{"id":136553,"date":"2024-02-19T08:46:00","date_gmt":"2024-02-19T03:16:00","guid":{"rendered":"https:\/\/www.aplustopper.com\/?p=136553"},"modified":"2024-02-19T14:19:13","modified_gmt":"2024-02-19T08:49:13","slug":"plus-one-economics-chapter-wise-previous-questions-chapter-15","status":"publish","type":"post","link":"https:\/\/www.aplustopper.com\/plus-one-economics-chapter-wise-previous-questions-chapter-15\/","title":{"rendered":"Plus One Economics Chapter Wise Previous Questions Chapter 15 Measures of Central Tendency"},"content":{"rendered":"

Kerala Plus One Economics Chapter Wise\u00a0Previous Questions Chapter 15 Measures of Central Tendency<\/h2>\n

Question 1.
\nRewrite the following statement correctly: (March 2009)<\/span>
\nA value which divides the data into 10 (ten) equal parts is called percentiles.
\nAnswer:
\nThe value which divides the data into 10 equal parts is called deciles.<\/p>\n

Question 2.
\nThe following information relates to the daily income of 150 families. Calculate the arithmetic mean. (March 2009)<\/span>
\n\"Plus
\nAnswer:
\nArithmetic mean,
\n\"Plus<\/p>\n

Question 3.
\nThe following data gives the ages of 20 agricultural labourers. Calculate the median age. (March 2009)<\/span>
\n\"Plus
\nAnswer:
\nMedian = Size of \\(\\left(\\frac{N+1}{2}\\right)^{t h}\\) item = 52.5<\/p>\n

Question 4.
\nFind the modal value of income obtained by 20 workers in a company. (Say 2009)<\/span>
\n\"Plus
\nAnswer:
\n300<\/p>\n

Question 5.
\nThe following data shows the weekly income of 10 families. (Say 2009)<\/span>
\n\"Plus
\nCompute the average family income.
\nAnswer:
\n\\(\\bar{x}=\\frac{\\Sigma x}{N}\\) = 1111<\/p>\n

Question 6.
\nMarks obtained by six students in a class are given below. Derive an equation of Arithmetic Mean. Calculate the Arithmetic Mean and explain the other characteristics of Arithmetic Mean by using the data: (March 2010)<\/span>
\nAnil = 800, Arun = 750, Binil = 650, Sunil = 520, Anoop = 340, Sooraj = 810.
\nAnswer:
\nMean = \\(\\frac{\\Sigma x}{N}\\)
\n\u03a3x = 800 + 750 + 650 + 520 + 340 + 810 = 3870
\nN = 6
\n\\(\\bar{x}=\\frac{\\sum x}{N}\\) = \\(\\frac{3870}{6}\\) = 645<\/p>\n

Question 7.
\nCorrect the following sentences: (March 2011)<\/span><\/p>\n

    \n
  1. The sum of deviations of items from the median is zero.<\/li>\n
  2. An average alone is enough to compare series.<\/li>\n
  3. The upper quartile has 25% of the items of the distribution below it.<\/li>\n
  4. Mode is the middlemost item of a series.<\/li>\n<\/ol>\n

    Answer:<\/p>\n

      \n
    1. The sum of deviation of items from mean is zero.<\/li>\n
    2. The average alone is not enough to compare series.<\/li>\n
    3. The upper quartile has 75% of the items of the distribution below it.<\/li>\n
    4. Median is the middlemost item of a series.<\/li>\n<\/ol>\n

      Question 8.
      \nThe following table shows daily wages and the number of workers in a factory. Find the median wage. (March 2011)<\/span>
      \n\"Plus
      \nAnswer:
      \nCalculate median for continuous series by using the formula,
      \n\"Plus<\/p>\n

      Question 9.
      \nCalculate the mode using a formula and locate the mode graphically to verify the result. (March 2012)<\/span>
      \n\"Plus
      \nAnswer:
      \n\"Plus<\/p>\n

      Question 10.
      \nThe following table gives data on the daily wages of 199 workers in a factory. Calculate D5 and P50 of the following series. Comment on the result. (March 2012)<\/span>
      \n\"Plus
      \nAnswer:
      \n\"Plus<\/p>\n

      Question 11.
      \nThe marks obtained by 60 students in the annual examination is given below. Calculate the mean, median, and mode. (Say 2012)<\/span>
      \n\"Plus
      \nAnswer:
      \na) Mean
      \n\"Plus
      \nb) Median
      \n\"Plus
      \nc) Mode
      \nMode = 3 \u00d7 median – 2 \u00d7 mean
      \n= 3 \u00d7 42 – 2 \u00d7 43.5
      \n= 126 – 87
      \n= 39<\/p>\n

      Question 12.
      \nDefine Arithmetic mean. (Say 2012)<\/span>
      \nAnswer:
      \nThe arithmetic mean is the value obtained by dividing the sum of a set of quantities by the number of quantities in the set.
      \nSuppose we have a data set containing the values a1<\/sub>, ………, an<\/sub>.
      \nThe arithmetic mean A is defined by the formula
      \n\"Plus
      \nIf the data set is a statistical population (i.e., consists of every possible observation and not just a subset of them), then the mean of that population is called the population mean. If the data set is a statistical sample (a subset of the population) we call the statistic resulting from this calculation a sample mean.
      \nThe arithmetic mean of a variable is often denoted by a bar, for example as in \\(\\bar{x}\\)s (read \u201cx bar”), which is the mean of the n values x1<\/sub>, x2<\/sub>,…. xn<\/sub>.<\/p>\n

      Question 13.
      \n\u201cWatching the reactions of the respondent can provide supplementary information.\u201d Identify the mode of data collection mentioned here. (March 2013)<\/span>
      \nAnswer:
      \nPersonal Interview<\/p>\n

      Question 14.
      \nHeights of 10 plants in a garden are given below. (March 2013)<\/span>
      \n\"Plus
      \na) Find the mean height.
      \nb) State the interesting property of A.M.
      \nAnswer:
      \na) Arithmetic mean (AM) = \u03a3X\/N = 305\/10 = 30.5
      \nHence, mean height = 30.5 cm
      \nb) i) Mode
      \nii) Median
      \niii) Mode or median
      \niv) Mode or median
      \nv) Mean
      \nvi) Mode or mean
      \nvii) Median<\/p>\n

      Question 15.
      \nAshna made the following statement. (March 2013)<\/span>
      \n\u201cArithmetic mean is always between the median and the mode.\u201d
      \nCorrect the statement if it is wrong.
      \nAnswer:
      \nWrong. Median is always between mean and mode.<\/p>\n

      Question 16.
      \nThe following table shows marks scored by 230 students in an examination. Find the mean median and mode of the series. (Say 2013)<\/span>
      \n\"Plus
      \nAnswer:
      \nHere cumulative frequency is given first we should arrange it in frequency distribution in class intervals.
      \n\"Plus<\/p>\n

      \"Plus
      \nL = Lower limit of the median class
      \ncf = Cumulative frequency of the class proceeding the median class
      \nf = Frequency of median class
      \nh = Magnitude of the median class interval
      \n\"Plus
      \nL = Lower limit of modal class
      \nD1<\/sub> = Difference between the frequency of the modal class and frequency of pre modal class
      \nD2<\/sub> = Difference between the modal class and post modal class
      \n\"Plus<\/p>\n

      Question 17.
      \nData represented through a histogram can help in the finding graphically the ________ (March 2014)<\/span>
      \na) mean
      \nb) mode
      \nc) median
      \nd) standard deviation
      \nAnswer:
      \nb) mode<\/p>\n

      Question 18.
      \nThe following data shows the marks obtained by 50 students of a class in a test. (March 2014)<\/span>
      \n\"Plus
      \nFind the arithmetic mean, median, and mode.
      \nAnswer:
      \n\"Plus<\/p>\n

      \"Plus
      \nWhere L = Lower limit of the median class
      \ncf = Cumulative frequency of preceding class
      \nf = Frequency of median class
      \nh = Class interval of the median class
      \n\"Plus<\/p>\n

      \"Plus
      \nWhere L = Lower limit of modal class
      \nD1<\/sub> = Difference between the frequency of modal class and frequency of pre modal class
      \nD2<\/sub> = Difference between the frequency of modal class and frequency of post modal class
      \nh = Class interval of modal class
      \n\"Plus<\/p>\n

      Question 19.
      \nPrepare a seminar paper on the several statistical measures of central tendency or averages and explain with relevant equations for individual series, discrete series, and continuous series. (March 2014)<\/span>
      \nAnswer:
      \nThe measuring of central tendency is a way of summarizing the data in the form of a typical or representative value.
      \nArithmetic Mean
      \nThere are several statistical measures of central tendency or \u201caverages\u201d. The three most commonly used averages are:<\/p>\n