{"id":1898,"date":"2022-11-17T11:00:19","date_gmt":"2022-11-17T05:30:19","guid":{"rendered":"https:\/\/www.aplustopper.com\/?p=1898"},"modified":"2022-11-18T11:07:29","modified_gmt":"2022-11-18T05:37:29","slug":"buoyant-force","status":"publish","type":"post","link":"https:\/\/www.aplustopper.com\/buoyant-force\/","title":{"rendered":"How Do You Find Buoyant Force"},"content":{"rendered":"

How Do You Find Buoyant Force<\/strong><\/h2>\n

Buoyancy<\/strong>
\nWhen a body is immersed in a liquid, the liquid exerts an upward force<\/a> on the body called as the ‘upthrust<\/strong>‘ or ‘buoyant force<\/strong>.’<\/p>\n

Factors affecting upthrust:<\/strong>
\n1. Larger the volume of the body submerged in the liquid, greater is the upthrust.
\n2. Larger the density of the liquid, greater is the upthrust.<\/p>\n

Applying Archimedes’ Principle<\/a><\/strong><\/h2>\n

Figure shows a boy transferring a boulder from the seabed to a beach.
\n\"\"
\n(a) He finds that the boulder becomes heavier as it emerges from the surface of the sea.
\n(b) The boulder is lighter when it is immersed in the sea because of the existence of the buoyant force.
\n(c) The buoyant force<\/strong> is an upward force resulting from an object being wholly or partially immersed in a fluid.
\n(d) The bigger the volume of the boulder immersed in the sea, the bigger the buoyant force.
\n\"ApplyingFigure shows the relationship between real weight and apparent weight of an object and the upward buoyant force acting on it.
\nBuoyant force = Actual weight – Apparent weight<\/strong>
\nTherefore,
\nApparent weight = Actual weight – Buoyant force<\/strong><\/p>\n

Experiment:<\/strong><\/p>\n

Aim:<\/strong> To investigate the relationship between the weight of water displaced and the buoyant force.
\nSituation:<\/strong> A hawker immersed a watermelon into a tub filled with water. Water was displaced from the tub when the watermelon was submerged in it. He noticed that the submerged watermelon was lighter.
\n\"ApplyingProblem:<\/strong> What is the relationship between the weight of water displaced and the buoyant force?
\nMaterials:<\/strong> Plasticine, thread
\nApparatus:<\/strong> Spring balance, electronic balance, eureka can, beaker
\nMethod:
\n\"Applying<\/strong><\/p>\n

    \n
  1. The mass of an empty beaker, m, is measured with an electronic balance and recorded.<\/li>\n
  2. A plasticine is attached to a spring balance with a string as shown in Figure (a).<\/li>\n
  3. The weight of the plasticine, W1<\/sub>\u00a0is measured and recorded.<\/li>\n
  4. Water is poured into a eureka can until it flows out of the spout of the can.<\/li>\n
  5. When the water has stopped dripping from the spout, the empty beaker is placed under it.<\/li>\n
  6. The plasticine is slowly lowered into the eureka can as shown in Figure (b) until it is completely immersed in the water.<\/li>\n
  7. The readings of the spring balance, W2<\/sub> and the mass of the beaker that is filled with displaced water, m2<\/sub> are taken and recorded.<\/li>\n<\/ol>\n

    Results:
    \n<\/strong>\"Applying
    \nDiscussion:<\/strong>
    \nFrom the experiment, it is found that (m2<\/sub> – m1<\/sub>) g = (W1<\/sub> – W2<\/sub>).
    \nHence, the weight of water displaced is equal to the buoyant force.<\/strong><\/p>\n

    Buoyant Force\u00a0Example Problems with Solutions<\/strong><\/h2>\n

    Example 1.\u00a0<\/strong>A body weighs 300 gmf in air and 260 gmf when completely immersed in water. Calculate the following
    \n(i) loss in weight of the body
    \n(ii) upthrust on the body.
    \nSolution: \u00a0<\/strong> \u00a0Given: Weight of body in air = 300 gmf
    \nWeight of the body in water = 260 gmf
    \n\u2234 Loss in weight of the body = 300 \u2013 260 = 40 gmf
    \n\u2234 Upthrust of the body = Loss in weight
    \n= 40 gmf<\/p>\n

    Example 2.\u00a0<\/strong>A solid block of volume 2 litres has a weight of 80 N. What will be its weight when immersed completely in water ?
    \nSolution:<\/strong> \u00a0 \u00a0 In order to calculate the weight of the block in water, first calculate the upthrust, i.e. the loss in weight of the body in water, then
    \nVolume of the block = 2 litres = 2000 cc
    \n\u2234 Volume of water displaced = 2000 cc
    \nWeight of water displaced = 2000 gm
    \n= 2.0 kgf
    \n( Density of water = 1 gm\/cc)
    \n= 2.0 \u00d7 9.8 N = 19.6 N
    \n\u2234 Upthrust of water = 19.6 N
    \nHence, weight of the body fully immersed in water = 80 N \u2013 19.6 N = 60.4 N<\/p>\n

    Example 3.\u00a0<\/strong>A solid block of density D has a weight W in air is fully immersed in a liquid of density d. Calculate its apparent weight when fully immersed in liquid.
    \nSolution:<\/strong>\u00a0 \u00a0 Weight of the block = W
    \nDensity of block = D
    \n\u2234 Volume of the block = \\(\\frac { W }{ D }\\)\u00a0. d
    \n\u2234 Upthrust on the block = \\(\\frac { W }{ D }\\) .d
    \n\u2234 Loss in weight of the block inside liquid = \\(\\frac { W }{ D }\\) .d
    \nHence, apparent weight of the block when fully immersed in water
    \n\\(=\\text{W}-\\frac{\\text{W}}{\\text{D}}\\text{d}=\\text{W}\\left( 1-\\frac{\\text{d}}{\\text{D}} \\right)\\)<\/p>\n

    Example 4.<\/strong> The weight of a stone in air is 0.65 N. When it is completely submerged in water, its weight is 0.50 N.
    \n\"ApplyingWhat is the buoyant force acting on the stone when it is completely submerged in water?
    \nSolution:<\/strong>
    \nBuoyant force
    \n= Actual weight – Apparent weight = 0.65 – 0.50 = 0.15 N<\/p>\n

    Example 5.<\/strong> Figure shows an empty oil drum floating on the surface of a pond.
    \n\"Applying
    \nDraw and label the two forces acting on the oil drum.
    \nSolution:
    \n\"Applying
    \n<\/strong><\/p>\n

    <\/h2>\n","protected":false},"excerpt":{"rendered":"

    How Do You Find Buoyant Force Buoyancy When a body is immersed in a liquid, the liquid exerts an upward force on the body called as the ‘upthrust‘ or ‘buoyant force.’ Factors affecting upthrust: 1. Larger the volume of the body submerged in the liquid, greater is the upthrust. 2. Larger the density of the […]<\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_genesis_hide_title":false,"_genesis_hide_breadcrumbs":false,"_genesis_hide_singular_image":false,"_genesis_hide_footer_widgets":false,"_genesis_custom_body_class":"","_genesis_custom_post_class":"","_genesis_layout":"","footnotes":""},"categories":[404],"tags":[701,702,665,703],"yoast_head":"\nHow Do You Find Buoyant Force - A Plus Topper<\/title>\n<meta name=\"robots\" content=\"index, follow, max-snippet:-1, max-image-preview:large, max-video-preview:-1\" \/>\n<link rel=\"canonical\" href=\"https:\/\/www.aplustopper.com\/buoyant-force\/\" \/>\n<meta property=\"og:locale\" content=\"en_US\" \/>\n<meta property=\"og:type\" content=\"article\" \/>\n<meta property=\"og:title\" content=\"How Do You Find Buoyant Force\" \/>\n<meta property=\"og:description\" content=\"How Do You Find Buoyant Force Buoyancy When a body is immersed in a liquid, the liquid exerts an upward force on the body called as the ‘upthrust‘ or ‘buoyant force.’ Factors affecting upthrust: 1. 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