height=\"622\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-16.png 637w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-16-300x293.png 300w\" sizes=\"(max-width: 637px) 100vw, 637px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 44:<\/strong><\/span><\/p>\n<ul>\n<li>A balloon filled with hydrogen has low density than air so it rises over the air but as height increases density of air decreases and at a certain height the density of hydrogen in balloon and density of air become equal. And as there is no density difference there is no pressure difference also and hence balloon stops rising further.<\/li>\n<li>Density of egg is greater than fresh water so it sinks in fresh water but due to addition of salt density of water increases which makes the density of salt water greater than egg and hence floats in a strong solution of salt.<\/li>\n<li>The bottom of the hydrometer is made heavier by loading it with lead shots so that it floats vertically with some of its portion outside the surface of water in the jar.<\/li>\n<li>Relative density of Ice is = 0.9 cm<sup>-3<\/sup><br \/>\nRelative density of sea water is = 1 cm<sup>-3<\/sup><br \/>\n(Density of ice \/ Density of sea water) = fraction submerged of iceberg<br \/>\n0.9\/1 = fraction of iceberg submerged<br \/>\nFraction of iceberg submerged = 9\/10.<\/li>\n<\/ul>\n<p>Thus in colder countries where there are icebergs in oceans, only about 1\/10 is seen above water and the remaining water 9\/10 remain submerged. Hence, there is danger of these icebergs to the ships sailing in these oceans.<\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 45:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83985\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-17.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 17\" width=\"640\" height=\"827\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-17.png 640w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-17-232x300.png 232w\" sizes=\"(max-width: 640px) 100vw, 640px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 46:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83987\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-18.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 18\" width=\"623\" height=\"643\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-18.png 623w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-18-291x300.png 291w\" sizes=\"(max-width: 623px) 100vw, 623px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 47:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-83988\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-19.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 19\" width=\"645\" height=\"785\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-19.png 645w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-19-246x300.png 246w\" sizes=\"(max-width: 645px) 100vw, 645px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 48:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-84000\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-20.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 20\" width=\"639\" height=\"759\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-20.png 639w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-20-253x300.png 253w\" sizes=\"(max-width: 639px) 100vw, 639px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 49:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-84001\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-21.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 21\" width=\"635\" height=\"530\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-21.png 635w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-21-300x250.png 300w\" sizes=\"(max-width: 635px) 100vw, 635px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 50:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-84002\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-22.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 22\" width=\"634\" height=\"698\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-22.png 634w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-22-272x300.png 272w\" sizes=\"(max-width: 634px) 100vw, 634px\" \/><\/p>\n<p><span style=\"color: #eb4924;\"><strong>Solution 51:<\/strong><\/span><br \/>\n<img loading=\"lazy\" decoding=\"async\" class=\"alignnone size-full wp-image-84004\" src=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-23.png\" alt=\"Frank ICSE Solutions for Class 9 Physics - Fluids 23\" width=\"637\" height=\"534\" srcset=\"https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-23.png 637w, https:\/\/www.aplustopper.com\/wp-content\/uploads\/2018\/01\/Frank-ICSE-Solutions-for-Class-9-Physics-Fluids-23-300x251.png 300w\" sizes=\"(max-width: 637px) 100vw, 637px\" \/><\/p>\n<p><a class=\"button-red\" title=\"FRANK ICSE Class 9 Physics Solutions\" href=\"https:\/\/www.aplustopper.com\/frank-icse-solutions-class-9-physics\/\">Physics<\/a><a class=\"button-blue\" title=\"FRANK ICSE Class 9 Chemistry Solutions\" href=\"https:\/\/www.aplustopper.com\/frank-icse-solutions-class-9-chemistry\/\">Chemistry<\/a><a class=\"button-blue\" title=\"FRANK ICSE Class 9 Biology Solutions\" href=\"https:\/\/www.aplustopper.com\/frank-icse-solutions-class-9-biology\/\">Biology<\/a><a class=\"button-blue\" title=\"FRANK ICSE Class 9 Maths Solutions\" href=\"https:\/\/www.aplustopper.com\/frank-icse-solutions-class-9-maths\/\">Maths<\/a><\/p>\n","protected":false},"excerpt":{"rendered":"<p>Frank ICSE Solutions for Class 9 Physics &#8211; Fluids PAGE NO: 157 Solution 1: The thrust on the unit surface is known as pressure. The SI unit of pressure is Nm-2. Solution 2: Pressure is given by P = h Xp Xg. Where h is height of liquid column, p is density of liquid, g [&hellip;]<\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_genesis_hide_title":false,"_genesis_hide_breadcrumbs":false,"_genesis_hide_singular_image":false,"_genesis_hide_footer_widgets":false,"_genesis_custom_body_class":"","_genesis_custom_post_class":"","_genesis_layout":"","footnotes":""},"categories":[6442,3034,404],"tags":[6813,6840,6837,6858,6824,6839,6838,6811,6836],"yoast_head":"<!-- This site is optimized with the Yoast SEO Premium plugin v17.8 (Yoast SEO v17.8) - https:\/\/yoast.com\/wordpress\/plugins\/seo\/ -->\n<title>Frank ICSE Solutions for Class 9 Physics - Fluids - A Plus Topper<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.aplustopper.com\/frank-icse-solutions-class-9-physics-fluids\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"Frank ICSE Solutions for Class 9 Physics - Fluids\" \/>\n<meta property=\"og:description\" content=\"Frank ICSE Solutions for Class 9 Physics &#8211; Fluids PAGE NO: 157 Solution 1: The thrust on the unit surface is known as pressure. The SI unit of pressure is Nm-2. Solution 2: Pressure is given by P = h Xp Xg. 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Fluids PAGE NO: 157 Solution 1: The thrust on the unit surface is known as pressure. The SI unit of pressure is Nm-2. Solution 2: Pressure is given by P = h Xp Xg. 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