RS Aggarwal Solutions Class 10 Chapter 10 Quadratic Equations 10A

These Solutions are part of RS Aggarwal Solutions Class 10. Here we have given RS Aggarwal Solutions Class 10 Chapter 10 Quadratic Equations 10A

Other Exercises

Exercise 10A

Solving-Factorable-Quadratic-Equations-1

Question 1:

(i) x²-x+3=0 is a quadratic polynomial.
∴ x²-x+3=0 is a quadratic equation.

(ii) 2x²+ $\frac { 5 }{ 2 }$ x-√3=0
⇒ 4x²+5x-2√3=0
Clearly is 4x²+5x-2√3=0 a quadratic polynomial.
∴ 2x²+ $\frac { 5 }{ 2 }$ x-√3=0 is a quadratic equation.

(iii) √2x²+7x+5√2=0 is a quadratic polynomial.
∴ √2x²+7x+5√2=0 is a quadratic equation.

(iv) $\frac { 1 }{ 3 }$ x²+ $\frac { 1 }{ 5 }$ x-2=0
⇒ 5x²+3x-2=0
Clearly, 5x²+3x-2=0 is a quadratic equation.
$\frac { 1 }{ 3 }$ x²+ $\frac { 1 }{ 5 }$ is a quadratic equation.

(v) x²-3x-√x+4=0 is not a quadratic polynomial since it contains √x, in which power 1/2 of x is not an integer.
∴ x²-3x-√x+4=0 is not a quadratic equation.

(vi) x- $\frac { 6}{ x }$ =3
⇒ x²-3x-6 =0
And (x²-3x-6)Being a polynomial of degree 2, it is a quadratic polynomial.
Hence, x- $\frac { 6}{ x }$ =3 is a quadratic equation.

(vii) x+ $\frac { 2}{ x }$ = x²
⇒ x³-x²-2 =0
And (x³-x²-2 =0) being a polynomial of degree 3, it is not a quadratic polynomial.
Hence, x+ $\frac { 2}{ x }$ = x² is not a quadratic equation.

(viii) ${ x }^{ 2 }-\frac { 1 }{ { x }^{ 2 } } =5$ ⇒ x⁴ -1=5x²
⇒x⁴-5x²-1 =0
And (x⁴-5x²-1 =0) being a polynomial of degree 4.
Hence ${ x }^{ 2 }-\frac { 1 }{ { x }^{ 2 } } =5$ is not a quadratic equation.

Solving A Quadratic Equation By Completing The Square

Question 2:
The given equation is 3x²+2x-1=0
(i) On substituting x = -1 in the equation, we get

(ii) On substituting $x=\frac { 1 }{ 3 }$ in the equation, we get
rs-aggarwal-class-10-solutions-quadratic-equations-10a-q2-2
(iii) On substituting $x=-\frac { 1 }{ 2 }$ in the equation , we get

More Resources

Question 3:
Since x = 1 is a solution of x²+kx+3=0 it must satisfy the equation.

Hence the required value of k = -4
Question 4:
Since $x=\frac { 3 }{ 4 }$ is a root of ax²+bx-6=0, we have

RS Aggarwal Solutions Class 10 Chapter 10 Quadratic Equations Ex 10a
Again x = -2 being a root of ax²+bx-6=0, we have

Multiplying (2) by 4 adding the result from (1), we get
11a = 44 ⇒ a = 4
Putting a = 4 in (1), we get

Question 5:
RS Aggarwal Class 10 Solutions Chapter 10 Quadratic Equations Ex 10a
Question 6:

Question 7:

Hence, 9 and -9 are the roots of the equation 3x²-243=0.
Question 8:

Hence, -5 and -7 are the roots of x²+12x+35=0.
Question 9:

Hence, 11 and 7 are the roots of equation x²=18x-77
Question 10:
Solution of RS Aggarwal Class 10 Chapter 10 Quadratic Equations Ex 10a
Hence, $x=-\frac { 1 }{ 3 }$ is the repeated root of the equation 9x²+6x+1=0
Question 11:

Hence, is the repeated root of the equation
Question 12:

Hence, $x=-\frac { 3 }{ 2 }$ , $x=-\frac { 1 }{ 2 }$ are the roots of 6x²+11x+3=0
Question 13:
Solution of RS Aggarwal Class 10 Chapter 10 Quadratic Equations Ex 10a
Hence, $x=\frac { 4 }{ 3 }$ and $x=-\frac { 3 }{ 2 }$ are the roots of equation 6x²+x-12=0

Question 14:
RS Aggarwal Solutions Class 10 2017 Chapter 10 Quadratic Equations Ex 10a
Hence, $x=-\frac { 1 }{ 3 }$ and 1 are the roots of the equation 3x²-2x-1=0.
Question 15:

Hence, $x=\frac { 2 }{ 3 }$ and $x=-\frac { 1 }{ 2 }$ are the roots of equation 6x²-x-2=0.
Question 16:

Hence, $x=-\frac { 1 }{ 16 }$ and $x=\frac { 2 }{ 3 }$ are the roots of 48x²-13x-1=0.
Question 17:
RS Aggarwal Solutions Class 10 2017 Chapter 10 Quadratic Equations Ex 10a
Hence, $x=-\frac { 5 }{ 3 }$ and x=-2 are the roots of the equation 3x²+11x+10=0
Question 18:
Class 10 RS Aggarwal Solutions Chapter 10 Quadratic Equations Ex 10a
Hence, $x=\frac { 25 }{ 4 }$ and x=-4 are the roots of the equation 4x²-9x=100.
Question 19:

Hence, $x=\frac { 4 }{ 9 }$ and 2 are the roots of the equation 9x²-22+8=0
Question 20:

Hence, $x=\frac { 7 }{ 5 }$ and $x=-\frac { 4 }{ 3 }$ are the roots of the given equation 15x²-28=x.
Question 21:
RS Aggarwal Class 10 Maths Book Solutions pdf Chapter 10 Quadratic Equations Ex 10a
Hence, $x=\frac { 1 }{ 3 }$ and -4 are the roots of given equation .
Question 22:

Hence, 1 and √2 are the roots of the given equation
Question 23:

Question 24:
RS Aggarwal Class 10 Book pdf download Chapter 10 Quadratic Equations Ex 10a
Question 25:

Hence, $\frac { -\sqrt { 7 } }{ 3 }$ and $\frac { \sqrt { 7 } }{ 7 }$ are the roots of given equation.
Question 26:

Hence, -√7 and $\frac { 13\sqrt { 7 } }{ 7 }$ are the roots of given equation.
Question 27:
RS Aggarwal Class 10 Book pdf download Chapter 10 Quadratic Equations Ex 10a
Hence, $\frac { 2\sqrt { 6 } }{ 3 }$ and $\frac { -\sqrt { 6 } }{ 8 }$ are the roots of given equation.
Question 28:
Class 10 Maths RS Aggarwal Solutions Chapter 10 Quadratic Equations Ex 10a
Hence, 5 and $-\frac { 7 }{ 5 }$ are the roots of given equation
Question 29:

Hence, $-\frac { 1 }{ 5 }$ and $\frac { 1 }{ 2 }$ are the roots of given equation.
Question 30:

Hence, 2 and $\frac { 1 }{ 2 }$ are the roots of given equation.
Question 31:
Class 10 Maths RS Aggarwal Solutions Chapter 10 Quadratic Equations Ex 10a
Hence, $-\frac { b }{ a }$ and $\frac { c }{ b }$ are the roots of given equation.
Question 32:

Hence, $\frac { -1 }{ { a }^{ 2 } }$ and $\frac { 1 }{ { b }^{ 2 } }$ are the roots of given equation.
Question 33:
RS Aggarwal Solutions Class 10 Chapter 10 Quadratic Equations Ex 10a
Hence, $\frac { 3a }{ 4b }$ and $\frac { -2b }{ 3a }$ are the roots of given equation.
Question 34:

Hence, $\frac { { a }^{ 2 } }{ 2 }$ and $\frac { { b }^{ 2 } }{ 2 }$ are the roots of given equation.
Question 35:
RS Aggarwal Solutions Class 10 Chapter 10 Quadratic Equations Ex 10a
Hence, 2 and 1 are the roots of the given equation
Question 36:
Class 10 RS Aggarwal Solutions Chapter 10 Quadratic Equations Ex 10a
Hence, -9 and 7 are the roots of the given equation
Question 37:

Hence, -4 and $\frac { 9 }{ 4 }$ are the roots of the given equation
Question 38:

Hence $\frac { 40 }{ 13 }$ and 6 are the roots of the given equation
Question 39:
Class 10 RS Aggarwal Solutions Chapter 10 Quadratic Equations Ex 10a
Hence, 4 and $-\frac { 2 }{ 9 }$ are the roots of the given equation
Question 40:
RS Aggarwal Solutions Class 10 2017 Chapter 10 Quadratic Equations Ex 10a
Hence, 3 and $\frac { 4 }{ 3 }$ are the roots of the given equation.
Question 41:

Hence, 5 and $\frac { 1 }{ 2 }$ are the roots of the given equation.
Question 42:
Putting the given equation become
RS Aggarwal Solutions Class 10 2017 Chapter 10 Quadratic Equations Ex 10a
Case I:
Solution of RS Aggarwal Class 10 Chapter 10 Quadratic Equations Ex 10a
Case II:

Hence, $-\frac { 3 }{ 2 }$ and -2 are the roots of the given equation
Question 43:

Putting the given equation become
RS Aggarwal Class 10 Solutions Chapter 10 Quadratic Equations Ex 10a
Case I:

Case II:

Hence, -1 and $-\frac { 23 }{ 5 }$ are the roots of the given equation
Question 44:
On putting the given equation become
RS Aggarwal Solutions Class 10 Chapter 10 Quadratic Equations Ex 10a
Case I:

Case II:

Hence, -10 and $-\frac { 1 }{ 5 }$ are the roots of the given equation.
Question 45:
Putting the given equation become

Case I:

Case II:

Hence, -1 and $\frac { 1 }{ 8 }$ are the roots of the given equation
Question 46:
The given equation
RS Aggarwal Solutions Class 10 2018 Chapter 10 Quadratic Equations Ex 10a
Hence, (a+b) and $\frac { (a+b) }{ 2 }$ is the roots of the given equation
Question 47:
Maths RS Aggarwal Class 10 Solutions Chapter 10 Quadratic Equations Ex 10a
Hence, $\frac { a+b }{ ab }$ and $\frac { 2 }{ a+b }$ are the roots of the given equation
Question 48:

Hence, -2,0 are the roots of the given equation
Question 49:

Hence, $\frac { 1 }{ 2 }$ and $\frac { 1 }{ 2 }$ are the roots of the given equation
Question 50:
Maths RS Aggarwal Class 10 Solutions Chapter 10 Quadratic Equations Ex 10a
Hence, 3 and 2 are the roots of the given equation.