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ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 19 Data Handling Ex 19.2

July 1, 2019 by Prasanna

ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 19 Data Handling Ex 19.2

Question 1.
The following data represents the different number of animals in a zoo. Prepare a pie chart for the given data.
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 19 Data Handling Ex 19.2 Q1.1
Solution:
Pie chart for the data is given below:
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 19 Data Handling Ex 19.2 Q1.2
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 19 Data Handling Ex 19.2 Q1.3

Question 2.
The following data represents the monthly expenditure of a family (in T) on various items. Draw a pie chart to represent this data.
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 19 Data Handling Ex 19.2 Q2.1
Solution:
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 19 Data Handling Ex 19.2 Q2.2
Pie chart representing the above given data is given:
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 19 Data Handling Ex 19.2 Q2.3

Question 3.
The following data represents the percentage distribution of the expenditure incurred in publishing a book.
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 19 Data Handling Ex 19.2 Q3.1
Draw a pie chart to represent this data.
Solution:
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 19 Data Handling Ex 19.2 Q3.2
Pie chart representing the above given data is given:
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 19 Data Handling Ex 19.2 Q3.3

Question 4.
The following data represents the number of students got admission in different streams of a college:
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 19 Data Handling Ex 19.2 Q4.1
Draw a pie chart to represent this data.
Solution:
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 19 Data Handling Ex 19.2 Q4.2
Pie chart representing the above given data is given below:
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 19 Data Handling Ex 19.2 Q4.3

Question 5.
The adjoining pie chart shows the expenditure of a country on various sports during year 2012. Study the pie chart carefully and answer the following questions:
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 19 Data Handling Ex 19.2 Q5.1
(i) What percent of total expenditure is spent on cricket?
(ii) How much percent more is spent on hockey than that on tennis?
(iii) If the total amount spent on sports in 2012 is ₹1,80,00,000, then find amount spent on Badminton,
(iv) If the total amount spent on sports in 2012 is ₹2,40,00,000 then find the amount spent on cricket and hockey together.
Solution:
From the given pie chart representing the expenditure
incurred on various sports during 2012.
(i) Expenditure on cricket = 90° = \(\frac{90}{360^{\circ}}\) × 100% = 25%
(ii) Expenditure on hockey = 75° = \(\frac{75}{360^{\circ}} \times 100 \%=\frac{125}{6} \%=20 \frac{5}{6} \%\)
∴ \(\frac{125}{6}-\frac{125}{9}=\frac{125}{18}=6.95 \%\) more
Expenditure on tennis = 50° = \(\frac{50}{360^{\circ}}\) × 100% = \(\frac{125}{9} \%\)% = 13.9%
(iii) Total amount spent on sports = ₹1,80,00,000
Then amount spent on Badminton = ₹ 1,80,00,000 × \(\frac{60}{360^{\circ}}\) = ₹30,00,000
(iv) If total amount spent on sports = 2,40,00,000,
then amount spent on cricket and hockey together
= 90° + 75° = 165° = \(\frac{165^{\circ}}{360^{\circ}}\) × 2,40,00,000 = 1,10,00,000

Question 6.
The adjoining pie chart shows the number of students enrolled in class VI to class X of a school.
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 19 Data Handling Ex 19.2 Q6.1
If 1440 students are enrolled from VI to X, then answer the following questions:
(i) How many students are enrolled in class VIII?
(ii) How many students are more in class IX than in class X?
(iii) What is the sum of students enrolled in VII and VIII?
(iv) Find the ratio of students enrolled in VI to students enrolled in X.
Solution:
The given pie chart is representing the enrolment of
students from class VI to class X in a school.
Total students were enrolled = 1440
(i) Enrolment of class VIII = \(\frac{85}{360^{\circ}}\) × 1440 = 340 students
(ii) Difference in X and IX class enrolement = 75° – 50 = 250°
\(\frac{25}{360^{\circ}}\) × 1440 = 100 students
(iii) Sum of students enrolled in VII and VIII classes
= 70° + 85° = 155° = \(\frac{155}{360^{\circ}}\) × 1440 = 620 students
Ratio between the students enrolled in VI to
students enrolled in X classes = 80° : 50° = 8 : 5

ML Aggarwal Class 8 Solutions for ICSE Maths

Filed Under: ICSE

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