RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Ratios of Complementary Angles

RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Ratios of Complementary Angles

These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Solutions Class 10 Chapter 8 Trigonometric Ratios of Complementary Angles

Exercise 8

Question 1:

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Question 2:
(i)  

∴ LHS = RHS
(ii)  

∴ LHS = RHS
(iii)  

∴ LHS = RHS
(iv)  

∴ LHS = RHS
(v)

∴ LHS = RHS

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• RS Aggarwal Solutions Class 10
• RD Sharma Class 10 Solutions
• NCERT Solutions

Question 3:
(i)

(ii)

(iii)

(iv)

Question 4:
(i) LHS = cos81° – sin9°
= cos(90° -9°)- sin9° = sin9° – sin9°
= 0 = RHS
(ii) LHS = tan71° – cot19°
=tan(90° – 19°) – cot19° =cot19° – cot19°
=0 = RHS
(iii) LHS = cosec80° – sec10°
= cosec(90° – 10°) – sec(10°)
= sec10° – sec10° = 0
= RHS


Question 5:
(i) LHS = sin53° cos37° + cos53° sin37°

∴ LHS = RHS
(ii) LHS = cos54° cos36° + sin54° sin36°

∴ LHS = RHS
(iii) LHS = sec70° sin20° + cos20° cosec70°

∴ LHS = RHS
Question 6:
(i)  

∴ LHS = RHS
(ii)  

∴ LHS = RHS
(iii)  

∴ LHS = RHS
(iv)  LHS = cot10°cot20° cot60°cot70° cot°

∴ LHS = RHS
(v) cosec15°cosec355°cosec55°cosec60°cosec75°

∴ LHS = RHS
Question 7:
(i)  LHS=

= RHS
(ii)  LHS=

= RHS
(iii)  LHS=

= RHS
(iv)  LHS = cosec(65° + θ) – sec(25°- θ) – tan(55° – θ) + cot(35° + θ)

= RHS
(v)  LHS =

= 0 + 1 = 1
= RHS
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