{"id":1541,"date":"2022-11-18T10:00:25","date_gmt":"2022-11-18T04:30:25","guid":{"rendered":"https:\/\/www.aplustopper.com\/?p=1541"},"modified":"2022-11-19T09:54:40","modified_gmt":"2022-11-19T04:24:40","slug":"ohms-law","status":"publish","type":"post","link":"https:\/\/www.aplustopper.com\/ohms-law\/","title":{"rendered":"What is the Ohm’s law?"},"content":{"rendered":"
People also ask<\/strong><\/p>\n What is the Ohm’s law? The proportional relationship of the potential difference between the ends of an ideal conductor and the current passing through it is known as Ohm\u2019s law. Ohm\u2019s law states that the current passing through an ideal conductor is directly proportional to the potential difference between its ends, provided that the temperature […]<\/p>\n","protected":false},"author":3,"featured_media":0,"comment_status":"open","ping_status":"open","sticky":false,"template":"","format":"standard","meta":{"_genesis_hide_title":false,"_genesis_hide_breadcrumbs":false,"_genesis_hide_singular_image":false,"_genesis_hide_footer_widgets":false,"_genesis_custom_body_class":"","_genesis_custom_post_class":"","_genesis_layout":"","footnotes":""},"categories":[404],"tags":[405,423,424,425],"yoast_head":"\n\n
Ohm’s Law Problems with Solution<\/strong><\/h2>\n
\n
\nSolution:
\n<\/strong>\\( R = \\frac{V}{I}\u00a0\\)
\n= 12\/0.2
\n= 60\u00a0\u03a9<\/li>\n
\nSolution:<\/strong>
\nV = I \u00d7 R
\n= 0.5 \u00d7\u00a05 = 2.5 V<\/li>\n
\n(a) What is the resistance of the heating element?
\n(b) Can this electric heater be used in a country where the main supply is 110 V? Explain your answer.
\nSolution:
\n<\/strong>(a)\u00a0\\( R = \\frac{V}{I}\u00a0\\)
\n= 230\/5
\n= 46\u00a0\u03a9
\n(b) The heater can still be used but the heating effect will be very much lesser as the current passing through the heater is very much smaller. The current that passes through the heater is:
\n\\( I = \\frac{V}{R}\u00a0\\)
\n= 110\/46
\n= 2.4 A
\nThis value is smaller than 5 A.<\/li>\n
\nSolution:<\/strong>
\nPotential difference across the motor when a current of 0.5 A is passing through:
\nV = IR = 0.5 x 10 = 5 V
\nWhen the potential difference is doubled
\n2 x 5 = I x 10
\nI = 1 A<\/li>\n<\/ol>\nWhat is a superconductor made of?<\/h2>\n
\n
\n<\/li>\n
\n<\/li>\n<\/ol>\n","protected":false},"excerpt":{"rendered":"