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ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 14 Constructions of Quadrilaterals Ex 14.2

July 3, 2019 by Prasanna

ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 14 Constructions of Quadrilaterals Ex 14.2

Question 1.
Construct a parallelogram ABCD such that AB = 5 cm, BC = 3·2 cm and ∠B 120°.
Solution:
Steps of construction :
(i) Draw AB = 5 cm
(ii) At B, Construct angle = 120°
(iii) With B as centre and 3·2 cm as radius cut off ∠B at C.
(iv) With C as centre and AB as radius draw an arc.
(v) With A as centre and 3·2 cm as radius
draw an arc which meets the previous arc at D.
(vi) Join AD and CD.
Then ABCD is required parallelogram
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 14 Constructions of Quadrilaterals Ex 14.2 Q1.1

Question 2.
Construct a parallelogram ABCD such that AB = 4·8 cm, BC = 4 cm and diagonal BD = 5·4 cm.
Solution:
Steps of construction :
(i) Construct a triangle ABD.
(ii) With B as centre and 4 cm as radius draw an arc.
(iii) With Das centre and 4·8 cm as radius,
draw an arc which meets the previous arc at C.
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 14 Constructions of Quadrilaterals Ex 14.2 Q2.1
(iv) Join CD, BC and AC
(v) Then ABCD is the required parallelogram.

Question 3.
Construct a parallelogram ABCD such that BC = 4·5 cm, BD = 4 cm and AC = 5·6 cm.
Solution:
Steps of construction :
(i) Construct a ∆ BOC with BC = 4·5 cm,
BO = \(\frac{1}{2}\) × 4 = 2 cm
and OC = \(\frac{1}{2}\) AC = \(\frac{1}{2}\) × 5.6 = 2·8 cm
(∵ Diagonals of ||gm bisect each other)
(ii) Produce OC to A such that OC = OA
(iii) Produce BO to D such that OD = OB.
(iv) Join AD, then ABCD is the required parallelogram.
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 14 Constructions of Quadrilaterals Ex 14.2 Q3.1

Question 4.
Construct a parallelogram ABCD such that AC = 6 cm, BD = 4·6 cm and angle between them is 45°.
Solution:
Steps of construction :
(i) Draw AO = \(\frac{1}{2}\) AC = 3 cm and produce AO to C
such that OC = OA.
(ii) At O, construct ∠COP = 45°.
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 14 Constructions of Quadrilaterals Ex 14.2 Q4.1
(iii) From OP, cut OD = \(\frac{1}{2}\) BD = \(\frac{1}{2}\) × 4·6 cm = 2·3 cm.
(iv) Produce OD to OB such that OB = OD.
(v) Join AB, BC, CD and DA, then
ABCD is the required to parallelogram.

Question 5.
Construct a rectangle whose adjacent sides are 5·6 cm and 4 cm.
Solution:
Steps of construction :
(i) Draw AB = 5·6 cm.
(ii) At B, construct ∠ABP = 90°
(iii) From BP, cut off BC = 4 cm.
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 14 Constructions of Quadrilaterals Ex 14.2 Q5.1
(iv) With C as centre and radius = 5·6 cm draw an arc.
(v) With A as centre and radius = 4 cm,
draw an arc to meet the previous arc at D
(vi) Join AD and CD. Then ABCD is the required rectangle.

Question 6.
Construct a rectangle such that one side is 5 cm and one diagonal is 6·8 cm.
Solution:
Steps of construction :
(i) Draw AB = 5 cm.
(ii) At A, construct ∠BAP = 90°.
(iii) With B as centre and radius = 6·8 cm,
draw an arc to meet AP at D.
(iv) With A as centre and radius = 6·8 cm draw an arc.
(v) With D as centre and radius = 5 cm,
draw an arc to meet the previous arc at C.
(vi) Join BC and CD. Then ABCD is the required rectangle.
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 14 Constructions of Quadrilaterals Ex 14.2 Q6.1

Question 7.
Construct a rectangle ABCD such that AB = 4 cm and ∠BAC = 60°.
Solution:
Steps of construction :
(i) Draw AB = 4 cm.
(ii) At B, draw ∠ABP = 90°
(iii) At A, construct ∠BAQ = 30°. Let AQ meet BPat D
(iv) With D as centre and radius = 4 cm draw an arc.
(v) With A as centre and radius = BD,
draw an arc to meet the previous arc at C.
(vi) Join AC and CD. Then ABCD is the required rectangle.
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 14 Constructions of Quadrilaterals Ex 14.2 Q7.1

Question 8.
Construct a rectangle such that one diagonal is 6-6 cm and angle between two diagonals is 120°.
Solution:
Steps of construction :
(i) Draw AO = \(\frac{1}{2}\) AC = (\(\frac{1}{2}\) × 6·6) cm and produce AO to C
such that OC = OA = 3·3 cm
(ii) At O, construct ∠COB = 120°
(iii) From OB, cut off OB = \(\frac{1}{2}\) AC = 3·3 cm.
(iv) Produce BO to D such that OB = OD = 3·3 cm.
(v) Join AB, BC, CD and DA.
Then ABCD is the required rectangle.
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 14 Constructions of Quadrilaterals Ex 14.2 Q8.1

Question 9.
Construct a rhombus whose one side is 5 cm and one angle is 45°
Solution:
Steps of construction :
(i) Draw AB = 5 cm.
(ii) At A, construct ∠BAP = 45°.
(iii) From AP, cut off AD = 5 cm.
(iv) With B as centre and radius = 5 cm, draw an arc.
(v) With D as centre and radius = 5 cm,
draw an arc to meet the previous arc at C.
(vi) Join BC and CD. Then ABCD is the required rhombus.
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 14 Constructions of Quadrilaterals Ex 14.2 Q9.1

Question 10.
Construct a rhombus whose one side is 4·5 cm and one diagonal is 5 cm.
Solution:
Steps of construction :
(i) Draw AB = 4·5 cm.
(ii) With A as centre and radius = 4·5 cm, draw an arc.
(iii) With B as centre and radius = 5 cm,
draw an arc to meet the previous arc at D.
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 14 Constructions of Quadrilaterals Ex 14.2 Q10.1
(iv) With B as centre and radius = 4·5 cm, draw an arc.
(v) With D as centre and radius = 4·5 cm,
draw an arc to meet the previous arc at C.
(vi) Join AD, BC and CD. Then ABCD is the required rhombus.

Question 11.
Construct a rhombus whose diagonals are 6·8 cm and 5·2 cm.
Solution:
Steps of construction :
(i) Draw AC = 6·8 cm.
(ii) Draw 1 bisector PQ of AC to meet it at O.
(iii) From POQ, cut off OB and OD such that
OB = OD = \(\frac{1}{2}\) BD = \(\frac{1}{2}\) (5·2) cm = 2·6 cm.
(iv) Join AB, BC, CD and DA. Then ABCD is the required rhombus.
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 14 Constructions of Quadrilaterals Ex 14.2 Q11.1

Question 12.
Construct a square whose one side is 4·3 cm.
Solution:
Steps of construction :
(i) Draw BC = 4·3 cm.
(ii) At B, construct ∠CBP = 90°
(iii) From BP, cut off BA = 4·3 cm.
(iv) With C as centre and radius = 4·3 cm, draw an arc.
(v) With A as centre and radius = 4·3 cm,
draw an arc to meet the previous arc at D.
(vi) Join AD and CD. Then ABCD is the required square.
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 14 Constructions of Quadrilaterals Ex 14.2 Q12.1

Question 13.
Construct a square whose one diagonal is 6·2 cm.
Solution:
Steps of construction :
(i) Draw AC = 6·2 cm.
(ii) Draw ⊥ bisector PQ of AC to meet it at O.
(iii) From POQ, cut off OB = OD = \(\frac{1}{2}\) AC = 3·1 cm.
(iv) Join AB, BC, CD and DA.
Then ABCD is the required square.
ML Aggarwal Class 8 Solutions for ICSE Maths Chapter 14 Constructions of Quadrilaterals Ex 14.2 Q13.1

ML Aggarwal Class 8 Solutions for ICSE Maths

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