**Selina Concise Mathematics Class 6 ICSE Solutions – Fractions**

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**EXERCISE 14(A)**

**Question 1.**

For each expression, given below, write a fraction :

(i) 2 out of 7 = ………..

(ii) 5 out of 17 = ………..

(iii) three-fifths = ………

**Solution:**

(i) 2 out of 7 =

(ii) 5 out of 17 =

(iii) three-fifths =

**Question 2.**

**Fill in the blanks :**

**Solution:**

(i) Proper

(ii) Improper

(iii) Improper

(iv) 1

(v) -1

(vi) Mixed

(vii) Like

(viii) Unlike fraction

(ix) Equal fraction

(x) Like

**Question 3.**

From the following fractions, separate :

(i) Proper fractions

(ii)Improper fractions :

**Solution:**

We know that proper fraction is a fraction whose numerator is less than its denominator and improper fraction is the fraction whose numerator is greater them its denominator :

**Question 4.**

Change the following mixed fractions to improper fractions :

**Solution:**

**Question 5.**

Change the following improper fractions to mixed fractions :

**Solution:**

**Question 6.**

Change the following groups of fractions to like fractions :

**Solution:**

**EXERCISE 14(B)**

**Question 1.**

Reduce the given fractions to their lowest terms :

**Solution:**

**Question 2.**

State, whether true or false ?

**Solution:**

**Question 3.**

Which fraction is greater ?

**Solution:**

**Question 4.**

Which fraction is smaller ?

**Solution:**

**Question 5.**

Arrange the given fractions in descending order of magnitude :

**Solution:**

**Question 6.**

Arrange the given fractions in ascending order of magnitude :

**Solution:**

**Question 7.**

I bought one dozen bananas and ate five of them. What fraction of the total number of bananas was left ?

**Solution:**

Number of bananas bought = 1

Dozen = 12

Number of bananas eaten by me = 5

Number of bananas left = 12 – 5 = 7

Fraction =

**Question 8.**

Insert the symbol ‘=’ or ‘>’ or ‘<’ between each of the pairs of fractions, given below :

**Solution:**

**Question 9.**

Out of 50 identical articles, 36 are broken. Find the fraction of :

(i) The total number of articles and the articles broken.

(ii) The remaining articles and total number of articles.

**Solution:**

Total number of articles = 50

Number of articles broken = 36

Remaining articles = 50 – 36 = 14

Now (i) the fraction of the total number of articles and articles broken =

**EXERCISE 14(C)**

**Question 1.**

Add the following fractions :

**Solution:**

**Question 2.**

Simplify :

**Solution:**

**EXERCISE 14(D)**

Point to Remember :

**BODMAS** :- While simplifying an expressions we can involve six operation in following orders.

**B** Stands for **“BRACKET”**

**O** Stands for **“OF”**

**D** Stands for **“DIVISION”**

**M** Stands for **“MULTIPLICATION”**

**A** Stands for **“ADDITION”**

**S** Stands for **“SUBTRACTION”**

**Question 1.**

Simplify :

**Solution:**

**Question 2.**

Simplify :

**Solution:**

**Question 3.**

Simplify :

**Solution:**

**Question 4.**

Simplify :

**Solution:**

**Question 5.**

Simplify :

**Solution:**

**EXERCISE 14(E)**

**Question 1.**

From a rope of 10 m long, 4 m is cut off. Find the length of the remaining rope.

**Solution:**

**Question 2.**

A piece of cloth is 5 metre long. After washing, it shrinks by of its length. What is the length of the cloth after washing ?

**Solution:**

**Question 3.**

I bought wheat worth Rs. 12, rice worth Rs. 25 and vegetables worth

Rs. 10. If I gave a hundred-rupee note to the shopkeeper ; how much did he return to me

**Solution:**

**Question 4.**

Out of 500 oranges in a box, are rotten and are kept for some guests. How many oranges are left in the box?

**Solution:**

**Question 5.**

An ornament piece is made of gold and copper. Its total weight is 96g. If of the ornament hi copper, find the weight of gold in it.

**Solution:**

**Question 6.**

A girl did half of some work on Monday and one-third of it on Tuesday. How much will she have to do on Wednesday in order to complete the work ?

**Solution:**

**Question 7.**

A man spends of his money and 8 still has Rs. 720 left with him. How much money did he have at first ?

**Solution:**

**Question 8.**

In a school, of the students are boys, and the number of girls is 100. Find the number of boys.

**Solution:**

**Question 9.**

After finishing of my journey, I find that 12 km of my journey is covered. How much distance is still left to be covered ?

**Solution:**

**Question 10.**

When Ajit travelled 15 km, he found that one-fourth of his journey was still left. What was the full length of the journey ?

**Solution:**

**Question 11.**

In a particular month, a man earns Rs. 7,200. Out of this income, he spends on food, on house rent, on insurance and on holidays. How much did he save in that month ?

**Solution:**

**REVISION EXERCISE**

**Question 1.**

**Solution:**

**Question 2.**

**Solution:**

**Question 3.**

Evaluate :

**Solution:**

**Question 4.**

Mr. Mehra gave one-third of his money to his son, one-fifth of his money to his daughter and the remaining amount to his wife. If his wife got Rs. 91,000, how much money did Mr. Mehra have originally?

**Solution:**

**Question 5.**

A sum of Rs. 84,000 is divided among three persons A, B and C. If A gets one-fourth of it and B gets one-fifth of it; how much did C get ?

**Solution:**

= Rs. 84,000 – (37,800) = Rs. 46,200

**Question 6.**

In one hour Rohit walks 3 km. How much distance will he cover in 2 hours?

**Solution:**

**Question 7.**

An 84 m long string is cut into pieces each of length 5 m. How many pieces are obtained ?

**Solution:**

**Question 8.**

In buying a ready made shirt-two-fifths of my pocket money is spent If Rs. 540 is still left with me, find :

(i) The money I had before I bought the shirt.

(ii) The emit of the shirt

**Solution:**

**Question 9.**

Mohan leaves Rs. 1,20,000 to his wife and three children such that two-fifths of this money is given to his wife and the remaining is distributed equally among the children. Find, how much each child gets ?

**Solution:**

Total amount = Rs. 12,0,000

Amount given to his wife = of Rs. 1,20,000

= Rs. 2 x 24,000 = Rs. 48,000

Remaining amount = Rs. 120000 – Rs. 48000 = Rs. 72000

This amount is distributed among three children equally.

Each’s share = Rs. 72,000 x = Rs. 24,000

**Question 10.**

Simplify :

**Solution:**

Selina Class 6 Maths ICSE SolutionsPhysicsChemistryBiologyGeographyHistory & Civics

Rudra N Jaiswal says

Rest chapter of maths. It’s really good we need more help by the solution of other chapters