## ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 7 Percentage Ex 7.2

Question 1.

Find the profit or loss percentage, when :

(i) C.P. = ₹400, S.P. = ₹468

(ii) C.P. = ₹ 13600, S.P. = ₹12104

Solution:

(i) C.P. = ₹400, S.P. = ₹468

Profit = S.P. – C.P. = 468 – 400 = ₹68

(ii) C.P. = ₹13600, S.P. = ₹12104

Loss = C.P. – S.P.

= ₹13600 – ₹12104 = ₹1496

Question 2.

By selling an article for ₹1636·25, a dealer gains ₹ 96·25. Find his gain per cent.

Solution:

S.P. of an article = ₹1636·25

Gain = ₹96·25

C.P. = S.P. – Gain

= ₹1636·25 – ₹96·25

= ₹1540

Question 3.

By selling an article for ₹770, a man incurs a loss of ₹110. Find his loss percentage.

Solution:

S.P. of an article = ₹ 770

Loss = ₹ 110

C.P. = S.P. + Loss = ₹ 770 + ₹ 110 = ₹ 880

Question 4.

Rashida bought 25 dozen eggs at the rate of ₹9.60 per dozen. 30 eggs were broken in the transaction and she sold the remaining eggs at one rupee each. Find her gain or loss percentage.

Solution:

C.P. of one dozen eggs = ₹ 9.60

C.P. of 25 dozen eggs = ₹ 25 × 9.60 = ₹ 240

Number of eggs = 25 dozen = 25 × 12 = 300

Number of eggs broken in transaction = 30

Number of remaining eggs = 300 – 30 = 270

S.P. of one egg = ₹ 1

S.P. of 270 eggs = ₹ 1 × 270 = ₹ 270

Profit = S.P. – C.P. = ₹ 270 – ₹ 240 = ₹ 30

Question 5.

The cost of an article was ₹20000 and ₹1400 were spent on its repairs. If it is sold for a profit of 20%, find the selling price of the article.

Solution:

Cost of an article = ₹20000

Cost of its repair = ₹1400

Total cost = ₹20000 + ₹1400 = ₹21400

Question 6.

A shopkeeper buys 200 bicycles at ₹1200 per bicycle. He spends ₹30 per bicycle on transportation. He also spends ₹4000 on advertising. Then he sells all the bicycles at ₹1350 per piece. Find his profit or loss. Also, calculate it as a percentage.

Solution:

Cost price of one bicycle = ₹1200

Cost price of 200 bicycle = ₹1200 × 200 = ₹240000

Expenditure on transportation for one bicycle = ₹30

Expenditure on transportation for 200 bicycle

= ₹30 × 200 = ₹6000

Expenditure on advertising = ₹4000

Net C.P. of the bicycle

= ₹240000 + ₹6000 + ₹4000 = ₹250000

S.P. of 200 bicycle at ₹1350 per bicycle

= ₹200 × 1350 = ₹270000

Profit = S.P. – C.P. = ₹270000 – ₹250000 = ₹20000

Question 7.

The cost price of an article is 90% of its selling price. Find his profit percentage.

Solution:

Let S.P. of an article = ₹ x

Then C.P. of an article = 90 % of ₹ x

Question 8.

Rao bought notebooks at the rate of 4 for ₹35 and sold them at the rate of 5 for ₹58. Calculate

(i) his gain percentage.

(ii) the number of notebooks he should sell to earn a profit of ₹171.

Solution:

Let the number of note books bought = 20

[Note : L.C.M. of 4 and 5 = 20]

∴ C.P. of the note books = ₹\(\frac{35}{4}\) × 20 = ₹ 35 × 5 = ₹ 175

and S.P. of the note books = ₹\(\frac{58}{5}\) × 20 = ₹58 × 4 = ₹232

(i) Gain = S.P. – C.P. = ₹ 232 – ₹175 = ₹57

(ii) When profit is ₹57, the quantity of note books sold = 20

When profit is ₹1, the quantity of note books sold = \(\frac{20}{57}\)

When profit is ₹171, the quantity of note books sold = \(\frac{20}{57}\) × 171

= 20 × 3 = 60

Question 9.

A vendor buys bananas at 3 for a rupee and sells at 4 for a rupee. Find his profit or loss percentage.

Solution:

Let number of bananas bought = 12

[Note : L.C.M. of 3 and 4 = 12]

∴ C.P. of bananas = ₹ \(\frac{1}{3}\) × 12 = ₹4

and S.P. of bananas = ₹\(\frac{1}{4}\) × 12 = ₹3

Loss = C.P. – S.P. = ₹4 = ₹3 = ₹1

Loss % = \(\left(\frac{\text { Loss }}{\text { C.P. }} \times 100\right) \%\)

= \(\left(\frac{1}{4} \times 100\right) \%\)

= \(\frac{100}{4} \%=25 \%\)

Question 10.

A shopkeeper buys a certain number of pens. If the selling price of 5 pens is equal to the cost price of 7 Pens, find his profit or loss percentage.

Solution:

Let the cost price of 7 Pens = ₹ x

Cost price of 1 Pen = ₹ \(\frac{x}{7}\)

Also, according to question,

Selling price of 5 Pens = ₹x

Selling price of 1 Pens = ₹ \(\frac{x}{5}\)

Profit = S.P. – C.P. = ₹ \(\frac{x}{7}\) – ₹ \(\frac{x}{5}\)

Question 11.

Find the selling price, when :

(i) Cost price = ₹2360, Profit = 8%

(ii) Cost price = ₹380, Loss = 7·5%

Solution:

(i) Cost price = ₹2360, Profit = 8%

We know that,

S.P = \(\left(\frac{100+\text { Profit } \%}{100}\right)\) × C.P.

Question 12.

A dealer bought a number of eggs at ₹18 a dozen and sold them at 50% profit. Find the selling price per egg.

Solution:

C.P. of one dozen eggs i.e. 12 eggs = ₹18

Profit = 50%

Question 13.

Mr Ghosh purchased wristwatches worth ₹60000. He sold one-third of them at a profit of 30%, one-third at a profit of 20% and remaining at a loss of 5%. Calculate his overall profit or loss percentage.

Solution:

C.P. of wristwatches = ₹60000

Hence Profit = 15 %

Question 14.

A laptop and a mobile phone were bought for ₹40000 and ₹24000 respectively. The shopkeeper made a profit of 8% on the laptop and a loss of 12% on the mobile phone. Find his gain or loss per cent on the whole transaction.

Solution:

C.P. of laptop = ₹40000

and C.P. of mobile phone = ₹24000

Profit on laptop = 8%

and loss on mobile phone = 12%

Total cost = ₹40000 + ₹24000 = ₹64000

and Total S.P. = ₹43200 + ₹21120 = ₹64320

∴ Gain = S.P. – C.P. = ₹64320 – ₹64000 = ₹320

∴ Gain % = \(\frac { Gain\times 100 }{ C.P. } \)

= \(\frac{320 \times 100}{64000}=\frac{1}{2} \%\) = 0.5%

Question 15.

Salman bought 40 chairs at ₹175 each fourth of them at a loss of 8%. At what price each must he sell the remaining chairs so as to gain 10% on the whole deal?

Solution:

C.P. of one chair = ₹175

C.P. of 40 chair = ₹175 × 40 = ₹7000

Question 16.

A shopkeeper sold two electronic gadgets for ₹44000 each. The shopkeeper made a loss of 12% on one and a profit of 10% on the other. Find his overall gain or loss.

Solution:

S.P. of first gadget = ₹44000

Loss = 12%

Now S.P. of both gadgets = ₹44000 × 2 = ₹88000

Their cost price = ₹50000 + ₹40000 = ₹90000

∴ Loss = C.P. – S.P. = ₹90000 – ₹88000 = ₹2000

Overall loss = ₹2000

Question 17.

The manufacturing price of a T.V. set is ₹12000. The company sold it to a dealer at 20% profit and the dealer sold it to a customer at 12·5% profit. Find the price which the customer has to pay.

Solution:

The manufacturing price of a T.V. set = ₹12000

S.P. for company = ₹ \(\left(1+\frac{20}{100}\right)\) × 12000

Question 18.

Find the cost price, when :

(i) selling Price = ₹450, loss = 10%

(ii) selling Price = ₹690, profit = 15%

Solution:

(i) Selling price = ₹450, loss =10%

we know that,

∴ C.P. = ₹5 × 100 = ₹500

(ii) Selling price = ₹690, Profit = 15%

We know that,

⇒ C.P. = ₹6 × 100 = ₹600

Question 19.

By selling an almirah for ₹3920, a shopkeeper would gain 12%. If it is sold for ₹4375, find his gain or loss, percentage.

Solution:

When Selling price of almirah = ₹3920

and Gain % = 12%

then C.P. =?

We know that,

Now when C.P. of almirah = ₹3500

and S.P. of almirah = ₹4375

gain = S.P. – C.P. = ₹4375 – ₹3500 = ₹875

Question 20.

By selling a bicycle at ₹1334, a shopkeeper would suffer a loss of 8%. At how much amount should he sell it to make a profit of \(12 \frac{1}{2}\)%?

Solution:

When selling price of bicycle = ₹1334

Loss % = 8%

C.P. = ?

We know that,

Selling price = (1 – loss%) of C.P.

Question 21.

By selling a tie for ₹252, a shopkeeper gains 5%. At what price should he sell the tie to gain 35% ?

Solution:

Selling price of tie = ₹252

gain% = 5%

C.P. = ?

We know that,

Selling price = (1 + Gain %) of C.P.

⇒ C.P. = ₹12 × 20 = ₹240

Now C.P. = ₹240

If shopkeeper wants a gain of 35%,

then Selling price = (1 + gain %) of C.P.

Question 22.

A shopkeeper sells a bag at a 12% profit. If he had sold it for ₹39 more, he would have made 18% profit. Find the cost price of the bag for the shopkeeper.

Solution:

First time gain = 12%

and second time gain = 18%

∴ Difference in gain % = 18 – 12 = 6%

Actual difference = ₹39

If gain is ₹6, then C.P. = ₹100

and if gain is ₹1, then C.P. = \(\frac{100}{6}\)

and if gain is ₹39. then C.P. = ₹ \(\frac{100 \times 39}{6}\) = ₹650

Question 23.

A shopkeeper sells a sweater at a loss of 5%. If he had sold it for ₹260 more, he would . have made a profit of 15%. Calculate the

purchase price of the sweater.

Solution:

Let the cost price of sweater = ₹ x

Loss = 5%

Hence the cost price of sweater = ₹1300

Question 24.

Janki sold her leather purse at 8% loss. If she had sold it for ₹ 150 more, she would have made 12% profit. Find the selling price of the purse.

Solution:

Let the selling price leather purse = ₹ x

Loss = 8%

Hence the selling price of leather purse = ₹690